#new topic in math for me
41 messages · Page 1 of 1 (latest)
You can solve it by writing (X-5)^2 * (X-5)^2
Therefore, (x^2+25-10x)(x^2+25-10x)
If that exponent is a 4. And that's still not really a solution.
That looks like a 4 to me, so x∈C
...I mean, isn't x always in C?
uh, in this case, yea? or wdym
...I mean how R is a subset of C.
x belongs to complex numbers; thus, no solution. How I was taught, is it not?
...what? Of course there's a solution. There's a complex solution.
Do you really think he's looking for that though
It's safe to assume he's solving for x∈R
Yes?
How is that safe?
"."
...what?
He's probably confused about how to solve it for ∈R, which is why he said "." as it's unsolvable
Idk why you think he's trying to find the complex solution; when the given variable is "x", it's def more than safe to assume not solutions for x belonging to real numbers.
You're reading a hell of a lot into ".".
uh ok? and?
And maybe you should stop assuming things based on literally a single character and just wait for OP to give us some actual information?
I don't why know you're overthinking it that much, if you were to give anyone that equation the first thought is x∈C, no solution. Not finding the complex solution itself.
Idk why you think it's safe to assume the minority of thoughts
There is a solution.
I'm literally not assuming anything. I'm waiting for OP to tell me.
^
^
I think it's a possibility.
Well let's wait then, I'm pretty certain he's solving for x∈R and not the ∈C solution
even mathematical calculator uses that as the first assumpation
Which is a random assumption you're making for no reason.
idk why u think its "unsafe to assume that"
and you're assuming he is solving for ∈C
common assumptions is far more accurate and should be said than a minority
I SAID I THINK IT'S A POSSIBILITY. YOU'LL NOTE THAT I HAVEN'T ACTUALLY GIVEN THEM ANY INSTRUCTIONS BASED ON THAT.
You don't try to solve a problem before you know what the problem is.
sounds like an assumption to me, but ok, sure