#Trig
1 messages · Page 1 of 1 (latest)
@runic estuary
Sorry, I'm not quite comfortable with friending people I don't know in person
its ok
so the thing im supposed to do now is find -3pi/4
and so that should be a 45 45 90 triangle when you draw the reference angle and connect it all and do make all the triangle math happen
That'll be at 5pi/4
yeh i know that but why do these all do different things
GRAH
IM SO CONFUSED
THE NUMBERS ARENT SUPPOSED TO LIE
Here the hypotenuse is sqrt(2), not one like the radius of the circle
It's fine, I thought the same thing at one point
wait a minute
so
sqrt2/2 isnt the sin or cos its just the length of that side right?
sin(45 degrees)=sqrt(2)/2, and cos(45 degrees)=sqrt(2)/2, which corresponds to the side lengths
Cos(x) will correlate with the horizontal line, while sin(x) will correlate with the vertical line
so if sin is opposite over hypotenuse then why isn’t it sqrt(2)/1
idk if that makes sensr
sense
Orthodox
That didn't work
oof
$\frac{\frac{\sqrt(2)}{2}}{1}$
Orthodox
Which is still $\frac{\sqrt(2)}{2}$
oh wait
Orthodox
I'll try and draw something out quickly
so opposite is the Y line and adjacent is the X line?
Nice, being able to figure something out on your own is always a nice feeling
it is
But of course never be afraid to ask questions
i feel so bad when it comes to math cuz i went to tutoring for like 8 months last year snd and learned like nothing
2 times a week too
Ah, tutoring sometimes isn't the best method for everyone
Probably wouldn't work well for me, personally speaking
wait so
for cosecant i got 1/sqrt(2)/2 and the same for secant
is thst right in this problem?
That should be, although it can be simplified
how do i simplify it
If you have $\frac{1}{\frac{\sqrt(2)}{2}}$
Orthodox
The very bottom number, the 2, can be taken up to the top
ahhhh i was about to do that ong
oh but then what do i do with the exponent
does it cancel out the radical and make it 1/2
oh i should also say the radical is -2
Here you'd have $\frac{2}{\sqrt(2)}$
Orthodox
For sin(-3pi/4) yes
That's a good question, I'd never really thought about it
I'll try to explain it with an example
i am why proofs were invented ðŸ˜
Let's say we have $\frac{1}{\frac{2}{3}}$
Orthodox
Wait that explanation won't work
Hmm
So, division is the same as multiplying by 1/x
So y/x = y*1/x
Wait no that doesn't work either
Okay, back to this
oof this seems a lot harder to explain thsn to use
Here you'll be doing 2/3 first, because the operation you're performing is 1/(2/3)
mhm
Division finds how many times the bottom goes into the top
Wait ignore this, this isn't necessary
So we have this
And we're finding how many times 2/3 goes into 1
yeh
Since a smaller number will fit in more times, then by dividing 2 by 3 will allow it to fit into 1 more times
So the being in the bottom is allowing for the final answer to be larger
So just taking the three to the top will allow the equation to produce the same larger number
Honestly I explained that so poorly, I barely understand what I said
If you got it though that's good
Yeah
so its the same with fractions and instead of doing all the silly math to get the same thing with more work youd just take the bottom and put it at the top
but your not taking the bottom and multiplying it by the top right?
You would be taking the bottom and multiplying it by the top
So $\frac{2}{\frac{4}{3}}$ would be $\frac{2*3}{4}$
Orthodox
that is so helpful
another thing
if i have 2*sqrt(3)/2 the 2’s cancel out and the remainder is sqrt(3) right?
Yep
Well, technically not remainder, just solution, but that's not really too important
Just definition thing
wth i got the right answer just now but im confused cuz i got it wrong first and thrn i guessed
What was it?
so for cot of 13pi/6 i got 2/sqrt(3)/2
and then i did 4/sqrt(3) but it was wrong so i swapped it to sqrt(3) cuz thsts what i got for tangent and it was right
then i just did 1/sqrt(3) because cot is the reciprocal of tan
agh nvm i know why
i totally screwed up
Ohh
so it wouldve been sqrt(3) but i just did everything wrong