#Neuro ARG - Cracking the "Numbers" Video
1 messages · Page 9 of 1
important difference if vedal played with google translate or something
its unlikely he did given what we've seen tho
it's supposed to be a file though, not a human language
I know it's off but is it possible that there's two keys? Or maybe two different instructions?
I can never say oh it’s been so long
Counting all the days, it’s been so damn long
Oh how much I’m scared to let you go…
Somewhere in the walls I hear you talk…
Finding all these numbers
Start with number 2 yeah
Matching all the letters
572943
Add another 9 yeah
Add another line yeah
Multiply by 5 yeah
How long will I keep this up?
I how much it hurts to see you go…
Generating lyrics is a pain
(This part shows the Golden Ratio)
Add another 6 yeah
Flip the numbers backwards
Make the 2 a 3 yeah
Abcdefg
Multiply by 9 yeah
Add the numbers 2 4
17 is first yeah
Abcdefg
Just a thought maybe I am way off mark
You're looking for the lowest entropy value of the putative plaintexts relative to each other. The absolute value doesn't really matter, it'll change depending on length anyway, it's whatever is lowest is most likely. For example, even a 139676 byte jpg, of which the majority is pretty compressed would score 7.9790936 vs the average of completely random data of 7.9987458. It's a small difference, but very relevant
The only case where this would fall apart is if there payload is entirely compressed data with no headers or structure
which is pretty damn cruel
i see. i guess i won't make more than 5 files to see then. thanks
any modern encryption scheme will also send entropy through the roof by design
save for maybe ECB mode with repeat plaintext blocks
I thought the shannon analysis confirmed that we we're dealing with high entropy
yeah we have shannon entropy numbers on every base64 string so far i believe
all super high
could this also be one payload split and encrypted separately?
is compressed / encrypted / random data basically indistinguishable? in that case we just have to hope the plaintext has enough structure that we can actually recognize it when we see it.
ive had the song on loop and i just got chills 
theres two voices here, one is whispering the lyrics and one is singing them
most noticeable around 48s in
not arg related
but its a cool song
lol
i think you saw a ghost
gotta listen super close
and not focus on the lyrics that actually sing
just use the adobe podcast thing
theres a monotone whispering
Most modern cryptography is indistinguishable from pure random noise (Outside of academic attacks on large amounts of data). A lot of compressed data is usually held in some kind of file structure (e.g. 7z/rar) which may (and usually does) give enough of an entropy drop to distinguish from random data. But there's nothing stopping you from just encrypting a raw compressed stream which would be indistinguishable from noise
but occam's razor and all you'd probably expect a simple filetype or printable text from the plaintext
well compression should be pretty easy to rule out so long as there weren't any manipulations after it
we can try at least a few popular algorithms on any functioning settings, most should indicate quite quickly if its incompatible data
don't most compression formats usually have headers and stuff you'd notice fairly quickly?
maybe the plain text looks like random noise, but you need to extract the bits at indexes that are fibonacci numbers?
most files in general do
im really stretching here.
if its a known header its possible to just remove said header tho
maybe but even if we did what would we do with them ¯_(ツ)_/¯
that would be absolute torture for the GM to inflict to us
presumably, once we extract the bits it will resemblance a known file type or just be plain text.
I suppose you could just check another level deep and check for the entropy of all extracted bits from the payload according to the fib sequence
I wonder how much £ worth of electricty we've used on computation for this ARG so far
endianness doesn't matter here right? if we have the correct plain text, assuming there wasn't multiple layers of encryption/compression, the entropy will still drop.
off the top of my head it shouldn't in terms of entropy
as long as you check consistently in terms of the same endianness for all plaintexts
THERE'S ANOTHER NUMBERS VIDEO???
x/26YzndR5VhxhR5tGvNJKOfHX2DL3qYXgyJvVQ5EJi6jH/wmI21ftjY+i5GstZRo0gHxRmEmS4iavJfRYrvtdrUXBSpZPiRi25e9HMV0FimPaDxMrVD8P4/VgYFWh01X92ftE5IlyNDasz4LCkWPiULaPGg+Et2AMzGqtLK7C0T/04wDgbqhYkcPBemStjxJcyfKjgXcMa3LJ6IQPaMakmgm2R3G38jIB/YNBZt3p4Ixc6VdvThxszTH1CxTFtKkwua2QsZFQaGmoOBx9n77TlpIFgxNz6PQyI5gQ0bcUI6szKQgAezC5tFT9lHhQVuau0xABiWMXX+m39RE45a0aE1/8G...
Oh boy.
new clue
i stopped it at 130 million. going to try to make it even faster and remove some known bugs later.
if anyone wants to try to run this .com file here you are
What exactly did you do to get this file again?
The files are coming for you
I don't think that file is a valid COM file. It has the initial signature of 0x5A4D ("MZ") but the two bytes with offset 4 should be the size of the program in multiples of 512 bytes. The file however is much smaller.
ohhhh a second numbers video dropped
math 2 from _neurosama
neuro calculus
we need neuro 2
i guess i am just going to search again for valid file types then. can you go further into detail what exactly do you mean by "two bytes with offset 4" and is file size rounded to upper 512 bytes or lower (i assume upper) (and what would file size of 1040, 1264, 2304 etc bytes look like)
what are you trying to do again?
read the post name
i mean, how are you "searching" for valid file types?
wdym file types
I'm talking to @hasty vale
its too hard for me to explain right now.
i can give you my python code if you can figure it out
sure why not
according to this https://wiki.osdev.org/MZ the header for a MZ executable file should start with a two byte signature (0x5a4d), two bytes number of bytes in last page and two bytes number of pages (with each page being 512 bytes except for the last one which can be smaller).
If you look in my image above the number of pages is 0xC22A with the last page having 0xA01E bytes. This means I would expect the file to be about 25.5MB but we obviously have way less data.
Someone tell me why you guys react 🤓 whenever someone learns a 2nd Numbers video exists? 
so it's .com specific basically?
yes. that stuff is what you would expect following the file signature for this type of file.

i cant go through documentation of every single file extension
i mean i guess it makes sense to add this for .com checking since they seem to have the least entropy
taking a quick look, are you converting the b64 string into hex, and then during a substitution cipher on the hex, and then checking if the resulting binary matches a file type?
isnt it like for any file? like for jpeg you will have header, and exif data and what not, having just header match is not going to tell how valid the file is as jpeg
so is it filetype specific or is it not
(can i just add size checking along with magic bytes or would i have to go through every documentation to look where they are is the question)
the header is file type specific. I think what w1n7er means is that the issue of you finding a solution which starts with the correct signature but still results in an invalid file will happen with every file type.
and I don't think there will be a generic solution for checking for the file size since there are so many different ways to implement the size in the header of the file
well this sucks then, because entropy isn't going to help with that.
i guess i would just have to first check for magic numbers and then manually add type specific checks
i'll try that with other base64 strings first, maybe they'll give more sensible filetypes than .386 or .com
yeah, maybe. I mean how likely is that we have to run a 16-bit MS DOS 2.0 program for the solution? 
to this, sorry i didn't answer, no, firstly, there is no binary, secondly, i go from file type and from it making a substitution, it checks whether substitution is even possible
i will start measuring this thread's progress by how much the schizo reacts go up
june 2 schizo count: 149
make a doc on it
none of the long base64 codes are any sort of recognizeable filetype according to linux
checking a header list didnt help either
i also went through pretty much all 128 bit keytypes but unless i made a mistake the phonenumber code didnt get me anything
unless the endianness is reversed but i doubt it
This is a list of file signatures, data used to identify or verify the content of a file. Such signatures are also known as magic numbers or Magic Bytes.
Many file formats are not intended to be read as text. If such a file is accidentally viewed as a text file, its contents will be unintelligible. However, sometimes the file signature can be re...
yeah i did that
tried that and the file command on linux which does the same thing
its 100% encrypted
I only comfirmed manually for few common files types but also ended up with nothing matched
the main problem im trying to tackle is the 128bit key in the javascript
im abut to build a base256 analog computer if i have to sit here and decrypt all this shit
soundcloud now says "Open in FireFox"
time to design an ASIC specifically for the ARG 
true
sorry I'm dumb and new but I scoured the Numbers II doc and decided to put in my 2 cents: Every sequence of numbers in Numbers II follows the same pattern of neuro/anti-neuros except for the number 906, which shows -+-+ instead of the established +- for that 2nd in the sequence spot. Maybe 906 is the "odd one out" mentioned on the soundcloud?
hey, don't call yourself dumb (:
It could be that you're onto something. Have you seen the docs yet? We've written quite a bit, but new analysis is always welcome if you wanna write it down!
We all dumb here at this point lol
other strings got tons of magic numbers hits but none of them look sensible enough for me to add further validity checks.
i will suspend this as a dead end until we get more strings or smth
hi, any success/news?
yes
"Open in FireFox" was it here before?
it is noted in the docs
no
it's new
So what is special about FireFox ?
So we need to do something in firefox?
if you open it in chrome you won't get the full code
i think nothing special, the description is a little bugged in chrome
it format the long encoded text different
Top = Firefox
Bottom = Chromium (Google/Edge)
ohhhh
I use firefox anyway
but the splits in the displayed firefox code might be intentional
I don't think obtaining the code is the clue itself
there is a doc about it already but, yea
we have doc: "numbers II - Soundcloud..." and we have it mentioned
Yes i'm just telling Kande
If we follow the splits in firefox there is one missing
/EmWDRdMl0f.... wasn't afffected by the splitting.
So my first thought about it just being an automated thing from FireFox to split text with "/" doesn't really work.
is it sounds kinda like she’s saying abcdefj to me
She probably has some accent. "Whisper" didn't even catch the "A" the the beginning and told me she is singing: "B, C, D, S, J,"
Is this to discuss Numbers 1 and 2 or just 1?
@round phoenix has leveled up! (0 ➜ 1)
Number 2 thoughts
Neuro's appear on the screen as numbers are read out. the Neuro's could be Algebra and their position is relevent to that. The gap in music each batch loses an amount of Neuros and gives a void to fill
i've offered two answers to each set up to set 3.
First Set:
(N) = 201
(-N1) + (N) = 1321
(-N1) + (-N2) + (N) = 5331
(-N1) = 1120
(-N2) = 4010
positional answer
(-N2) + (N) = [4211]
afterimage answer
(-N1) + (-N2) = [5130]
Second Set:
(N) = 723
(-N1) + (N) = 743
(-N1) + (-N2) + (N) = 4913
(-N1) = 20
(-N2) = 4170
position answer
(-N1) + (-N2) = [4190]
afterimage answer
(-N2) + (N) =[4893]
Third Set (the upside down se
(N) = 879
(-N1) + (N) = 975
(-N1) + (-N2) + (N) = 2415
(-N1) = 104
(-N2) = 1440
positional answer
(-N2) + (N) = [2311]
afterimage answer
(-N1) + (-N2) = [1544]
Fourth Set
(N1) = 716
(-N1) + (N1) + (-N2) + (N2) = 906
(-N1) + (-N2) + (N2) = 4156
(No Neuro) = (No Number)
(-N1) = ???
(-N2) = ???
(N2) = ???
I'm stuck here, maybe the neuro's at the end require batches 1, 2 and 3
iCould be way off but its fun to try stuff
Did anyone tried to convert the lalala in numbers 1 to binary, to see if it gives any results? I didn't saw it in the document or I missed it.
Also did anyone tried convert the lyrics to binary by, if the letter is odd number = 1 and if even = 0
someone did something at least similar in the docs
did anyone try bundling the numbers by their last digit like this yet and finding a pattern based on that?
201 1321 5831
723 743 4913
879 875 2145
716 906 4156
879 would not fit the pattern, but it's the only one that does not
i dont think i have enough brainpower to comprehend. could you elaborate?
the ones that are said without long breaks inbetween end in the same digit (1,3,almost 5,6)
so we are "missing" ones ending with 2 and 4, which is a "void" we could "fill"
oh yeah
3 3 3
9 5 5
6 6 6```
even if by themselves they mean nothing and only used for rhyming that still suggests something
even if it'd suggest leaving them out or sth
would 879 then be the odd one out
if this theory works then yeah
still, can we come up with a pattern for the rest that isn't schizo
it is quite a leap of logic to be honest
yeah, I don't see any form of pattern after this
he is not like the other girls
idk if it means anything but they are all odd numbers
oig wat
my guy, 6
except 6
lol
all odd except 6
i frogo
nvm it probably actually doesnt mean anything
even if it doesn't mean anything and is just arranged like that for rhyming, that would suggest order of numbers is not important
yes
is it in the doc or what is up
it's a screen shot so yes
If so then what is about X and Y?
1+1 and 1+2 are also unclear, but technically it doesn't say these must be connected. this may be just a number dump
For a second I thought of linear equation but that doesn't connect with anything 
if you re-arrange 879 slightly by putting the 9 in front you get the 16th fibonacci number 987
surely it's just a tutel's typo 
it won't rhyme then though
hmmm, is it a coincidence though that vedal's user name contains the 16th fibonacci number? 
idk
if you want to start reaching even harder here are numbers in a table where rows are first digit and columns last digit
Hmmm
If you include 0 it's the 17th, could mean "17 is first, yeah"
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181.
but "start with 2"
"17 is first yeah" refers to the result having 17 as its first 2 digits I think
tbf that is what we assume
hmmm why when I give the decoded gibberish message to GPT for fun it bugs him out and crash the hell out of him?
gpt 4 and gpt 3
Nothing...
I think first stepping stone would be decoding the numbers segment with inverted neuro
plenty of clues; xy could be horizontal/vertical, leave odd one out could be the last frame when no numbers were said and so on
somebody will see it
Has anyone checked the entropy of SoundCloud description?
it's in the docs
or just compressed, but i feel like it'd be wild if it was just a .zip file. Still should check tho
Brute-forcing two base64 this is nonsense
Well, yes
Everyone brutes, but they don't look for archives
What's the best source of magic byte matching? Is it really just googling the first few bytes (what I've been doing, cause i'm dum :p ) or is there a tool somewhere?
binwalk/foremost is pretty good for it
didn't even know that there's a 3rd discussion of arg
goes to show you that im not even schizo

rrrrrrrrrrrrRAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGHHJHHHHHHHHH
WHAT DO THE GODDAMN NUMBERS MEAN
what is the schizo count for today
ulong.MaxValue
schizo/schizo
N̴͑̂u̷͗̓m̸̒̾b̷͂͘e̶̓̿ȑ̷̓ś̴͌
huh what
tried to send a message and it blocked it from sending
ohh I understand why probably
I have an idea but I don't know if I'm right or not... The small one: "DQ5z14ighWwiag7y+cWFQg=="
This one keeps me thinking over and over. It's in the place where a number must be, and if it's indeed a number it's probably a UK number I guess (Vedal is from the UK).
It could be a fictional number, but still a number. UK numbers for SMS (because we know for sure it's an SMS), start from +44. So we know 2 things for sure if it's indeed a number.
It's encoded numbers, probably as text.
It's starting with "+44."
In the Enigma movie, they managed to crack the Enigma machine by understating that each letter of the Enigma is starting with the very famous nazi welcoming pharse, so it's helped them decode it much faster.
Is there a way to do something similar with this? Try to decode it, as if it's a number and the first one must be +44?
That's pretty smart. So basically we're uncovering some of the cipher text and we use that to get insights on the key, right?
Yes
if we manage to crack the small one and understand how it works
maybe we'll be able to crack the others
That's definitely worth writing down
We can assume that maybe "DQ5z = +44" ?
I think so, or at least that the very front is +
Or maybe not assume, but it's a strong hunch
oh also for Uk is 7
44 7
so +447
so if it's correct we actually know a + and 3 numbers
also +447 to base64 = "KzQ0Nw"
also if it's a real operator in the UK, we can try +447(and all the possible operators in the UK)
In that way we'll have 4 digits and one that may or may not be true.
"Mobile telephony (071xx–075xx and 077xx–079xx), personal numbering (070xx), non-UK mobile networks (07624) and pagers (076xx)" - from wikipedia: https://en.wikipedia.org/wiki/Telephone_numbers_in_the_United_Kingdom
When you send SMS the 0 converted into +44 if you from the UK.
In the United Kingdom, telephone numbers are administered by the Office of Communications (Ofcom). For this purpose, Ofcom established a telephone numbering plan, known as the National Telephone Numbering Plan, which is the system for assigning telephone numbers to subscriber stations.
Telephone numbers are of variable length. Local numbers are ...
So long we don't get on a wildtrack that can could generate a lot of phone numbers. That's how you end up dialing people who have nothing with it to do.
Stay careful folks~
I think it's may be a custom alphabet of base64? If the first 4 digits are actually "+447" that means?
D = K
Q = z
5 = Q
z = 0
1 = N
4 = w
So "ig" in: "DQ5z14ighWwiag7y+cWFQg==" must be one of these:
MQ
Mg
Mw
NQ
OA
OQ
and maybe also:
MA
Ng
or it'll change if it counts as 77 for example or any other number with the combination of 7...
yeah, custom alphabet idea was discussed before for the larger ciphers but I don't think any progress was made from those
Yes I know
If it's indeed a phone number, and first 3 digits are +44, so the next 3 digits are numbers between "700" to "799 I guess.
But the next 3 will be hell, from 000 to 999...
i have a feeling they will never crack the code
this thread should file for bankruptcy
maybe the real arg clue was the time we lost along the way
u gotta try tho
Depending on when the soundcloud account was created, arg may not even be done
just coping waiting on a new banger to pop up on the soundclound
If you think about the time as lost then you're more likely to forget the fun we had. ARGs are as close as you can get to an "open-world puzzle game" in that you can try to find solutions for several different puzzles at a time with vastly different approaches and coming up with these and seeing what others came up with is fun.
maybe it's out there somewhere on another account 
any updates since friday?
Nope, only minor changes on SoundCloud profile.
I looked into the string a bit.
The only thing I found was
- It can be divided by 4
- 64 different characters used
4*64 = 265
You can make a bytes array out of it.
my brother thats base64
skim the docs, everything's in here
let him tell his oppinion
I know about base64, but you can make a byte array 2 different ways.
Take the first 4 and add them.
The other way would be
(Letter_count / 4) * 0
(Letter_count / 4) * 1
(Letter_count / 4) * 2
(Letter_count / 4) * 3
Add that 4
I can't tell if someone tried that.
byte array or byte matrix?
I am not aure what the difference is.
I know from coding that you can have a list in lines or colums.
We had a problem in work that one software used columes and one lines.
We had to translate it to use the byte array.
My guess is that it could be the same here.
yes, columns first and row first
That would make it a lot harder to see without translating it first.
No idea if it was tried before.
is this rafa?
yeah
we ignore him in this thread
if you wanna be schizo go to #1112082183235047506
after all he hasnt sent any numbers
it's a safe block, just block the dumbass
bro, the mod role....
then what does the clue mean
how does that account directly link to the original QR code on the intro to vedal's stream?
there's no proof of linking either
didn't you already?
go for it
no thanks
whatever makes you happy

Maybe my schizo, but... I read the documents again, and I realized something. All AI that I have tested, and I and also few more people hear instead of "another" - enough. Enough for 9 and enough for 6, both numbers possible in base64 binary. 9 = [0001001] and 6 = [000110], if it's indeed enough instead of another, it can be this, maybe. ALSO, enough for line, can indicate enough number to get a "line" in base64 "/" which is = [111111]
if we go even harder, 2 = [000010], 572943 = 57, 29, 43 which is 57 = [111001], 29 = [011101], 43 = [101011]
My knowledge in the subject is not that big, so I can't make all the calculations but maybe someone here can do something with this if it'll be useful.
finaly found the video where the guy explains how he uploads the video with the youtube id
but not that important now

oh i know
Iv3 been offli e quite some time
and
static sama replied
i didnt expect that tbh xD
I don't think it holds much significance, but for the first two sequences of numbers the second number is a prime number (1321 and 743)
But could perhaps be RSA prime factors?
They're very small for RSA though, you normally wouldn't pick such small prime numbers
Im not sure how to link to a message on mobile, but I mentioned a couple of things in the main Neuro arg which might be possible solutions (which are math related)
Imo I feel like they might lead to somewhere but I'm not sure if I'm even doing the right math
Hi, is there any progress?
Depends on when you last checked in (: https://docs.google.com/spreadsheets/d/1BCpJA-2GlmjzrxFIEA2pq5Xt6QuAaUI-2L_iAcAnl6Y/edit#gid=521227060
Oke, got it. I guess we still don't know solution for "Numbers" and stuffs related to this?
If we ever solved one of the major puzzles I think we'd all rush to write it trice in the timeline lol
Haha, yeah, you're right 😄
I checked the "DQ5z14ighWwiag7y+cWFQg==" a couple of hours ago for custom alphabet numbers, will post my document soon.
Sheet1
First,Encodes to,Middle,Encodes to,Last,Encodes to,To not be confused about similarities between Il, o0, etc:
0,MD,0,A,0,w,Upper case O
1,MT,1,E,1,x,Upper case I
2,Mj,2,I,2,y,Upper case L
3,Mz,3,M,3,z,A zero 0
4,ND,4,Q,4,0
5,NT,5,U,5,1,If we take a number such as 123456789
6,Nj,6,Y,6,2,An...
Random observation I hope is not the true/original meaning of 572943. First word of the lines in numbers 1:
5 - Finding
7 - Matching
2 - Counting
9 - Add
4 - Somewhere
3 - Oh
it could refer to words in certain lines, but again, without the official lyrics we can never be sure where the lines are supposed to begin or end, we just have a guess
we only have confirmation on the first 3 lines of Numbers, which we did cut properly in our version
Kind of the same thing with Numbers II:
5 - Let
7 - End
2 - Come
9 - 1+1
4 - Should
3 - Tell
but yeah, valid point
Let end come 
not saying you should stop trying btw, we should explore every possibility
but just try your method with other possible versions of the lyrics to see if maybe something intelligible comes up
Yeah, trying different places in different ways with this method. But most stuff end up missing 1-2 things. Like first word with each of the letters "ABCDEFG" in numbers 1 is missing the E:
A - All
B - Been
C - Counting
D - Days
E -
F - Finding
G - Generating
Have anyone tried to apply the instructions based on the blinks?
Like there's 8 blinks so 9 sections of the lyrics and applied the instructions in the order of the sections 5->7->2->9->4->3
Don't think we have tried that yet
Thinking bout trying to apply the syllables to something, just don't know where itd be useful
Tried brainstorming this stuff.... way too many ways to approach/interpret the lyrics set up like this. Could get real messy real fast
So cya in 3 years 
Gl king
Fighting!
I'm going to try and approach it as RSA encryption with clues from the lyrics
this is a long shot, but let's say 572943 is part of the public key, probably n and the two primes in the number II lyrics are p and q
to calculate the private key we would need to derive e from p, q and n
hmmm, no it can't be n because based on p and q it should be n = pq = 981503
so perhaps e = 572943
Nope, also doesn't work since gcd(e, λ(n)) has to be 1 and λ(n) = lcm(p − 1, q − 1) = 489720, so gcd(572943,489720) = 21 
and e has to be a coprime, so it can't be 572943 since that's not a prime number
Technically the numbers in RSA keys don't actually have to fullfil those requirements to work, right? Only to be secure.
don't quote me, but i'm pretty sure the encryption/decryption math would break if the two numbers aren't at least co-prime
fair, i only remember some vague stuff from a course 10 years ago
If you try RSA you can also try GPG i know there was talk about it but i don't really know the difference
Isn't GPG a protocol consisting of a suite of different algorithm, or am I remembering it wrong?
to my knowledge, yeah, GPG uses a suite of algorithms. typically gpg messages / keys have magic headers though, which i don't see in any of the ciphertext-looking base64s
yea i think RSA is in it too iirc
Yes, you can just take two random number as the public key but that would be meaningless if you're looking for security
Got it
it should be that
why it's called "magic headers"?
presumably because you can identify the file by the header, just like the term magic bytes
it's all magic 
(after all magic bytes are usually a header)
I'm planning to make a full analysis of numbers frame by frame. I want to clear some things in the audio too. I don't know if it will happen on the weekend or sooner.
if you want i can use izotope rx10 for audio stuff
I want to compare some parts of the letters to each other
Like is it Nine line, line line or line nine or nine nine
ah gotcha
I have izotope, but I'm not that good with it. But yes, it shall be better for the job.
you can use lowpass highpass filters around 250 and 5k
oh you have izotope
you can play and select frequencies with it as well
the blue highlighted thing does selecting by frequency and time
Strange
I just noticed something
all the videos are 24 framer per second
Is it not 60?
nope its not 60 lol
24 isn't too uncommon tbh
number 1
what the point in making it 24 framer?
literally only Neuro on the screen
Study, only a picture
maybe easier for us to investigate
I'll check now what I can.
Ik 24fps is somewhat common for movies
how do I cut with it a part of the sound
Wdym
you can just give us the timestamp if you want
what are you looking for?
if you want to hear a specfic frequency band,you'll have to do a global filter and then play the segment you wanted to hear
at least i don't know there's a feature where you can do a filter on a specfic part for the track
in rx you can select time + frequency so you hear the selected freq at the time
It's this
this is probably nothing, but yet another way to interpet "fill the void" in numbers II could be to find fibonacci numbers that when the individual digits are sung, they end up being 4 syllables. in which case I believe 610, 987, 2584 and 4181 are the only ones that fit
Im going crazy
We all are
Listening to it in repeats now
I don't think that you can really find stuff in audio
i've done that last week and still found nothing
i've cut the numbers part (lyrics) and assembled them but still found nothing(no images or hidden audio)
and no images or noise in both study and number I
im assuming this isnt a clue but there's gaps around the 5k-8k range in the study video
im probably overanalyzing it
SOmeone want to hear it in repeats as well?
to confirm if it's nine or line
I'll upload files in flac
where did you get the flac file?
vedal posted it or you used some software to do interpolation on the track?
Convert the sound to flac to not lose on quality
pretty sure she says nine then line when i used a freq bandpass
well they all sound different to be honest
you can just select the base freq and can hear clearly that it's "nine", not "line"
The first one sounds like "Nune"
I mean in 572943
Second sounds like Nine and third like line
but maybe it's my schizo idk
enjoy
u could also have ear fatigue
ive experienced that a lot
Listen to it and see if you hear Nine or Line
First is 9 from the "572943"
Second is the first time we hear nine\line
and the last is the second time
I feel like 572|43 doesn't make as much sense because of the SoundCloud link
It's a referense
it's confirmed 9
so we can use it
but it still sound different from the other two
Now I'll check the fibs
First fib appears in frame number: 1294.
First fib last seen in frame number: 1432.
First fib, total number of framer: 138 = 5750ms
Second fib appears in frame number: 1440.
Second fib last seen in frame number: 1572.
Second fib, total number of framer: 132 = 5500ms
Third fib appears in frame number: 1581.
Third fib last seen in frame number: 1717.
Third fib, total number of framer: 136 = 5666.66ms
Fourth fib appears in frame number: 1728.
Fourth fib last seen in frame number: 1860.
Fourth fib, total number of framer: 132 = 5500ms
Do we need to add it into the document or not?
you could mark it down somewhere in the number thread library
@warm finch has leveled up! (35 ➜ 36)
Which one?
Lost or new? Check out Number Thread Library Preamble This document is dedicated to documenting who and what ideas were brought up in the process of solving the “Numbers” video, for the sole purpose of avoiding going into a thinking loop, since there were several instances where newcomers kept ...
I have no idea where to add it in the Library and don't want to make people mad, so if you think it's good add it where it best to be or just leave it to disappear lol
"Matching all the letters 572943"
on a calculator, 572943 is EhGZLS rotated
calculator?
7 segment display
Code should have been 5418008 smh
lol
Hey, unrelated to the arg. But I am solving another arg and need some help with audio files. Can someone help?
@foggy brook has leveled up! (2 ➜ 3)
?
send it
What do you need help with
I’m solving a mc arg thingie, this was found on a hidden button s website. It sounds like melohi but it seems off. https://cdn.discordapp.com/attachments/1004017420194828388/1116378950105567242/mellohi.mp3
All I can tell you is that there is nothing in the spectrum (at least it seems)
btw, u should check the file header, it looks a little weird
idk if this data is relevant at all
I suspect that discord would strip any interesting metadata
im pretty sure they only do that for images don't they?
I think this is right
572943 is odd due to its magical property that no matter how you split it you cannot make a letter out of two numbers
so meaning, the translation of 572943 to letters
will
always
be
egbidc
im just sayin i feel like that egbidc is gonna be a key to something
It can be also base64 or any other way.
Anyone tried to brute force "Numbers" AES-crypted description with a 128-bit key made up of digits only?
I don't know if it's reasonable
what does it even mean "of digits only". bits can only be digits 0 and 1.
if you mean "regular" digits, then what are you decoding them from? decimal, hex, ascii, base64?
I though decimal
like the video say : start with 2, add 9, etc...
if it's the key, it would be something like 1725 1452 6523 4875
maybe i'm wrong
no "==" meaning not base64
what do you mean?
a base64 is only a base64 string if it has a == or = at its end
doesn't matter
that's only if the data it's carrying doesn't have length of a multiple of 3 and needs padding
It has a system of numbers = letters
also this
anyways
Does anybody know how tf I can make a python script use all my CPU instead of 1 core? I always get errors with this
assuming a "cracking" rate of 10e7 then checking all 16 digit numbers isn't possible, but fixing the first 2 and last 2 from the description poem could be done in about a day. I think somebody did try it, but only in ecb(?), and only checking for printable plaintext/certain magic bytes
maybe "number 17 first" is a big clue for bruteforcing
since we can
I can try everything if I'll be able to make this python work with CPU
take a look at the multiprocessing module in python
I tired it still use 1 core or gives me errors. I can try to make like 10 different python script and tell each search for 1/10 of the possible keys.
but still they allwill be on 1 core
I guess
python would probably not work with this
since
its slow
you can try lua which uses only 1 thread
and with luajit you can make it pretty fast, even faster than python
(and its simple and similar to python too)
I'm pretty sure people have already posted rust bruteforcers for this
oh that also works
rust is
as fast
as C
which is about the fastest language iirc
so like yeah
but i still think that my theory could be a promising lead possibly
I think the best thing we can do is to guess possible combinations of the key and try to find what left with BF.
ehhhh
i feel like trying to solve it
the intended way
might work
consider this
we might be overthinking it
we have like 30 possible ways and each another 5 or 10
good luck
the only reason we didnt solved it yet is because of this
too much possible things that can be the key
do we need to use fib? yes? so all the calculations need to be with fib, ok. How we need to use the fib?
you need try all possible versions of this
bruteforcing a AES key is insanely hard anyway
Yess
I think most people that were active just gave up lol
is it possible that there isnt a AES key encrypting this?
possibly this is a whole
another language?
because, it tripped off one of the base 64 decoders i used
saying
"invalid UTF-8 keys"
because
IT HAS invalid UTF-8 keys
this thing is not exactly fully UTF-8!!
meaning its either A. another language OR encrypted to the point where it spits out non-UTF-8 keys
sure. the main reason for AES is the entropy + size of the decoded base64 being multiple of 64 byte blocks
welp that is a pretty damn convincing reason
also if you encrypt a phone number with AES it looks kinda like the base64 in the study sms library.
you need to make a subprocess
with only one process you can only use one core
yea I kinda moved to other languages now
yeah then AES is how everything's encrypted here
what does a 128 bit AES key usually look like
it's just a phone number doesn't have enough so when you encode it with a 16 character key to base64 it turned to something similar like in the study one
I think anything
I guess anything on your keyboard
it can be literally any squence of 128 bit. doesn't have to be printable characters
then its kinda impossible to decrypt it here y'see?
this is where you need to solve the puzzle
yeah thats the trickest part
it could very well be
that the decryption key
is just numbers
or even letters
that's why AES is considered a secure encryption algorithm 😉 unless you can make assumptions that limit the possible inputs you will not be able to bruteforce it before the universe ends
I bet in the near future it'll be full of holes
I just hope we get some more hints. The way it is now is just to inconclusive
new discoveries:
572943 actually matters
we now know the meaning behind "another 9" in that one lyric
we also noww know its quite literally adding another 9
Thats already been discovered from a long time you can check the docs
What's arg
Yes people did try brute force with 17 as the two first and 24 as the two last but i don't remember if they use ecb and i don't think they used any IVs or padding
Also correct me if im wrong but some website pads their keys if you enter one smaller than 16 no ?
hey i was thinking what if the start with x end with y is to decode numbers but ive been away so excuse me if youve already solved it, also the number string could be the first time a number appears is one of the b64 numbers if that makes sense, but my code isnt working so... (im not up-to-date, so excuse me if youve kinda solved most of i)
i don't thing the number II video was that much solved so you might find some stuff for sure
clue?
that the twitter account we noted earlier?
at first glance this isn't @_neurosama
it isnt @_neurosama, because they arent suspended
got it, random account then
probably someone trying to sabotage, or just be creepy.
yes, random account
aye, that topic was just specifically assuming a 16 numeric key. I've been trying null padding and concating the passphrase to itself till it was long enough for other wordlists myself. Bar that I could only realistically see md5
Might be a really old account that got hacked and the hacker mightve sent racial slurs or something
i am proposing to nuke "MAN#3701 take on the lyrics (instructions for block cipher)" from numbers thread library.
the sheer complexity it would take to make a symmetrically encrypted text with "and" encryption is too great to reasonably consider for even just 1 round of encryption
also i would like to kindly ask if anyone has a convenient 1040 byte string of sensible data to donate for analysing its encrypted entropy
i am pretty sure it would be possible to reverse engineer almost the entirety of the original key used for "and" encryption, and the keys for other steps from it as well, but i am also pretty sure that you would just get 128 bits of "1"s
not sure how serious that question is, but:
If I need like up to 256 bytes of medium-entropy data, I usually just let my brain play LLM and type some random sentences about what I'm doing, thinking, seeing, etc.
If I need much more than that, I sometimes use something like Alice in Wonderland or other books (the projekt gutenberg website is pretty neat).
resonable, I forfeit
You can easily reach 7.9 entropy by just compressing some data instead of encrypting it, so if you're trying to disprove that the high entropy mean encryption that's already known. Try analysing the entropy of a compressed image.
Wouldn't a compressed image still have magic bytes?
I think it should, either an image header or a header indicating compression. If it really was compression, and the headers were intentionally stripped away, I think it'll be too unreasonable for a puzzle. There are so many compression schemes out there
Agreed. I'd look into raw headerless compression if we had direct indicator from the ARG that we're looking for compressed data. It's the same reason I'm skeptical about trying to decrypt the data with a specific algorithm like AES. There are just too many options.
I might look into libraries/stack overflow questions related to python and cryptography since I feel like there might be something there
(to try and decrypt the data)
Sounds like a plan. I get the feeling we should be looking for a way to determine what we're even dealing with. Like how Bit recognized that the frame of garbage signs might be malbolge code
okay so I wrote a program that (quite naively) generates some numbers based on the lyrics.
I didn't include the more complex interpretations of some lines yet.
It generated about 1100 number sequences, but only 75 of those were 16 digits long.
only one of that did not end up with a bad decrypt (assumed IV = nulls), but of course it's just a bunch of gibberish
@shell heron has leveled up! (1 ➜ 2)
the one non-bad decrypt was with 1789901481413904 btw
hm, entropy is 7.79[...]
I guess I gotta implement the less simple stuff
no, this isn't what i am trying.
i am trying to get average data entropy for all (some) data obfuscation methods and plug the values into markov's inequality to get the probability for data with the exact entropy as the strings we have from the method.
this would obviously mean that it would likely give more than 75% chance to data being not being messed with at all, but the point is to look for comparatively most probable approach rather than simply "likely" approach
refer to this message by Thanatos about minute differences in entropy #1112401279680008242 message
this is exactly what i am trying to do, using probability theory to cheat and find likely obfuscation method
In regard to the compression talk earlier offzip's pretty good at scrubbing for raw headerless DEFLATE streams, but nothing there. It would also be strange since all 3 ciphertexts were %16
Can you send the full 1100 wordlist?
I added some instruction variants, so that's the second version, which is slightly bigger (6400 numbers)
I can also upload the code if you're interested.
it's just not written with good readability in mind...
What programming language?
did you include any fibonacci or golden ratio stuff in this sequence generator or
JavaScript (Node.js, i.e. server-side JS)
nope. no fibonacci shenanigans yet
I wonder if this code needs content warnings
like
"*Beware: * r e c u r s i o n"
just thought of this and want to throw this out there, but what if flipping the numbers backward means literally flipping them backward, and then match them with letters (ex: 3 → E, 6 → d). I've messed around with it and have gotten some results that are 16 bytes so it might work as the AES key/IV.
Example: by treating the "add the line" part as a line break and using "Add the numbers to 4" I got the number
1712478247604
58
↓
lclspcBspcdop
sB
This works as the key/IV when converted to hex, though I still don't know how the ABCDEFG part comes into play and there is still a bit of guessing as to what letter each number translates too
Probably not right but at this point I feel like everyone's a bit desperate
dead chat.
how about a vote for keeping or letting it die. i was thinking it could get nuked by discord automatically but i guess it won't
We could just let it die. I mean, main thread isn't moving very fast now. That way we could just pick it up again if main becomes too busy
yeah thats weird it should get nuked after a week of inactivity iirc
dont lock this yet tho
so what are those b's 
hex maybe?
I think the numbers on the right with the distortion means that it's not the actual result, the biggest clue is what's at the top
but then we only see bs
Possible but it’s only bs which is weird
yh
its instructions on what to do
Maybe something like modhex? Both that, but similar
It says that we should take all the "secret" numbers from the number 2 video, and run the algorithm from the numbers 1 video on them
yh
Though also, where is initial_number even used?
initial_number = 2 is a parameter used for that (idk what parameters the algorithm takes so im guessing thats what its for)
for the algorithm from 1 im guessing
The function calls are before hand
but im not too familiar with the arg atm
the numbers 1 video itself says "start with number 2", this is just confirming that 2 is some initial value (IV) for the algorithm
oh god what if we need to find those exact keys and note down what b is substituting
Yeah, Im aware of that, it’s just the way it’s formatted feels off to me
yh, that could be possible
Would be very nice of vedal to give us a way to confirm our results that way
also, what are those lines above/between letters for?
some values are also completely missing, not replaced with b
Those b's look llike musical notes to me. God, I can't read.
They kinda remind me of musical notation
so iv is just ...0000000000000010 
we need to do a reverse I guess
bs could stand for bytes in python. Like b'123' for example
secret numbers from numbers 1 to do something with numbers 2 to get the numbers we need
Could be an IV for the numbers 1 algorithm rather than AES itself
I guess maybe the numbers on the right side are the result of applying numbers of numbers 1 to the array of numbers 2
what does that even mean
Yeah how would that work
Wouldn’t that be more likely to be secret_number?
It would be like explaining an entire encryption scheme with substitution stages and whatnot through a music video
Do we have numbers given from Numbers 1 besides the lyrics?
the instructions from numbers 1
there's a specific "secret number" to apply and mix around with numbers 2
It's much more likely to me that the left column shows the parameters and the right shows the heavily distorted output
from a programation stand point applying cipher.number1(secret) to cipher.number2.array() doesn't really make sense to me
what is cypher here ? a superclass ? does number2.array() return an array of object which have the method number1(secret) ? do we have an interface here somewhere ?
these pairs of numbers and stuff id strange
since generating keys is called only once i guess it's call by cipher, then we call on each object the numbers1(secret)
they return a pair of number with results, some contains letters some don't, we never got letters from our attempts with number1
i guess we do see a lot og 24 at the end so it clarify the add the numbers 2 4 (lmao to 4 believers)
tbh the "b" might be corrupted data just like the lines or weird characters
wait, so numbers 1 is indeed an encyption algorithm instructions
nooooooooooooooooooooooooooooooo
i dont want to implement and encryptions 
maybe the key from numbers 1 include numbers and the letters "abcdefg"
this is why in generated keys we see "b"
cipher is an implementation of the algorithm that's hidden from us
Yeah, yeah. But for a initial number for numbers one algorithm wouldn’t it be secret_number as it’s put as a parameter in the pseudocode?
it's like that in pycryptodrome, you create cipher with an algorithm, then you call that cipher's methods
Yeah, and as I’ve said from programming standpoint defining initial_number after encrypting doesn’t make much sense
from what i can see the distortion can be either :
- "b"
- number erased
- weird artefacts
so we can gather that this algorithm do return in a range of 17...24
You're seeing the printf output, not the psuedocode, the order of the lines don't reflect the order of operation
Oh fair brain go brrr
Study js confused me
It's much more likely the cipher is being run during the "Generating keys..." line
If we're running by Numbers I being instructions for an encryption algorithm, initial number should be the inital state. Then the keys we see below are probably what we should aim to get?
All speculation, probably wrong
problem is keyword "keys"
maybe we need to go through numbers 2 description in 128 bit parts applying it to cipher one by one
personnaly i tried doing the algorithm from number 1 starting with the numbers of days as starting number (might not have done the algorithm correctly) but i got no result with it
i speculate it's because of distortion
This sounds like a good idea
if you look at the distortions i listed every result are in range of 17...24
did not see anyone saying this and I'm probably wrong:
maybe "public static void" generating things are study-sama? attempt to solve something (the descs?) with number1 algoritm
so we can check if we have the good algorithm from number 1 with number2 numbers and try to find the starting number somehow
okay
i have big theories
the symbols may have their meanings
for the weird music note thingy, you can see it appears mostly at the start
yes
like x7
etc
that can be a 1
then theres a little _ but at the top
mostly at the end
which can be a 4
the keys that have that, are the ones we should focus on first
there is also _ at the start which replace a 7 tho
also artefacts seems to replace sevral numbers
what about when the line is above a number instead of replacing it
the fact that most results are 17590...24 and 17589....24 is intersting tho
we should do those first
our main priority is finding out how to turn those into 16 bit keys
the "b" could be 11
hex
which would invalidate 4156
i don't think this is substitution like that
there is so many numbers being replaced by each one
4913: 175b068887b24
4156: b7189938327924
i'd rather we focus on the numbers that are readable on one group
17 590 24 are repeating int he first 2 group
even third
I ain't reading all this but I'm sure that "add another line" means add another "1"
the 1 would go through multiplication and reversing
I did the thing backwards with one of the examples
I ended up with the correct number
the b's are placeholders, just like the musical symbols
"correct" number?
weirdly enough it always ends up with a length of 15
I'll try to type it out
because they each have at least one distortion so can't be 16
175110688871124
117189938327924
distortion can change more than one number
oh hey you guys moved here, time to lurk
It says 1 is 256 bit
binary
So what do we do with this?
Nothing it's desc from num 2
capital letter is replaced with ?
Is 26 a reference to "matching all the letters"?
Or
doesn't look anything like Y
The Y is in front of the Z
Oh wait i see it ignore-
It can means that x/26Yz is not part of the code.
It's jusut really hard to see "Y" in front of the weird blurb hovering in the same area
In study it says xyz
I thought the Y is 8
assuming we get a key/secret number, we still have to know the following to verify:
- What is the cipher?
- How exactly to "apply" one to the other?
So we are technically working with 3 ciphers/derivations here, the one to get the key, the one to get ciphers.numbers1 & ciphers.numbers2, and the one to apply both of them together
It's straight up the description from numbers with strange artifacts that mean nothing
the cipher is numbers 2
the decryption of numbers 2 is the key for numbers 1
What the lyrics of numbers 2 again
then from there we do the soundcloud and studies
Take between x and y and odd one out?
Numbers that we can see in the new video
No I mean the xy thing
Start from X. End with Y. Remove XY + odd one out
Odd one can be z
So we get /26
Decide to 26?
Devide*
Probably, the issue is with what exactly those encryption/key derivation schemes are. Are we expecting the same scheme for all decryption/encryption or will they be different? If different, how?
Are we postulating that the numbers videos themselves are the respective schemes?
oh damn it
Hmmm, divide the numbers from Numbers2 by 26 before inputting it into Numbers1?
4156 ?7?8993832792?
?7?8993832792?
?8993832792? ("seventeen is first": remove 17 from the front)
?899383279 ("add two, four": remove 2 and 4 from end)
?899383279 ("multiply by 9": divide by 9. this is where the first number is important. there will be two possible values that divide evenly and one of those will be ruled out later. for now, just assume 5 as the first number.)
-> 5899383279 / 9 = 655487031
655487031
655487021 ("make the two a three": replace 3 with 2)
120784556 ("flip the numbers backwards": reverse the order of the digits)
12078455 ("add another six": remove the 6. this also lets us know that "another" doesn't require that digit to be already present in the number)
2415691 ("multiply by five": divide by 5)
now the next instruction is "add another nine, add another line" and the numbers at the end are 9 and 1, so "line" must refer to 1
24156 (removed 9 and 1)
4156 ("start with two": remove the 2 from the start)
AND THIS LAST NUMBER MATCHES THE FIRST NUMBER
fuck yea, it worked a second time
If we take from x to y it's /26 and we left with z, which is probably the odd one. So we left with /26 if we assume that x/26Yz is part of it.
that does make sense
mate
didnt you just see it
its the start of the cipher
its not a clue
thing is, can we get the full number this way?
so this is numbers1 cipher
ok, we have a numbers 1 cipher, what now
what else to plug into it
the solution to Numbers should be 1759032572147924
You have unlocked new role
if i didn't make a mistake
okay
cook more
im liking it
we need a second key now
@shell heron can you do 4913
just asking, do it work with others numbers like 201 or is 4156 the only one you tried
idk, haven't tried it out yet
I'd code it. I don't like doing things like this manually
nothing for any strings
How do you get this? 5899383279 / 5 = 655487031 wouldn't you get 5899383279 / 5 = 1179876655.8? Maybe you made a typo?
Based on the 128bit clue I suspect we won't get plaintext just yet
@tired wind has leveled up! (9 ➜ 10)
a = '2' + a
a = a + '91'
a = str(int(a)*5)
a = a[::-1]
a = a.replace('2', '3')
a = str(int(a) * 9)
a = a + '24'
a = '17' + a
print(a)```
code? fact check plz
yes
Found it, the typo is / 5, should be / 9
are you running it with the list we got ?
201 - 175031009924
1321 - 1750315940924
does this look correct?
forgot to add the 6
yea sorry about that typo
was writing too fast
a +"6" before flip
1321 - 17590315940924
does this look more correct
another small typo: replace 2 with 2
yes
okay
we need 2 keys
pfcpmf can you try 130 , 129 , 1432 please
i done python for it and it work for 4156, 906, and probably 716

Do they all produce 16 charas
once we have 2 16bit keys, get the numbers 2 description and pass it thru AES CBC, and try both keys for iv and key
a = '201'
a = '2' + a
a = a + '9'
a = str(int(a)*5)
a = a + '6'
a = a[::-1]
a = a.replace('2', '3')
a = str(int(a) * 9)
a = a + '24'
a = '17' + a
print(a)
This gets much closer to the distorted results and is a simpler interpretation of the lyrics
it should give us a 32 bit key which is then used to decode the numbers 1 description with AES ECB
thing is
numbers 1 has [BINARY] in it
so we may be looking for a bin file
Yes
or a binary number
the list
(1321, '17590315940924')
(5831, '17590356737924')
(723, '1759032467924')
(743, '1759032557924')
(4913, '17590368887924')
(879, '1759039406924')
(875, '1759037606924')
(2145, '17590343309924')
(716, '1758993677924')
(906, '1758989186924')
(4156, '17589938327924')```
Seems to either be 16 or 18
wait
Seems distinctly to be 2 sets
201 1759031009924
1321 17590315940924
5831 17590356737924
723 1759032467924
743 1759032557924
4913 17590368887924
879 1759039406924
875 1759037606924
2145 17590343309924
716 1758993677924
906 1758989186924
4156 17589938327924
I think it checks out
can you say which ones are 16 bits
wait am i stupid, none are 16 symbols
Combine the fronts
572943
257294391
12864719556
65591746831
1759032572147924
Prepend 201 to 175..., 1321 to 175... etc
('723', '7231759032467924')
('743', '7431759032557924')
('879', '8791759039406924')
('875', '8751759037606924')
('716', '7161758993677924')
('906', '9061758989186924')```
only 16 symbols
yes that was said earlier
sometimes 1759 and 1758
okay
none of the numbers from the new video are 16 bits, but if you do the same with the numbers from the Numbers video (5-7-2-9-4-3), you get one that is 16 bits
I posted it earlier
how many possibilites are there to calculate
all of them are both tested for iv and key
wair
try the last 2
they're the odd ones
aes, 16 bits, cbc using numbers 2 desc cipher
use both as iv and key
Pfcpmf and your almighty tool plz
I'm certain that the numbers used in today's video are only there to show us how the 'cipher' works
why are we focusing on the examples when we figured out how to used the numbers 1 algorythm ?
thanks god someone that speak sense
I agree with this
exactly
we need to apply it to the numbers 2 numbers
no
that's what we already did
we need to apply it to number 1
572943?
16 bits?
bro
nothing for any of the those numbers, but that's with zeroed iv
I mean the screenshot explicitly says they're "keys"
👨🍳 
we literally need to use them to decode

we already used them to figure out the algorithm
now we're back to numbers 1 but we actually know what we are doing
congrats we figured out the algorithm
crazy idea:
we know the cipher but we need a starting number to supposively find a key
maybe use the cipher on Fibonacci Sequence until we get a 256 bits solution ?
this has 16 characters though
to decode the aes!
whats taking so long testing the numbers then?
you applying algorithms to neuro's forehead?
we need a starting numbers that is given by the numbers 1 video
no
oh god
we start with numbers 2
AES has very specific key lengths, need to find a way to construct either 128-bit or 256-bit keys out of the results
🤦
if anyone wants to implement it themselves:
//[number] is the input, [n] is the output
n = "2" + number;
n += "9";
n += "1";
n *= 5;
n += "6";
n = n.split('').reverse().join('');
n = n.replaceAll('2', '3');
n *= 9;
n += "2";
n += "4";
n = "17" + n;
this is probably close enough to pseudocode
pls darkeew just breath a sec
where can we get a 32 bit key
Good idea, but I believe the 128-bit clue suggests we should get two 128 bit blocks. I could be misinterpreting tho
We did it in python before
a = '201'
a = '2' + a
a = a + '9'
a = str(int(a)*5)
a = a + '6'
a = a[::-1]
a = a.replace('2', '3')
a = str(int(a) * 9)
a = a + '24'
a = '17' + a
print(a)
we have an algorythm that take a number and return a key, so in the numbers 1 video we need to figure out the number this algorithm takes
there is no wrong we just don't have the number to give the algorythm
only 10^6 possibilities to bruteforce

no
works on mobile https://gchq.github.io/CyberChef/
The Cyber Swiss Army Knife - a web app for encryption, encoding, compression and data analysis
test where
we need the first line a = [number]
this unknow number need to be found somewhere on the first video
i already did. or you mean with ivs?
already did that
the whole point of these additional hint were to help us with the first video, we didn't know how to use the lyrics now we do, but we need a number to use the lyrics on
wait
the thing
the photo from the newest video
check the first line
why look at the newest videos
I think we're using it on the right numbers, we need to construct keys from them
i don't think so we using it on examples we were given
guys
we have to remenber at the start we only had the numbers 1 video so the ARG can be solved only with the first video
using 1759032572147924 as a key for both video descriptions results in bad decrypts
* with IV of all zeroes
no
if we keep forgetting the first video and focusing on the new ones we just gonna keep being stuck
That's not true, tons of ARGs that can't be solved with just the first clue. In fact it's often done intentionally so that the ARG isn't solved too quickly
I did Key and IV as "1759032572147924" > CFB > Input Raw > Output > HEX and with the input being the Numbers 2 gave me a wall of numbers and letters
okay but do you agree that all the new video are clues to help us understand the first video
?
no screenshot because embed permissions
To help us understand the first two I'd say yeah
I (think?) I agree with Amarok. We got the cipher.numbers1() part of cipher.numbers1(secret_number). Now we need to find what that secret number is...
i mean yea study is just a whole bag of stuff too i agree
given all the golden ratio references could the secret number be 1.618
Can anyone confirm if this output means something?
we didn't explore the golden ratio that much so
secret_number is just a parameter for a function, vedal is a programmer, the first line in the screenshot clearly says that the secret numbers are in the numbers2 video/array
Send screenshot to my dm
also from the lyrics it seem this secret number as a 9 and a 1 and when multiply by 5 it has a 2.
"add another 9 add another line"
Your output is hex, the wall of text and numbers is just garbage represented as hexidecimal numbers
I'm gonna go to bed; it's way too late here
good luck guys o7
oh, ok
this video is literally all the clues we need
spectogram said numbers 2 was 128bit and numbers one is 256 bits
well
i guarantee this wont be the end of the arg even if we solve it
pretty sure the soundcloud isnt just for giving clues..
stop wildly speculating Darkeew, this channel isn't about that
and the study video number
need to focus the conversation in this thread on the task at hand
but yeah I agree that "1st = 256-bit [BINARY] 2nd = 128-bit" is a clue to constructing the key
im speculating here because most of you dont actually check the topic at hand in the other thread





