Please help

[lunar nacelle]

A carpenter wants to climb a beam to build a frame on top of a hill. He must
pull the beam over the entire distance AB and on a slope inclined at an angle of 15° with respect to
the horizontal.
AB is 30 meters long and the mass of the beam is 60 kg. During the ascent, the beam is subjected to
several forces including its weight ⃗ . ( ⃗ forms a 90° angle with the horizontal)
Calculate the work of the weight ⃗ of the beam on the displacement AB.
I also put the photo for you, thank you!

[main arrow]

Let r be the vector of displacement and F(grav) be the vector of gravitational force.
Then the work is the dot product:
W(F(grav)) = F(grav)·r
Now, let's write each vector's coordinates. We will put the axes as usual: x-axis to the right, y-axis upwards.
F(grav) = {0, -mg}
r = |r|{cos(α}, sin(α)}
So:
W(F(grav)) = -mg|r|sin(α)
In our case m = 60 kg, |r| = 30 m, α = 15°.

[lunar nacelle]

the result ?

[main arrow]

Well, I'm sure you can just substitute the values into the formula.

[lunar nacelle]

well im not that gppd in english so it was a little difficult for me to understand everything xd

[main arrow]

Which part?

[lunar nacelle]

x-axis to the right, y-axis upwards.
F(grav) = {0, -mg}
r = |r|{cos(α}, sin(α)}
So:
W(F(grav)) = -mg|r|sin(α)
In our case m = 60 kg, |r| = 30 m, α = 15°.