#I have this question - Power Drop (w,km,μW)
1 messages · Page 1 of 1 (latest)
my answer is 11
0.45 w =450000 μW
now you just need to solve the equasion: 450000/(10^(x/2.75))=45
1 messages · Page 1 of 1 (latest)
When a power cable drops by a factor of 10 approximately every 2.75 km.
If the original signal power is 0.45 W (= 4.5 x 10-1) then how far will a signal be transmitted before power is attenuated to 45 μW?
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my answer is 11
0.45 w =450000 μW
now you just need to solve the equasion: 450000/(10^(x/2.75))=45