#anyone plss help
18 messages · Page 1 of 1 (latest)
,w sqrt(x) + sqrt(x + 1) + sqrt(x + 2) = 2
@lone sierra easy and simple 
Damn this is some cool bot right here
So this question have no solution
@tardy dirge
Yes
You can also say \ $x \geqslant 0$, hence \ $\sqrt{x + 1} \geqslant 1 \ \sqrt{x + 2} \geqslant \sqrt{2} \approx 1.4 \ \ \sqrt{x} + \sqrt{x + 1} + \sqrt{x + 2} \geqslant 2.4 > 2$
@lone sierra
Mizere
@lone sierra Please don't repost the same question in more than one help channel.