#Can you try to solve this problem using trigonometric substitution?

109 messages · Page 1 of 1 (latest)

primal knoll
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∫√x^6−x^8

tropic solar
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Factor out x^6. That should make it clear.

primal knoll
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i did that

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still came up with a diff answer from the textbook

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can you try solving it for me using trig substitution

tropic solar
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sqrt(x^6 - x^8)
= sqrt(x^6 * (1 - x^2))
= x^3 * sqrt(1 - x^2)

x = cos(t)
x^3 * sqrt(1 - x^2) = cos^3(t) * sin(t)```
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I'm sure you can take it from there.

primal knoll
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I got sin^3 (x) times cos^2 (x)

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did one of us use the wrong substitution?

tropic solar
primal knoll
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no

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Since dx = cos(x)dx

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so I have

x^3 sqrt (1-x^2) * dx

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so it becomes sin^3 (x) * cos(x) * cos(x)

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no?

tropic solar
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Oh, right. I forgot to replace dx. In my defense, you didn't write it.

primal knoll
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haha lol

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When I fully expand it I end up with a weird answer very close to the textbook

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but I cant tell where I deviated

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from the correct answer

tropic solar
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Okay, so we have int sin^3(t)cos^2(t) dt.

primal knoll
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Yes

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I then broke down sin^3(t) into sin^2(t)sin(t)

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I converted sin^2(t) into (1-cos^2(t))

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so I end up with

int (1-cos^2(t))*sin(t)*cos^2(t) dt

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cos(t) = u
-sin(t) dt = du
dt = du/-sin(t)

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-1 int (1-u^2)u^2 du

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taking the antiderivative I get

-cos^3(t)/3 + cos^5(t)/5 + C

tropic solar
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Gotta roll it back to terms of x.

primal knoll
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plugging in the value of cos(t) through a triangle I end up with

-(1-x^2)^3/2 (1-x^2)^5/2 + C
-------------- + --------------
3x^3/2 5x^5/2

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the textbook answer is

(-1+x^2)(2+3x^2)(sqrt x^6 - x^8)
---------------------------------------- + C
15x^3

tropic solar
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Okay, wait, I can't read any of that. What's cos(t)?

primal knoll
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(1-x^2)

tropic solar
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...not according to my math.

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Okay, wait, where did the xs in the denominator come from?

primal knoll
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when I plug in the values in the right triangle, Cos (t) = adj/hyp so it is sqrt(1-x^2) / x

tropic solar
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Why is your hypotenuse x?

primal knoll
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because x = sin(t)

tropic solar
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And sin(t) equals...?

primal knoll
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ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

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let me see

tropic solar
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You didn't even do the wrong math right. If your hypotenuse was x, then your adjacent side should've been sqrt(x^2 - 1).

primal knoll
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ok

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yea basically

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I drew the triangle right and labeled

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just wrote down the wrong thing

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no the adj side should be sqrt (1-x^2)

tropic solar
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...if x was the hypotenuse.

primal knoll
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ah yea if

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right

tropic solar
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Hence "you didn't even do the wrong math right".

primal knoll
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so my final answer is now

-(1-x^2)^3/2 (1-x^2)^5/2 + C
-------------- + --------------
3 5

tropic solar
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Where the hell does the textbook get the xs in the denominator?

primal knoll
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idk

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I also dont understand how they came up with the numerator

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I'm close

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but

tropic solar
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I am almost entirely certain the textbook is just wrong. I could be completely certain if I felt like differentiating that ridiculous monster.

primal knoll
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Maybe its the same answer

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just differently written

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but this textbooks been giving me so many problems

tropic solar
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It's not the same answer.

primal knoll
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I've done so many questions

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and came up with diff answers

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and im certain that all the steps are took are legal

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thats why I wanted to talk to someone on a call so we can try to figure it out and think of a new way of solving

tropic solar
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,w d/dx (x^2 - 1)(2 + 3x^2)(sqrt(x^6 - x^8))/(15x^3)

wise fjordBOT
tropic solar
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Huh. Sonofabitch.

primal knoll
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Hahaha

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Perhaps they used U substitution however the book requires us to use trig substitution

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,w d/dx ((1-x^2)^3/2)/3 + ((1-x^2)^5/2)/5

tropic solar
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,w d/dx (1 - x^2)^(5/2)/5 - (1 - x^2)^(3/2)/3

primal knoll
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it input the question wrong whatever

wise fjordBOT
tropic solar
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Which is also correct.

primal knoll
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so

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they are the same

tropic solar
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Or off by a constant, at least.

primal knoll
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Hmm

tropic solar
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Obvious first step is to combine the fractions. As in, so obvious I don't know why I'm the one who has to say it.

primal knoll
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I tried

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still wouldn't make sense to me how the x would reach the denominator

tropic solar
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...multiply by x^3/x^3.

primal knoll
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ah okay

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Technically I did solve the integral

tropic solar
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You did.

primal knoll
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Thank you and god

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This exam is going to be tough

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I appreciate the help

tropic solar
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What'd God have to do with it?

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You're the one who did the work.

primal knoll
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Hes the one who made my brain

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im just messing around ik what you mean

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thank you though

tropic solar
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No prob.

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I really have no clue what the hell's going on with the form of that answer.

primal knoll
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All the questions and answers in the book is like that. The textbook has videos that answers each problem but the professor refuses to give us access to it and i tried finding them online

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I emailed her and fought about it but she doesnt care

tropic solar
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,w int sqrt(x^6 - x^8) dx

wise fjordBOT
tropic solar
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Okay, what the hell, WA?

primal knoll
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wow

tropic solar
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Okay, WA did u sub.

primal knoll
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thats cheating

tropic solar
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Maybe... maybe you're supposed to do u sub, then trig sub?

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U sub does get you 1/2 int u sqrt(1 - u) du. If you then take a trig sub for u...

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Then you end up right back where we were.