factorisation
#factorisation
velvet sage
formal bough
factorisation
For 1/2: a^2 - b^2 = (a+b)(a-b)
For 3/4: Given Quadratic x^2 + bx + c, find two numbers d and e such that d•e = c and d+e = b, then the quadratic equals (x+d)(x+e)
Long answers:
- Given Quadratic ax^2 + bx + c, find two numbers d and e that sum to b and multiply to ac (so add to 3a, multiply to 4a^2)
Then Quadratic equals (ax^2 + dx) + (ex + c)
Use LCF and distribute property
2/3) (a•b)/(c•d) = a/c • b/d
velvet sage
thank you
can u also help me with 1 more thing
i cant do thes
its form exponents
@formal bough
formal bough
a^x = 1(a^(-x))
For 6/7/8: a^(b•c) = a^b • a^c
9/10 uses scientific notation, where a number is shown as a•10^b, where 1 <= a < 10 and b is some integer
velvet sage
oh
thank
you
what is the answer of 8th question
i dont understand
the 8th one
velvet sage
9/10 uses scientific notation, where a number is shown as a•10^b, where 1 <= a <...
8th one
i dont udnerstand it
formal bough
-1^(2•k), where k is some integer
= (-1^2)^k
What’s -1 squared
velvet sage
1