#Discrete math
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You apply (a) to the new expression "[(r \/ p2) -> q]"
so basically you gonna get "(*)" but with r in place of "p1"
oh i see
what does it mean by "new expression"
nothing more than it being new relative to the previous item, it's another expression constructed in (b) that you didn't have before
the new expression being
[(r v p2) -> q] <-> [(r -> q) /\ (p2 -> q)]
or do we apply the [(r v p3) -> q] from (i)?
it's p3 in place of p2
but this is the expression you get from applying the (a) equivalence to the new expression [(r v p3) -> q]
r in place of the old "p1", p3 in place of the old "p2"