#Is this right or no
50 messages · Page 1 of 1 (latest)
Sooo, f^-1(f(x)) = f^1(x) ?
No. The rule of inverses is that f^-1(f(x)) = f(f^-1(x)) = x for all values x where both f(x) and f^-1(x) are defined
I don't get that at all but #2 should be this then?:
f(f^-1(x)) = (3√x-7)+7^3
When you say f^(-1)(f(x)), what you're doing is taking f^(-1)(x) and putting whatever f(x) is in the place of the x in f^(-1)(x).
That's what I did right? Or did I get #2 and #3 mixed up??
No, that's not what you did. At all. You did f(x) * f^(-1)(x).
Right right I meant in my Discord message
Still no. That's just cbrt(x) - 336.
so if f(x) is (x+7)^3
then f(f^-1(x)) is just (x+7)^3, but with the inverse of f(x), which is (3√x-7), put in place of x, so it would look like (3√x-7)+7^3 or am I just not getting it
(3root(x) - 7** +7**)^3
The plus 7 is inside the parathenses
Yeah sorry I didn't know if there was a symbol or some way to word 3root(x) that's what I meant by 3√x
Yea I can’t even do that root symbol on mobile
Oh I just looked it up and copy pasted lol
That's why I typed cbrt(x).
so then f^-1(f(x)) = (3root(7^3)-7) ?
That went over my head, I didn't know that's what cbrt meant
"cube root".
Ohh ok
...there's no x. That's just a constant.
Parentheses.
...no.
this is so annoying
I agree.
How is it wrong though like I physically don't get it
(x + 7^3) = x + 343
(x + 7)^3 = x^3 + 21x^2 + 147x + 343```
Oh so it was just a problem of where I put the ^3
I see
is #2 or #3 wrong or are they both wrong
...which one has cbrt(x - 7) in it?
so the cute root shouldn't be that long it should only go over the x then
I just realized I put 2 ( in #3
The cute root
FINALKLY
Yes Zac
I slayed
Yes Zac