probability-can somebody help me out here

[lavish spindle]

1st one

tell me if you don't understand my handwriting

[shrewd scroll]

17 - 5 = 12
since the number on one dice is already given, the total possibilities becomes 6³ = 216
below are the possibilities that sums up to 17 (one of them being 5):
5 1 5 6 -> 4!/2! = 12 ways
5 2 4 6 -> 4! = 24 ways
5 3 4 5 -> 4!/2! = 12 ways
5 4 4 4 -> 4!/3! = 4 ways
5 2 5 5 -> 4!/3! = 4 ways
5 3 3 6 -> 4!/2! = 12 ways
-------- +
68 ways
hence the probability is 68/216 = 17/54

[lavish spindle]

hey can you tell me if there is any sort of way for finding combination possible if you have been given the sum like above =12

btw thanks you saved me

[thorny tiger]

dice is already plural, you can't say dices

[shrewd scroll]

I think you have to do it manually

[shrewd scroll]

urwelcome

[lavish spindle]

dude can I find P(die showed 5) by finding those with no 5 and minus it by sample space
Total possible outcomes =P(S)=6⁴=1296
Like P(A1) =5⁴=625 [only 5 outcomes now (1,2,3,4,6)]
P(A)= P(S)-P(A1)= 1296 -625=671[those with 5]

[lavish spindle]

please tell if I'm doing some wrong concept