Algebra

[frail salmon]

a

oh

ok so

if 7a - ab over c = c

express b in terms of a and c

@dire pond

[dire pond]

wha

[frail salmon]

ikr

[dire pond]

you mean (7a - ab) / c = c?

in human terms

[frail salmon]

no, 7a is seperate

it would be

7a/1 - ab/c = c

but in the equation the 1 isn’t there

[dire pond]

$7a - \frac{ab}{c} = c$

[oblique path]

flr

[frail salmon]

yes

[dire pond]

like this?

ok

ez

1. separate the b terms from the non-b terms

[frail salmon]

so, in layman’s terms…?

like how would i do that

[dire pond]

it is layman's terms..

x+y = z
is equivalent to

y = -x + z

for example

you can add/subtract the same amount from both sides

[frail salmon]

ohhh

i get that

[dire pond]

which terms contain a factor of b?

[frail salmon]

so if im separating the b terms from the non b terms then

[frail salmon]

ab?

[dire pond]

huh

[frail salmon]

the term ab contains a factor of b

[dire pond]

you have 3 terms

7a

• ab/c

= c

[frail salmon]

oh

ab/c

[dire pond]

yep

so apply this adding/subtracting rule to isolate the b term

[frail salmon]

so id divide the c on both sides to get just the ab right

or no

multiply

[dire pond]

no need for now

[dire pond]

.

[frail salmon]

this one?

[dire pond]

yes

[frail salmon]

ehm

[dire pond]

in other words you can "move a term on the other side" if you multiply it by -1

[frail salmon]

doesn’t multiplying by -1 just change the sides?

symbols*

im sorry if i sound stupid im just not particularly great at algebra

[dire pond]

sorry Disc crashed lol

[frail salmon]

no worries

[dire pond]

7a - ab/c = c

• ab/c = c -7a

ab/c = -c +7a

then you want only b so you divide by the factor that's with the b

in this case a/c

b = -c^2/a + 7c

that's it

[frail salmon]

you lost me when you did ^

idk what “^” means

is that just to represent the

fractional line or

[dire pond]

power

a^2 = a * a

[frail salmon]

oh god

yeah no im just

yeah im totally lost 😂

[dire pond]

$7a - \frac{ab}{c}=c$
$7a - \frac{ab}{c} - 7a = c - 7a$
$- \frac{ab}{c} = c - 7a$
$ \frac{ab}{c} = -c + 7a$
$\frac{ \frac{ab}{c}}{\frac{a}{c}} = \frac{-c + 7a}{\frac{a}{c}}$
$\frac{ab}{c} \frac{c}{a} = ({-c + 7a})\frac{c}{a}$
$b = ({-c + 7a})*\frac{c}{a}$

$b = {-\frac{c^{2}}{a} + 7c}$

[oblique path]

flr

[dire pond]

omg

one sec

$7a - \frac{ab}{c}=c
7a - \frac{ab}{c} - 7a = c - 7a

• \frac{ab}{c} = c - 7a
  \frac{ab}{c} = -c + 7a
  \frac{ \frac{ab}{c}}{\frac{a}{c}} = \frac{-c + 7a}{\frac{a}{c}}
  \frac{ab}{c} \frac{c}{a} = ({-c + 7a})\frac{c}{a}
  b = ({-c + 7a})*\frac{c}{a}

b = {-\frac{c^{2}}{a} + 7c}$

[oblique path]

flr
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dire pond]

nope

lol

fffffffffffffff

[frail salmon]

god my brain hurts reading this

[dire pond]

one sec

[oblique path]

flr
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dire pond]

ffs

[frail salmon]

in the 4th line did you multiply by -1?

[dire pond]

yes

[frail salmon]

also in my textbook’s answer sheet

dunno if it’s right or wrong but:

b = c(7a-c)/a

[dire pond]

it's exactly the same

just they didn't divide by a and mutliply by c

which usually would be considered as an incomplete answer but whatever

anyway. That should be it

you are welcome

[frail salmon]

ok, thanks @dire pond

small question, in the fifth line you put everything over a/c, why? @dire pond

[dire pond]

You have b times something

And you want just the b

So you divide by the something

Something = a/c in this case

Welcome

[frail salmon]

ohhh