#find recursive for when n is positive
1 messages · Page 1 of 1 (latest)
f(0) = 1
f(1) = f(1 - 1) - 1 = 0
f(2) = f(2 - 1) - 1 = -1
f(3) = f(3 - 1) - 1 = -2
...
from the pattern above we can conclude that
f(n) = -(n - 1)
1 messages · Page 1 of 1 (latest)
I would like general steps on how to approach this type of problem
f(0) = 1
f(1) = f(1 - 1) - 1 = 0
f(2) = f(2 - 1) - 1 = -1
f(3) = f(3 - 1) - 1 = -2
...
from the pattern above we can conclude that
f(n) = -(n - 1)