cuboid

[near storm]

Help please

Help??

[acoustic lodge]

so the maximum length that can be fit inside it is the diagonal ?

more specifically 3d diagonal

[near storm]

Can you elaborate on that please

[acoustic lodge]

maximum length of a straight line that can fit inside a square would be its diagonal correct ?

[near storm]

Yep

The hypotenuse right

?

[acoustic lodge]

ye

[near storm]

Yea

[acoustic lodge]

the maximum length that can fit inside a cube or cuboid is that same diagonal, but height also taken

[near storm]

Yep

But how do I use those numbers given

[acoustic lodge]

did you find the hypotenuse ?

[near storm]

Is it 85^2 + 40^2

And then the root of the answer is the hyp right

?

[acoustic lodge]

yup

that would give you the hypotenuse, then you have another step

first find hypotenuse imma then tell you the other step

[near storm]

Ok

5 root 353

Right?

[acoustic lodge]

Oo also I m playing so I might reply a bit late

[near storm]

Ok

[acoustic lodge]

now look at the triangle it makes with height

[near storm]

U mean the 40?

[acoustic lodge]

wait imma draw and show

[near storm]

Ok

[acoustic lodge]

this triangle @lament viper

[near storm]

Yes

[acoustic lodge]

oh wrong ping

[near storm]

It’s fine lol

[acoustic lodge]

we have to find hypotenuse of this traingle

[near storm]

Yep

[acoustic lodge]

ye, it only makes this chat holyer

[near storm]

I understand it

Wait lemme try do it myself

[acoustic lodge]

okie

[near storm]

So do I do

And then the root of that is my final answer right?

[acoustic lodge]

yup

[near storm]

Thanks g

But I have to answer the question

Will the 1m rod fit or not

[acoustic lodge]

now what is sqrt of what you found

is it larger than 1 m ?

[near storm]

Yea

It’s 102.1

2 cm ish larger

Isnt it

[acoustic lodge]

nah

[near storm]

?

[acoustic lodge]

its 1.02 m

[near storm]

No I took it in cm

Same thing bro

Either way or doesn’t fit

Right?

[acoustic lodge]

ye

[near storm]

Okay

So how do I write it

[acoustic lodge]

so it fits :D

[near storm]

No?

It says 1m rod

Nvm

It does fit

I read it wrong

[acoustic lodge]

1.02 m space

and 1m rod

[near storm]

Yea

This good?

[acoustic lodge]

yup

[near storm]

Thanks

Appreciate it

[acoustic lodge]

you are welcome :D

[near storm]

Also

I need help with this question

I don’t get it at all

[acoustic lodge]

which one ?

[near storm]

It’s about bearings

I don’t rlly know much of it tbh

[acoustic lodge]

,rotate

[near storm]

Do I use Pythagoras here?

[acoustic lodge]

wait lemme read

you have to find boat's distance

[near storm]

Yea

[acoustic lodge]

so yes pythogoras

[near storm]

So how much it travels?

Or

[acoustic lodge]

no no, how far is it from original place

[near storm]

So is it like a triangle

And I find the hypotenuse

[acoustic lodge]

ye

[near storm]

The 55km is the base

And the 30m is the height

Then 50^2 + 30^2

then the root of that

Right?

[acoustic lodge]

55^2 right ?

[near storm]

Yea my bad

But is that it

[acoustic lodge]

ye

[near storm]

Oh lol

I thought u has to use like a protractor

[acoustic lodge]

no lol, north west east are at 90 degrees

[near storm]

How do I round

Cuz I got root 3925

[acoustic lodge]

what did you get ?

oh

[near storm]

Then from that to 5 root 157

Simplest form

[acoustic lodge]

,w sqrt(3925)

[near storm]

62.6 good enough?

[acoustic lodge]

yup

[near storm]

Alright