#DESPERATE HELP PLEASE SPAM PING ME
533 messages · Page 1 of 1 (latest)
OMG okay so like
I guess this is logo of google Adsense
maybe idk..
so uhm the blue shape is like
here i
put it on another thread i have the stuff
Total area....or whatever info you have pls....
im trying to figure out the area 😭 there was a hand written version
Outside Yellow Line is 11cm
Inside Yellow line is 6.3cm
Outside Blue Line is 11.5cm
Inside Blue line is 6.3cm
The Green circle is 8.64cm with a radius of 2.75
The Blue stick also has like
and so the area of the green shape is
OHhhhhh
17.27875959cm2
Ok
im trying to figure out yellow's area
Wait
i just need to know like
the theory or
formula
to figure out its area
i can figure out the numbers then sorta if i have that
OKAY WAIT
HERE I HAVE MORE INFO
What is ur grade....
9..
A sum is not supposed to be so calculative.....i am grade 8
what
im from australia
C1 = Semi Circle Green – 5.5cm in diameter, 2.75cm in radius. To figure out circumference.
c=2πr . c=2 x π x 2.75cm =17.28cm ÷ 2 = 8.64cm
C2 = Semi Circle Blue
c=2πr . c=2 x π x 2.75cm =17.28cm ÷ 2 = 8.64cm
C3 = Quarter Circle Blue
θ/360 x 2πr d=144/360 x 2 x π x 2=6.911
Y1 = Outside Yellow Line = 11cm
Y2 = Inside Yellow Line = 6.3cm
B1 = Outside Blue Line = 11.5cm
B2 = Inside Blue Line = 6.3cm
AND...
......
The yellow part is just a rectangle
its not though..
They don't overlap?
nope
Without a semicircle and a triangle
theyre all seperate
Bruh when do you have to submit...
oh it was due 3 days ago
but i had atechnical issue
so im gonna show him this mroning around
idk
I mean your school timing
9 hours
Ooooo
@mellow lark is this like impossible
uhm the top of blue is a quarter circle
the green is a full circle
and on the bottom of blue is a semicircle
the quarter circle has a is 144/360 angle or theta IDK
help
okay uhm but i figured out
Yes?
C1 = Semi Circle Green – 5.5cm in diameter, 2.75cm in radius. To figure out circumference.
c=2πr . c=2 x π x 2.75cm =17.28cm ÷ 2 = 8.64cm
C2 = Semi Circle Blue
c=2πr . c=2 x π x 2.75cm =17.28cm ÷ 2 = 8.64cm
C3 = Quarter Circle Blue
θ/360 x 2πr d=144/360 x 2 x π x 2=6.911
Y1 = Outside Yellow Line = 11cm
Y2 = Inside Yellow Line = 6.3cm
B1 = Outside Blue Line = 11.5cm
B2 = Inside Blue Line = 6.3cm
11cm + 6.3cm + 11.5cm + 6.3cm + 6.911cm + 8.64cm + 8.64cm = 58.791 perimeter
this much!
Perimeter is not needed unfortunately.
oh..
what do u need
i can help with it
if i can figure out
its total area i can subtract
the blue and green to find yellow
but i need to find blue first
which seems easier
okay wait here i have a thingy
40.92cm2 estimated...
What is the angle of the sector?
I think this is good to go....
They gave you this?
its 144/360
OH
uhm
hold on..
im
LETS NOT SAY QUARTER
ITS NOT A QUARTER
ITS THE SHAPE OF IT
40.92 cm2 or die
How do you know?
Yellow part is 40.92
My work is a bit lot messy
Paint??????!!!!
Just a big tough rough work please
So as mj gave....
I can solve it if I know the angle of the sector.
Oooooooo9oooooooooooooooooooo
Jhhhgyffhhhhgyhh
Jhhhgyffhhhhgyhhhgg
Hhg
Gg
Ggb
Sorry i spammed....
and
the lines on blue are the diamater of the semi circles if u see it that way too
i put two lines showing
the angle of the sector
and if it was a
semi circle
it would be 5.5cm
How do you know?
Same....
Were you supposed to measure it?
Concept is the same....
Just making sure.
No neeed of using full decimals....
Just use estimates....
Class 9 starting bro.
You will be mercied
yea
starting? im finishing year 9
144/360 makes no sense.
Yep
wait it doesnt
That means the angle is 40 degrees and it's an obtuse angle.
?
Why make things so complicated
i feel like i mis said so many things
Yeah probably.
If you get the angle let me know.
Otherwise I have to do my own work.
Just visualise sums...
how did u guys figure out those numbers..
As is said the yellow part is nothing but a rectangle....without some parts
yea but it doesnt overlap so i ahve to subtract it
What do you mean by doesnt overlap....
Ok bruh....
Join my grp
yellow seems like its a rectangle covered by those two shapes right?
but yellow is actually just that shape
but knowing that its a rectangle can help
okay wait
uhm
to figure out yellow i would have to
Okkk
Youre
Shaded part is yellow.....rectangle
The length of the yellow outer part is 11cm
yes
The diameter for green circle is the breadth for the yellow rectangle.
yea the diameter of the green circle is 5.5
and so the width of the yellow rectangle would be 5.5?
Yep
Yep...
and then in blues case its rectangle
without the semi circles / sector
would be
11.5cm length x 5.5 width
63.25cm2
The area of the green circle inside the yellow rec is 11.8 estimate
and then the semi circles would be
Blue part not reqd
how did u get this estimate? i need to shower working
Oh no estimate
.
what does this mean
Divide
Total area or only the yellow part is reqd
23.76cm
whats reqd??
do u mean requested?
Bruh sorry....i have to exit.....its so late here...
oh
alright
theres a total of 6 questions
its this thing i have it on a file
hopefully someone can help
DESPERATE HELP PLEASE SPAM PING ME
OKAY SO green area and blue area together is 110.77cm, to find out the total area and yellow i would have to.
okay wait
@mellow lark i haev a question if u could answer if ur free
Mhm?
its not a quarter circle, but more closer to a semi circle
the sector
its 144/360 and it is an obtuse angle
im pretyt sure thats right
so
u said like
u said the angle would be 40 degrees but
its not..
the angle is 144 degrees
?
So it's just 144.
yea
Okay that helps.
wait
OMG
I NOTICED IT
OHH
144/360 i didnt mean divison
i meant like
its 144 degrees over 360 total degrees
😭
wait what can i use the angle for though?
What is 36 degrees in radians?
radians?
wait i need to google what that means
im so sorry
okay i think i know how to figure out the area instead of subtracting
it doesnt need to be exact but
if i can figure out
the triangles depicted from the red lines
i can solve this
because those triangles i made are all the same size (measured and confirmed with teacher)
i also saw him doing it and said it would work
so i think
im just gonna make it straight even if itsn ot
but like
ur way is probably more accurate
i just need to figure out what a radian is
wait wouldnt 36 degrees in radians be what i showed u?
just this?
or do u mean like
what would it be
as a radian expression
0.628319
thats what it would be in radians
36° × π / 180°
= 0.2π rad
= 0.62831853072 rad
Good that's what I needed.
Multiply that by the radius and you have the area of the sector which you add the the parallelogram beneath it.
Find the area of the yellow rectangle. To that, add half of the green circle's area to account of overlap.
Let me finish, I'm not helping after this.
Find the area of the blue rectangle. Add that to the areas of the two semicircles on the ends. Now add this with
This.
From all of that, subtract
This.
so i multiply 0.62831853072 by 2.75cm which is the area of the sector?
Exactly.
i was gonna try and figure out the area of these but this way
seems more
whats it called
accurate
from doing 144
----- times pi times 2.75 to the power of 2
360
thats what u meant right?
oh see you, hope u have a good night / after noon / morning
Replace 144 with 36.
Thank you, good luck.
for the other sector?
Mhm.
Here let me simplify.
alright
Mhm.
<@&776327020388679680>
@narrow scroll found it
hi
so like practically
i have to find the area of this shape
ive been stuck on this question for a few hours.
i know most measurements
Wait can you label angles ?
Angles of the kite or above the kite
oh uhm
so above the kite
the two sectors
the smaller one has an angle of 36 degrees
the bigger oen has a 144 degrees
Upper 144
Aight or kite's top has 144
Ye
isnt it just 144
The sides
This is gonna take ages 
Well do you know length from top to bottom ?
of the kite or the blue section?
Kite
maybe
And right to left ?
no im crying
😭
why the fuck is this so hard
can we get mj back here
ill buy them nitro
if they figure this out for me 💔
no
im staying up
i have to
its due 3 days ago
but i had technical issues
so im doing it now
☠️
and bullshitting my way
SO PLEASE
CAN U HELP ME
ILL BE UR SLAVE
OR WTV
WHY THE FUCK AM I ASIAN AND SHIT AT MATH
@last mountain BRO
WERE BOTH WRONG
IT CAN BE VIEWED AS QUADRILATERIAL
INSTEAD OF A KITE
AND IT WORKS
too
A kite is a quadrilateral
A parallelogram is quadrilateral too
In which grade are you in
What did you guys find
I CANT FIND SHIT
HOW DO I FIGURE THIS OUT
IVE BEEN AWAKE FOR 5 HOURS DOING THIS
AND THATS ALL IVE DONE SO FAR
And do you have to type the answer or MCQ
waht
no i had to make the letters up
@clever storm
do you know to figure out the area of this kite
or like whats missing to figure it out
Divide it into 2 right angled triangles
yea then?
what do i do after that??
okay wait
so would both right angled triangles be
Not sure about the second one
What's radius of the semi circle above
wait what do i do with the radius
Multiple this by 2 that's the area of the kite
Yes
Wait I just wanna confirm
alright
I am still wondering how can they give a ninth grader this question
wait why
is this like not possible
for a ninth grader
or like is advanced or is it lower
Idk the syllabus at your place
.....
But it's a bit too big
I mean a person with a little bit more than basic knowledge about properties of quadrilaterals can only solve this question
Maybe syllabus at your place is different
fuck u australia
I am just comparing it with what I have studied in grade 9
I have finished that grade
@clever storm
Yeah
do you know how to figure out percentages next
Can you give the question
What percentage of the total area is the green, the blue and the yellow?
Yellow ( 33.4cm^2) + Green ( 23.76cm^2) + Blue (87.01cm^2) = 144.17cm^2 in total
is my results
so all i have to do is like
33.4cm / 144.17cm x100?
and the same for the others?
Yeah
My geometry is pretty weak
are u in america
Nah
I FINISHED IM SO PROUD