#simple factorize
1 messages · Page 1 of 1 (latest)
$x^2-y^2-6y-9\=x^2-(y+3)^2\=(x+y+3)(x-y-3)$
Daniel_The_Maniel
It’s just a perfect square trinomial and a difference of squares
Thanks
Can u do this
C and d
I can do c just do d
Heyy
Nvm i can do d no too
for c use substitution, let t = x²
it becomes 4t² + 16t+ 9
idk if we can split middle term here but u can something better here
add 7 and subtract 7
It becomes : 4t² + 16t + 4² - root 7 squared
(4t+4)² - root 7 squared
final answer : (4x²+4+ root 7)(4x²+4- root 7)
maybe u can factorize these quadratics too but i'll leave that to ya
$1-x^2-y^2+x^2y^2+4xy$
Daniel_The_Maniel
$-x^2-y^2+2xy+x^2y^2+2xy+1\ -(x-y)^2 +(xy+1)^2\(x-y+xy+1)(x-y-xy-1)$
Daniel_The_Maniel
lol this isn't "simple"
You know the thing I hate about factoring is that if you’re given just a random polynomial the chance it factors neatly is so small
All the techniques we learn only work with very specific cases
The question has to be designed to factor nicely
WAit this is wrong
It should be $(xy+x-y+1)(xy-x+y+1)$
Daniel_The_Maniel
Its simple i already did it without help both
Did you do b
I think that one was the hardest
Why did you even ask for help lmao
Idk
When i saw question i got scared so i asked but when i solve it , it was easy
Lol
Nice
Anyway thanks for help in a
Np
/close
Maybe it’s \close
Bruh
Idk
Whatever it should close on its own in a few hours