It's not an Error to be honset but I want to receive an url link for the file
#I just keep getting that damn error
fresh delta
excuse me. but i don't understand the problem or the context of problem, can you explain me?
vivid crown
Can you show us your code?
lofty forge
i just want to make a function that get the file url from the bucket in appwrite
fresh delta
on a function?
lofty forge
that is what I get when I use get_file_view() function
lofty forge
on a function?
yah
lofty forge
that is what I get when I use get_file_view() function
I got it in binary form that is the problem
fresh delta
have you the id of image?
or file
i you have the file id, maybe you can create a specific string with the basic pattern of url
on cloud it should be cloud.appwrite.io/v1/storage/buckets/<bucketId>/files/<fileId>/view?project=<projectId>&mode=admin
lofty forge
on cloud it should be cloud.appwrite.io/v1/storage/buckets/<bucketId>/files/<fil...
ok
I'll try it
fresh delta
i don't know if this is a correct solution, maybe you can try, but stay attention with the roles on bucket, otherwise the file can be accessible to everyone
fresh delta
lofty forge
even the download, it get the same result
fresh delta
ok but what should you do with the url?
lofty forge
I'll pass the parameters to the url
I need to send that url to the front-end developer
so he can handle it
vivid crown
You have to use getFile and use the metadata to create the URL
https://appwrite.io/docs/references/cloud/client-web/storage#getFile
getFileDownload returns the file content, same as getFilePreview
lofty forge
I could not find it