title...arcsin(x) is sin^-1(x) or inverse sin function for americans
#How to take anti-derivative in pic?
polar anvil
hybrid trench
title...arcsin(x) is sin^-1(x) or inverse sin function for americans
First, since dx/√(1 - x^2) = d(arcsin(x)):
x arcsin(x)dx/√(1 - x^2) = x arcsin(x)d(arcsin(x)) = sin(arcsin(x))arcsin(x)d(arcsin(x))
So, if you take u = arcsin(x), the expression becomes:
sin(u)udu
And this is tackled by integration by parts.
polar anvil
First, since dx/√(1 - x^2) = d(arcsin(x)):
x arcsin(x)dx/√(1 - x^2) = x arcsin(x...
can you explain without the u-substitution, please? they dont really teach us that so I don't understand very well
hybrid trench
can you explain without the u-substitution, please? they dont really teach us th...
Wait, really? Huh...
There aren't any methods simpler than u-substitution, though.