#The Derivative as a function
13 messages · Page 1 of 1 (latest)
Wait, I'm confused. If you're having trouble finding f'(x), how would you do anything with f'(x) = 0?
...right, and when is that 0?
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solving for f'(x) = 0 for x
@glacial zealot
I see, thanks! @quaint estuary
I thought I had to get an actual number for that part, but I just need to put f'(x)= (x^2+22x)/(x^2+22x+22) for the first part, correct? @quaint estuary
...yes, that's what the problem explicitly states.