Rope force physics

[austere barn]

The weight of the traffic light is 218N. Calculate the force applied on both ropes. Is 181N on both ropes correct?

[golden crypt]

181.67 N
yepp

[austere barn]

thank you

[frank dirge]

@austere barn has given 1 rep to @golden crypt

[austere barn]

wait

i got 181.1188

109/sin(37) right?

[golden crypt]

whats sin (37)?

[austere barn]

.602

[golden crypt]

well yeah so i remember the aprox value of it which is sin (37) = 3/5

[austere barn]

oh

[stray magnet]

Suppose the given angles are α. Then, by Newton's second law:
0 = mg - |T|sin(α) - |T|sin(α)
So:
|T| = mg/(2sin(α))
Since |P| = mg:
|T| = |P|/(2sin(α))
And that evaluates to about 181 N, so yes, correct.

[austere barn]

thats why

[golden crypt]

so maybe cause of that

[austere barn]

yup

[golden crypt]

yeh

[austere barn]

given that W = 60N, is the force on the diagonal rope 84.9N? i assume it is.

Follow up question: How much force must F1 and F2 apply for the object to stay stationary?

[stray magnet]

Ah... Sorry, don't know if I can do this correctly.

[austere barn]

seems tough

what makes it difficult for me is the positioning of F1, i dont even know what that would be like in real life

[stray magnet]

Well, you can imagine that as pinching that point of the rope with your fingers and tugging it to the left.

[golden crypt]

i think 60 N

[austere barn]

i got 60N too

[stray magnet]

Can you show how you did it?

[austere barn]

what about the follow up question?

[austere barn]

he is not talking about the horizontal forces, he is talking about the diagonal force on the rope

[golden crypt]

uhm well

well cause its 45 degrees so

[austere barn]

adj = 60N/tan45

[golden crypt]

the fig looks a bit different but uhm its the same ig
we can assume it like this
and then cause its 45 degrees F has to be equal to W

unprofesional way but whatever

[stray magnet]

Oh, wait. I think I know what you mean.
Suppose that 45 degree angle is α. Then:
0 = |P| - |T|sin(α)
So:
|T| = |P|/sin(α)
Then yes, |T| is about 84.9 N.

[austere barn]

yup

T and P confuse me lmao

[golden crypt]

its for that only

[stray magnet]

T is the tension force, P is weight.

[austere barn]

oh

[austere barn]

so you are saying both F1 and F2 are 60N?

that wouldnt make sense

[stray magnet]

Let me try.

[austere barn]

what i do agree on is the vertical component and horizontal component of Fd (diagonal tension force) being 60N

and probbably pointing to the left too