Equation of tangent line | Mathematics | Page 1

short lodge Nov 1, 2022, 5:31 PM

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So I derived that function and got 2x/2root(x^2+5), then f'(2) gives me 2/3 but idk what to do next.

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this is what im supposed to get but idk where y-3 and x-2 came from

midnight nymph Nov 1, 2022, 7:17 PM

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You want the equation of a line, right? So what does the derivative give you?

short lodge Nov 1, 2022, 7:23 PM

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derivative of root(x^2+5)?

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its 1/2 * root(f(x)) * f'(x)

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so 2x/xroot(x^2+5)

midnight nymph Nov 1, 2022, 7:50 PM

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...no, what does the derivative tell you about the line?

short lodge Nov 1, 2022, 7:56 PM

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the slope?

midnight nymph Nov 1, 2022, 9:58 PM

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Right. So what else do you need to know about the line in order to be able to represent it?

real phoenix Nov 1, 2022, 11:14 PM

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This isn’t uni

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Your using the chain rule to differentiate

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Then evaluate at 2 it looks like

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And find the y coordinate through the x in the question

#Equation of tangent line