#Determining if a series cvg or div

49 messages · Page 1 of 1 (latest)

sleek glen
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I'm lost on what to do here. We're told to use the Integral test but i'm not sure how to start. It seems, just from me looking at it, that it'd cvg to 0.

severe dagger
sleek glen
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yep

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I guess the questions comes down to doing the integral

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now that I've sat here for a second

severe dagger
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So... what's the integral, then?

sleek glen
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I do not know

severe dagger
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You just said you knew how to do the integral test.

sleek glen
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I know how to do the integral test

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I do not know how to do the integral

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oh

severe dagger
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...what is the integral that you don't know how to do?

sleek glen
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n*tan(1/n)

severe dagger
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That's not an integral.

sleek glen
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hmm

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i'm confused

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how is that not an integral

severe dagger
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...because... it's just an expression... is x + 1 an integral?

sleek glen
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idk how to type the integral symbol

severe dagger
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Just say int. It's what I do.

sleek glen
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oh wait

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don't pay attention to that

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There's the integral I do not know how to do

severe dagger
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Well, you have two problems.

sleek glen
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ok

severe dagger
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One, why is your top bound b?

sleek glen
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I replaced the inf with b, at the end of the integral I plug in b

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which ig does end up being inf, but it's how my teacher does it

severe dagger
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...you plug in b...?

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Look, just... write infinity. It's a standard notation.

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Second problem. Technically the antiderivative of what's written would just be nx tan(1/n).

sleek glen
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This is what we do actually, sorry

severe dagger
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...okay, whatever.

sleek glen
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lmao brother

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chill

severe dagger
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Will you just address the second problem?

sleek glen
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ok

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so if the antiderv of the what's written is nx tan(1/n)

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Is this what I do?

severe dagger
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No.

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I was pointing out a mistake in your notation.

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Because what's n there?

sleek glen
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ah

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instead of dx it'd be dn?

severe dagger
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Or, more traditionally, replace n with x.