#Limits
1 messages · Page 1 of 1 (latest)
thank you for looking into this, I'm in a pinch since I have a job in a few hours to attend.
@gilded abyss has given 1 rep to @gusty halo
I actually did
and
wait is it sqrt 2y+22-4 or in fact sqrt (2y +22 )-4
cause I did the former
If I read it as the latter I think I can find the answer

OMG I just realized I Read the sqrt wrong
wait
Yeah I believe I have read it wrong thank you so much for clearing this out. as for the thing you wish to let me know what is it?
did you solve it?
let me try
@gusty halo ooof I cant I'm getting confused
may I know how you will solve this one?
im trying as well xD i thought it was eas
ikr, this is the only number I
I
I'm stuck with

ok wait let me re write it
get this
after multiplying conjugate
then you break out 2 fromtop
and divide away x + 3
then you get
1
then input x = -3
and then its solved
should be 1 /4
minus 16?
-4x-4 is positive 16 right?
ah may I know why is it +4 instead of -4?
The complex conjugate has the same real part as z and the imaginary part with the opposite sign. That means, if z = a + ib is a complex number, then z∗ = a − ib will be its conjugate. In the polar form of a complex number, the conjugate of re^iθ is given by re^−iθ.
I see so I should write them off as the opposite of the part where there isnt any variable
is that how you conjugate?
ok if youre confused about conjugate just skip it
you dont even need any knowledge about it
just the rule
(a+b)(a-b) = a^2 -b^2
I'll look into this on a following time
with just this I can solve it
I'll just do 2(x+3) then I'm all set
cancel them out
if you multiply both top and bottom with something
lets say 5
its same as multiplying by 1
because they both cancel each other out
yeah it cancels out
so its mathematically correct
the answer of the equation is 2/8
which is 1/4
Thank you so much for clearing things out
how do I rep you again?
already did
Thank you again so much for helping me.
there are a few different conjugates, this is the complex conjugate
but like
algebraic one is
x + y -> x - y
I see noted, I'll definitely review on that one.