What have you tried?
#Integrals
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round lily
What have you tried?
I'm not sure where to start
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I'm not sure where to start
...probably find m and M.
round lily
...probably find `m` and `M`.
M = 25 and m=5?
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M = 25 and m=5?
How did you get that?
round lily
How did you get that?
I graphed it on desmos
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I graphed it on desmos
...okay, and how did you know what values on the graph would be m and M?
round lily
...okay, and how did you know what values on the graph would be `m` and `M`?
it said the absolute min was m
round lily
...okay, and how did you know what values on the graph would be `m` and `M`?
thats completely wrong isnt it?
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thats completely wrong isnt it?
No, it's right, it's just... like, you graphed it in Desmos. That's not really an algebraic method of finding the solution.
Like, if this was on a test, would you be allowed to use Desmos?
round lily
I believe so but ill try not to use desmos next time
round lily
No, it's right, it's just... like, you graphed it in Desmos. That's not really a...
whats the next step?
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whats the next step?
The step after finding m and M?
round lily
yea
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It's... plugging them into the given inequality...
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It's... plugging them into the given inequality...
m(3) would be 15 and M(3) is 75?
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m(3) would be 15 and M(3) is 75?
...okay...
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