Been arguing about this after the exam w friends

[tulip rock]

ye

weve done it 2 different ways

i did

6(2a+2)-4(3a-1) at the top

and solved

but they did something else

[zealous sphinx]

That's fine, there's prolly other valid methods as well

[tulip rock]

THEY GOT COMPLETELY DIFFERENT ANSWERS

where did i go wrong

[twilit bear]

First of all, u gotta combine ur denominator

Which u did later

And then, r u sure u got 12-4 right?

[tulip rock]

-12a+4

but the - behind it

changes it into -

so its

-12a+(-)4

r i g h t?

[fiery steppe]

Here in the second last step 12a+12-12a-4 = 8 not 16

[shell tapir]

No bro he has done it correct
U r the one messing up
It is 12a+12-(12a-4)

@tulip rock it is correct

[tulip rock]

my friends got -22/ something

[fiery steppe]

$\text{Following cross multiplication:}
\frac{6(2a + 2) - 4(3a - 1)}{(3a-1)(2a+2)}
\vspace{1ex}
\implies\frac{12a + 12 - 12a + 4}{6a^2 + 6a - 2a - 2}
\implies\frac{16}{6a^2 + 4a - 2}$

[edgy cliff]

AdhKris(People's Voters Union)

[tulip rock]

,help

[edgy cliff]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[rugged monolith]

I need help on this Pythagorean theorem question can somone help me

[wraith talon]

?

you should get 16/((2a+2)(3a-1))

now

if theres an equal sign

thats a different story

if its = 0

you can multiply everything by both