#complex analysis question

126 messages · Page 1 of 1 (latest)

dim kraken
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i got this question i cant seem to figure how to work out after knowing the mapping

tribal basin
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parameterise for y=x+1 and get y(t)=t+1, x(t)=t t∈ℝ
z=x+iy
(x+iy+1)/(x+iy-1)
(t+i(t+1)+1)/(t+i(t+1)-1)
rationalise the denominator
-(t+1+i+it)(it+i+1-x)/(2t²+2)
((2t²+2t)/(2t²+2))-i((2+2t)/(2t²+2))
now I'll graph this and post it here:
which is (x-0.5)²+(y+0.5)²=0.5
or |z-0.5+0.5i|=√0.5

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@dim kraken

late mapleBOT
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@dim kraken has given 1 rep to @tribal basin

tribal basin
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@dim kraken I made a minor error in my modulus form, the radius is not 0.5², it's √0.5

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if you don't mind me asking, what exactly were you struggling with?

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I have a habit of just giving answers and not really helping the surrounding understanding

dim kraken
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i can show you the answer my lecturer gave if that would help

tribal basin
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ok

dim kraken
tribal basin
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ok that makes sense, he just solved it with complex coordinates rather than parametrics

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if you find parametrics easier then do those

dim kraken
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like i dont understand how he got the answer for the first translation

tribal basin
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parametrics and complex coordinates are very similar

dim kraken
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i know its -1 but then het got (-1+i)+ sqrt(2)e etc

tribal basin
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(f(t),g(t))→f(t)+ig(t)

dim kraken
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and i didnt get it T_T

dim kraken
tribal basin
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so z~(t)=(t-1)+i(t+1) because it was translated by -1, right?
then you expand the brackets and get z~(t)=t-1+ti+i→(-1+i)+t+ti where t+ti=t(1+i)→(e^(iπ/4))√2
so now you have (-1+i)+√2(e^iπ/4)t

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-1 on the real part

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@dim kraken

dim kraken
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i then got confused when he did the magnification

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where we did w=2w

tribal basin
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notice on the step before when the 2(u²+v²)+u+v is converted into a circle equation

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where did the 2 go?

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because it's equal to 0 the 2 was divided out

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which makes it necessary to do the magnification on a later step

dim kraken
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but wouldnt dividing w by 2 give you 1/4 at the end and not 1/2

tribal basin
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no, it's squared so it's ⅛×4

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⅛×2²

dim kraken
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huh

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how is it 4

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arent u dividing it by 2 once

tribal basin
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(u/2 + ¼)² when you get u to be just u you get (u+½)² which because that multiplication in the brackets is 2, it is 2 everywhere within the bracket. but it's effect is 2² so 4

dim kraken
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OHHH wait so u only divide the u and v components for the magnifcation rather than the whole thing?

tribal basin
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pretty much

dim kraken
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bruh

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i also have another question

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xddd

tribal basin
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sure

dim kraken
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so ive worked out the decomposition again

tribal basin
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yeah

dim kraken
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but part b has me lost

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ill send the answer through as well

tribal basin
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ok

dim kraken
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OMG WAIT

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i see why its y=3x now

tribal basin
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x(t)=t y(t)=3t-⅓

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yeah

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lmao

dim kraken
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but idk why he did the magnification first rather than the translation

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i thought u was supposed to do it in order?

tribal basin
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doesn't really matter which order as long as you account for it, but I agree he should have done it in order for ease of understanding

dim kraken
tribal basin
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sure, I won't always be able to answer them in a timely manner though

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so might be a better idea to post them here

dim kraken
late mapleBOT
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@dim kraken has given 1 rep to @tribal basin

tribal basin
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no problem

dim kraken
tribal basin
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+1

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I can't read

dim kraken
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but why

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wasnt the translation supposed to be +3

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this module is gonna be the death of me i swear

tribal basin
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makes it easier to deal with, constants won't change whether it's a straight line or a circle

tribal basin
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then you have x(t)=t and y(t)=3t

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so much better

dim kraken
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but why wasnt the magnification eq y=9x-1 instead of y=3x-1

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because isnt magnification supposed to be for the whole eq

tribal basin
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because it's applied only to the constant

dim kraken
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all the time?

tribal basin
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with analysing these functions and just finding whether it's a straight line or a circle or whatever you can almost do whatever you want with a constant

dim kraken
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so he just applied the magnification to the constant alone and left the t component alone?

tribal basin
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pretty much

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he could just apply the translation ⅓

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idk why he didn't

dim kraken
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would it be wrong for me to continue on with 9t or

tribal basin
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well, it would get you the same answer in terms of straight line or circle, but not the desired answer

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treat it as though he just did the translation ⅓

dim kraken
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why 1/3 😭 this is so confusing

tribal basin
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y=3x-⅓

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y=3x if you translate it ⅓ to the right

dim kraken
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yeah

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so do i even need to use the decomposition we did in part a at this point

tribal basin
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not for this method of solution, your lecturer is a very strange man with his solutions

dim kraken
tribal basin
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same overall answer yes

dim kraken
dim kraken
# tribal basin same overall answer yes

NVM ITS SO LONG but from my understanding, what your saying is when it comes to finding out whether its a line or circle the value of the translation is insignificant and same with the magnification of it?

tribal basin
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yep

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like no scalar multiple of 2x will make it 2x²

dim kraken
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okay yeah i get that

dim kraken
tribal basin
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lmao

dim kraken
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wouldnt it be -3t-it

tribal basin
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no?

dim kraken
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whaaaa

tribal basin
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what's the general form for a complex number

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x+iy

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what's the parametric for y and x

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t=x(t) 3t=y(t)

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t-3it

dim kraken
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ohhhhhh yeah i did it the wrong way oops

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how would you apply the rotation ?

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@tribal basin

tribal basin
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not entirely sure without seeing what you have and how you got it

dim kraken
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i got the same w(t) =t-3it as him and in part a it rotates by -pi/2

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but idk how to apply that to the w(t)

tribal basin
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rotation by -pi/2 means you find the line orthogonal with the same constants

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well

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yeah pretty much, negative 90° and 90° with a line is the same

dim kraken
tribal basin
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no problem