Differentiation

[steep grotto]

Could anyone help me to understand this? I understand that I woulkd have to replace x with -1 but that's about it.

[sour trellis]

I can help.

[steep grotto]

thanks

[sour trellis]

Alright.

@steep grotto do you know integration?

If not I can show another approach.

[steep grotto]

I am learning intergration now.

[sour trellis]

Could you integrate something like $4x$?

[thorn ingot]

femboy

[sour trellis]

nvm we can do it without complications like this

Notice that $\frac{\mathrm{d}}{\mathrm{d}x}x^2+C=2x$

[thorn ingot]

femboy

[sour trellis]

Where C is just some arbitrary constant

Thus if $f(x)=x^2+C$ then $f'(x)=2x$.

[thorn ingot]

femboy

[sour trellis]

We now know $f(x)$.

[thorn ingot]

femboy

[sour trellis]

Let's solve for the constant.

$(-1)^2+C=4 \implies$

$1+C=4 \implies$

$C=3$

[thorn ingot]

femboy

[sour trellis]

$f(x)=x^2+3$

[thorn ingot]

femboy

[sour trellis]

@steep grotto

[steep grotto]

Hi sorry I'm back ill try to read this all

[steep grotto]

$2x$^2?

[thorn ingot]

Verluei
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[steep grotto]

@sour trellis

[sour trellis]

no 😦

$\frac{\mathrm{d}}{\mathrm{d}x}2x^2=4x$

[thorn ingot]

femboy