#latex
1 messages · Page 4 of 1
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(y = mx + c)
adjectivenoun
(\frac{160}{\pi + 4})
adjectivenoun
skySLAYER
EminemSomething
skySLAYER
$X= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
Syphrix7
,list
Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.
If you still have questions, talk to our friendly support team here.
Render LaTeX code and configure rendering options.
tex: Render LaTeX code.
ctan: Searches the ctan
texdoc: Searches the texdoc
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texconfig: View or modify your personal LaTeX rendering options.
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,tex balls
STOOPUD MAN
sheeesh
Dude1
$$/3*4/$$
saucyxavier
,tex cock and balls
Bloorbg
heh
$\text{Suck Deez Nuts}$
skySLAYER
,tex ligma
! Альвувки
greenfalcon
,tex chill
DageniusDaren
,tex out
DageniusDaren
,tex please
DageniusDaren
,tex thanks
DageniusDaren
zephr0n
,Tex suck Deez nuts
Codeblocks found, but no LaTeX codeblocks!
Please write your codeblocks as follows.
```tex
code
```
zephr0n
,tex weirdo
Rider
.
.
,tex lol
anonymouseeee8080
,tex stop
DageniusDaren
,tex s= ut + 1/2 at^2
DageniusDaren
s= ut + 1/2 at^2
```Compilation error:```! Missing $ inserted.
<inserted text>
$
l.57 s= ut + 1/2 at^
2
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.
LaTeX Font Info: Calculating math sizes for size <14> on input line 57.
LaTeX Font Info: Trying to load font information for U+msa on input line 57.```

greenfalcon
,tex xue hua piao piao/bei feng xiao xiao
Sheeeesh
$X= \frac{dababy sussy amogus school}{Xue hua piao piao bei feng xiao xiao}$
Sheeeesh
$\frac {when z impooster is sus}{say invented without n}$
$\frac{sus}{sus}=\frac{sus}{sus}$
Sheeeesh
,tex erase
DageniusDaren
,tex xD
Control X
$$\frac{Among}{Us} \neq \frac{Imposter}{Pasta} \neq Big + Brain$$
Control X
,help
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,tex Physics
DageniusDaren
,tex 
DageniusDaren
,tex
+
DageniusDaren
,tex
+
+
DageniusDaren
,tex idk what to do here
_cfspring
єאץɭเא
,tex daddy chill
! Альвувки
,tex no homo
DageniusDaren
,tex Znotes
VeteranGhostRaider🇮🇳
,tex is
! Альвувки
,tex good
DageniusDaren
,tex !
𝕵𝖚𝖉𝖊 𝕯𝖚𝖆𝖗𝖙𝖊 ඞ
,tex better than
! Альвувки
,tex minimum
EYW Gaming
Codeblocks found, but no LaTeX codeblocks!
Please write your codeblocks as follows.
```tex
code
```
єאץɭเא
\frac{1}{2}
\\ hello
Pt
\frac{1}{2}
\\ hello
```Compilation error:```! Missing $ inserted.
<inserted text>
$
l.57 \frac{1}{2}
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.
LaTeX Font Info: Calculating math sizes for size <14> on input line 57.
LaTeX Font Info: Trying to load font information for U+msa on input line 57.```
,tex 
DageniusDaren
$BC=AD\
\
\
For(BC),B(-5,8)\
y=mx+C, \quad y=8, m=1, x=-5\
8=1(-5)+C, find(C)\
8+5=C\
C=13\
y=x+13\
\
\
\
\vec{BC}=\vec{AD}
\
\vec{BC}=\left(\begin{array}{c} -a\
-b\
\end{array}\right)\
\
\vec{BC}=\sqrt{(-a)^2+(-b)^2)}=\sqrt{8}\
a^2+b^2=8\
\
\
B(-5,8)\
C(X,Y)=C(-5-a, 8-b)\
X=-5-a\
Y=8-b|
BC; Y=X+13\
8-b=-5-a+13\
a-b=0\
\
\
a-b=0\
b=a\
a^2+b^2=8\
a^2+(a)^2=8\
2a^2=8\
\frac{2a^2}{2}=\frac{8}{2}\
\
\sqrt{a^2}=\sqrt{4}\
a=2\
\
a=b\
2=b\
\
\
A(7, 2)\
D=(X, Y)=D(7-a, 2-b)\
X=7-a\
X=7-2\
X=5\
\
Y=2-b\
Y=2-2\
Y=0\
\
\
\
D(5,0)$
skySLAYER
$A=\sqrt{s(s-a)(s-b)(s-c)}\
Where:s=\frac{a+b+c}{2}\$
skySLAYER
,tex y=mx+C
y=mx+c
,tex A bo'l Ou' Wotah.
EYW Gaming
💀
,help
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,help cmd
You really shouldn't take it literally :upside_down:. Please type ,help ping, for example!
The full command list may be found using ,list.
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
,list
Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.
If you still have questions, talk to our friendly support team here.
Render LaTeX code and configure rendering options.
tex: Render LaTeX code.
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,tex d/dx (x) = 1
EminemSomething
Ehh
Pt
GamingMatrixes
pgf
\begin{align*}
\text{assume}\enspace A \Longrightarrow (-4; 1)\
B \Longrightarrow (2; \enspace 4) \
C \Longrightarrow (6; -2)
\end{align*}
\noindent
\begin{tabular}{rl}
&\overline{AB} = \sqrt{45} \
&\overline{AC} = \sqrt{109} \
&\overline{BC} = \sqrt{52}
\end{tabular}
adjectivenoun
\begin{align*}
\text{assume}\enspace A \Longrightarrow (-4; 1)\\
B \Longrightarrow (2; \enspace 4) \\
C \Longrightarrow (6; -2)
\end{align*}
\noindent
\begin{tabular}{rl}
&\overline{AB} = \sqrt{45} \\
&\overline{AC} = \sqrt{109} \\
&\overline{BC} = \sqrt{52}
\end{tabular}
```Compilation error:```! Paragraph ended before \align* was complete.
<to be read again>
\par
l.61
I suspect you've forgotten a `}', causing me to apply this
control sequence to too much text. How can we recover?
My plan is to forget the whole thing and hope for the best.```
Sheeeeeeeeeeeeeeeeeeeeeeeeeeeesh
\begin{align*}
\text{assume}\enspace A \Longrightarrow (-4; 1)\
B \Longrightarrow (2; \enspace 4) \
C \Longrightarrow (6; -2)
\begin{tabular}{rl}
&\overline{AB} = \sqrt{45} \
&\overline{AC} = \sqrt{109} \
&\overline{BC} = \sqrt{52}
\end{tabular}
\end{align*}
adjectivenoun
\begin{align*}
\text{assume}\enspace A \Longrightarrow (-4; 1)\\
B \Longrightarrow (2; \enspace 4) \\
C \Longrightarrow (6; -2)
\begin{tabular}{rl}
&\overline{AB} = \sqrt{45} \\
&\overline{AC} = \sqrt{109} \\
&\overline{BC} = \sqrt{52}
\end{tabular}
\end{align*}
```Compilation error:```! Paragraph ended before \align* was complete.
<to be read again>
\par
l.61
I suspect you've forgotten a `}', causing me to apply this
control sequence to too much text. How can we recover?
My plan is to forget the whole thing and hope for the best.```
Sheeeeeeeeeeeeeeeeeeeeeeeeeeeesh
notAnxiety
IsmailFateen
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex f my life
R45H1F
,tex better sleep than study
R45H1F
notAnxiety
,tex boorgir
,tex sosig
𝕵𝖚𝖉𝖊 𝕯𝖚𝖆𝖗𝖙𝖊 ඞ
,tex and bebsi
! Альвувки
єאץɭเא
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
darkcurtains
,tex no
zephron
Neutrino
,tex y= ax^2 + bx + c
blu
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,Tex ax^2 + bx + c = 0
Codeblocks found, but no LaTeX codeblocks!
Please write your codeblocks as follows.
```tex
code
```
,tex $\text{Taylor series expansion for } f(x) \ f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x - a)^n \ \text{Maclaurin Series is Taylor series, where } a = 0. \text{Expansion:} \ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \cdots + \frac{f^{(n)}(0)}{n!}x^n \\ \text{sin}(0) = 0, \text{cos}(0) = 1 \ \frac{d}{dx} \text{sin}(x) = \text{cos}(x), \frac{d}{dx} \text{cos}(x) = -\text{sin}(x) \ \text{Maclaurin of sin}(x)\text{:} \ \text{sin}(x) = \text{sin}(0) + \text{cos}(0)x + \frac{-\text{sin}(0)}{2!}x^2 + \frac{-\text{cos}(0)}{3!}x^3 + \frac{\text{sin}(0)}{4!}x^4 + \cdots \ \text{sin}(x) = 0 + 1x + \frac{0}{2!}x^2 + \frac{-1}{3!}x^3 + \frac{0}{4!}x^4 + \frac{1}{5!}x^5 + \cdots \ \text{sin}(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots$
,tex $
{\huge \texttt{GIMME FREE NITRO PLZ BCUZ I WANT + I BROKE}}
$
Algortex
,tex $\texttt{SUS}$
Algortex
,tex $
\texttt{Please react with flag of your country}
$
Algortex
,tex $\int{u(x)v'(x)} dx = u(x)v(x) - \int{u'(x)v(x)} dx$
Algortex
,tex help
Please use ,help tex for command help.
'-'
pgf
skySLAYER
$Y=\left(\frac{4500\sqrt{3}}{49}\right)\sqrt{3}-\frac{49}{9000}\cdot \left(\frac{4500\sqrt{3}}{49}\right)^2\
\
\
Y=\frac{13500}{49}-\frac{6750}{49}\
\
Y=\frac{6750}{49}\
\
\
\therefore Maximum\quad Height=\frac{6750}{49}$
skySLAYER
$y=x\sqrt{3}-\frac{49}{9000}x^2$
skySLAYER
\frac{\sqrt{3}}{2× - \frac{49}{9000}}\right)
$-\frac{49}{9000} \left(x+\frac{\sqrt{3}}{2× - \frac{49}{9000}}\right)$
$ax^2-bx+c=0\
\
X=\frac{b\pm \sqrt{b^2 - 4ac}}{2a}$
skySLAYER
$ax^2+bx+c=0\
\
X_2=\frac{-b\pm \sqrt{b^2 - 4ac}}{2a}$
skySLAYER
$\left(\frac{b}{2a}\pm \frac{\sqrt{b^2 - 4ac}}{2a}\right) -\left(\frac{-b}{2a}\pm \frac{\sqrt{b^2 - 4ac}}{2a}\right)=Y\
\
\
\frac{b}{2a}+\frac{b}{2a}=Y\
\
\
Y=\frac{2b}{2a}\
\
\
Y=\frac{b}{a}\$
Therefore the solutions of ax²-bx+c are an increase of b/a from the solutions of ax²+bx+c
skySLAYER
,tex big brain 🧠
kortuvor
,tex \texttt{Please help me with YOLOv5 Object Detection}
Algortex
,tex \texttt{I'm too ceebs to build an entire model}
Algortex
,tex \text{sus}
Algortex
,help
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
,tex \text{test}
Alcoholic
,tex 7/8
Alcoholic
,tex \LaTeX{}
Alcoholic
$\frac{1}{4}$
Alcoholic
Alcoholic
$x^{y^{z}}$
Alcoholic
IsmailFateen
,tex \text{const SUS = require("SUS");}
Algortex
Yo wasup
good
All g man wbu
no i mean last month temp was over 40C now less than 30C due to rain
Where u live if u don't mind me asking
,tex whatsup
zephr0n
there is curently very bad monsoon flooding in Bangladesh
good
Mian muneeb temp gonna go back to 40+ in few days
yeahh
there was very small monsoon last few years
$(3)\
36a+6(3)+c=6\
36a+18+c=6\
c=-12-36a\
\
(2)=(3)\
3-4a=-12-36a\
32a=-15
\
a=-\frac{15}{32}\
\
(2)\
c=3-4\left(-\frac{15}{32}\right)\
\
c=3+\frac{15}{8}\
\
c=\frac{39}{8}\
\
\
\
\therefore a=–\frac{15}{32}\
\
\therefore b=3\
\
\therefore c=\frac{39}{8}$
what is this
skySLAYER
ok understood
$(3)\
36a+6(3)+c=6\
36a+18+c=6\
c=-12-36a\
\
(2)=(3)\
3-4a=-12-36a\
32a=-15
\
a=-\frac{15}{32}\
\
(2)\
c=3-4\left(-\frac{15}{32}\right)\
\
c=3+\frac{15}{8}\
\
c=\frac{39}{8}\
\
\
\
\therefore a=–\frac{15}{32}\
\
\therefore b=3\
\
\therefore c=\frac{39}{8}$
skySLAYER
$(3)\\
36a+6(3)+c=6\\
36a+18+c=6\\
c=-12-36a\\
\\
(2)=(3)\\
3-4a=-12-36a\\
32a=-15
\\
a=-\frac{15}{32}\\
\\
(2)\\
c=3-4\left(-\frac{15}{32}\right)\\
\\
c=3+\frac{15}{8}\\
\\
c=\frac{39}{8}\\
\\
\\
\\
\therefore a=–\frac{15}{32}\\
\\
\therefore b=3\\
\\
\therefore c=\frac{39}{8}$
$(3)\
36a+6(3)+c=5\
36a+18+c=5\
c=-13-36a\
\
(2)=(3)\
3-4a=-13-36a\
32a=-16
\
a=-\frac{16}{32}=-\frac{1}{2}\
\
(2)\
c=3-4\left(-\frac{1}{2}\right)\
\
c=3+2\
\
c=5\
\
\
\therefore y=5+3x-\frac{1}{2}x^2$
skySLAYER
TechnicAli
$(1)+(2)\
(4a-2b+c)+(4a+2b+c)=-3+9\
2(4a+c)=6\
4a+c=3\hspace{2mm}(4)$
skySLAYER
,tex \text{Sussy amogus}
Algortex
skySLAYER
$36+4x^4=25x^2\
4x^4-25x^2+36=0\
4(x^2)^2-25x^2+36=0\
\
Let\hspace{3mm}x^2=\beta\
4\beta ^2-25\beta +36=0\
4\beta ^2-16\beta -9\beta +36=0\
(4\beta -9)(\beta-4)=0\
\
\beta=4, \frac{9}{4}\
\
\
Since;\
x^2=\beta\
x^2=4\
x^2=\pm 2\
\
\
x^2=\frac{9}{4}\
\
x=\pm \frac{3}{2}\
\
\
\therefore x^2=\pm 2\
\
\therefore x=\pm \frac{3}{2}$
skySLAYER
$x(x^2-4)(-2-(x-3)^2) \leq 0$
$x(x^2-4)(-2-(x-3)^2) \leq 0$
\begin{align*}x(x^2-4)(-2-(x-3)^2) \leq 0
\begin{align*}x(x^2-4)(-2-(x-3)^2) \leq 0\end{align*}
adjectivenoun
@solid oriole help
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
$x(x^2-4)(-2-(x-3)^2) \leq 0 $
$ x(x^2-4)(-2-(x-3)^2) \leq 0 $
( x(x^2-4)(-2-(x-3)^2) \leq 0 )
adjectivenoun
$a_n=a+d(2n-1)\hspace{3mm}(1)\
\
S_n=\left(\frac{a_1+a_n}{2}\right)n\
\
\
\
25th\hspace{2mm}Term = 44.5\
44.5=a_1+24d\hspace{2mm}(1)\
\
\
S_{30}=765\
a_30=a+29d\
\
765=\left(\frac{a_1+a_{30}}{2}\right)30\
\
\
765=\left(\frac{a_1+a_1+29d}{2}\right)30\
\
765=(2a_1+29d)15\
51=2a_1+29d\hspace{2mm}(2)\
\
\
\
Solve\hspace{2mm} (1) \hspace{2mm}and \hspace{2mm}(2)\hspace{2mm} simultaneously:\
44.5=a_1+24d\
51=2a_1+29d\
\
2(44.5=a_1+24d)\
89=2a_1+48d\
\
ELIMINATION:\
89-51=2a_1+48d-(2a_1+29d)\
38=19d\
d=2\
\
44.5=a_1+24(2)\
a_1=-3.5\
\
\
Find\hspace{2mm} a_{16}:\
a_n=-3.5+2(n-1)\
a_{16}=-3.5+2(15)\
a_{16}=26.5\
\
\
\therefore a_{16}=26.5\$
skySLAYER
skySLAYER
,preamble
Akash Kumar
,tex \emph {Pain}
Alcoholic
,tex \text{How are you able to see that}
Algortex
Press on the script like thing and ur code will be gone
But the results will remain
$y=\frac{2(x-5)}{\sqrt{x}+1}\
\
\frac{dy}{dx}=\frac{d}{dx}\left(\frac{(2x-10)}{\sqrt{x+1}}\right)\
\
\
\frac{d}{dx}(2x-10)=2\
\
\frac{d}{dx}(x+1)^{\frac{1}{2}}=\frac{1}{2}(x+1)^{\frac{1}{2}} \cdot \frac{d}{dx}(x+1)=\frac{1}{2}(x+1)^{\frac{-1}{2}}\
\
\
\
\frac{dy}{dx}=\frac{\left((x+1)^{\frac{1}{2}}\cdot 2-(2x-10)\cdot\frac{1}{2}(x+1)^{\frac{-1}{2}} \right)}{((x+1)^{\frac{1}{2}})^2}\
\
\
\frac{dy}{dx}=\frac{\left((x+1)^{\frac{1}{2}}\cdot 2-(2x-10)\cdot\frac{1}{2}(x+1)^{\frac{-1}{2}} \right)}{(x+1)}\
\
\
\frac{dy}{dx}=\frac{\left(2(x+1)^{\frac{1}{2}}-\left(\frac{x-5}{(x+1)^{\frac{1}{2}}}\right)\right)}{(x+1)}\
\
\
\frac{dy}{dx}=\frac{2(x+1)-(x-5)}{(x+1)(x+1)^{\frac{1}{2}}}\
\
\
\frac{dy}{dx}=\frac{x+7}{(x+1)^{\frac{3}{2}}}\
\
\
\
\frac{dy}{dx}=\frac{5}{4}\
\
\
\frac{dy}{dx}=\frac{x+7}{(x+1)^{\frac{3}{2}}}
\
\
\frac{5}{4}=\frac{x+7}{(x+1)^{\frac{3}{2}}}\
\
\
5((x+1)^{\frac{3}{2}}=4(x+7)\
(5\sqrt{(x+1)^3})^2=(4x+28)^2\
25(x+1)^3=16x^2+224x+784\
25x^3+75x^2+75x+25=16x^2+224x+784\
25x^3+59x^2-149x-759=0\
X=3\
\
\
y=\frac{2(x-5)}{\sqrt{x+1}}\
\
\
y=\frac{2(3-5)}{\sqrt{3+1}}\
\
\
y=\frac{-4}{\sqrt{4}}=\frac{-4}{2}
\
y=-2\
\
\
\therefore \hspace{2mm}Coordinates \hspace{2mm}of\hspace{2mm} a\hspace{2mm} point\hspace{2mm} when\hspace{2mm} m=\frac{5}{4}\hspace{2mm} are \hspace{2mm}(3,-2)$
skySLAYER
$y=\frac{2(x-5)}{\sqrt{x}+1}
\frac{dy}{dx}=\frac{d}{dx}\left(\frac{(2x-10)}{\sqrt{x+1}}\right)
\frac{d}{dx}(2x-10)=2
\frac{d}{dx}(x+1)^{\frac{1}{2}}=\frac{1}{2}(x+1)^{\frac{1}{2}} \cdot \frac{d}{dx}(x+1)=\frac{1}{2}(x+1)^{\frac{-1}{2}}
\frac{dy}{dx}=\frac{\left((x+1)^{\frac{1}{2}}\cdot 2-(2x-10)\cdot\frac{1}{2}(x+1)^{\frac{-1}{2}} \right)}{((x+1)^{\frac{1}{2}})^2}
\frac{dy}{dx}=\frac{\left((x+1)^{\frac{1}{2}}\cdot 2-(2x-10)\cdot\frac{1}{2}(x+1)^{\frac{-1}{2}} \right)}{(x+1)}
\frac{dy}{dx}=\frac{\left(2(x+1)^{\frac{1}{2}}-\left(\frac{x-5}{(x+1)^{\frac{1}{2}}}\right)\right)}{(x+1)}
\frac{dy}{dx}=\frac{2(x+1)-(x-5)}{(x+1)(x+1)^{\frac{1}{2}}}
\frac{dy}{dx}=\frac{x+7}{(x+1)^{\frac{3}{2}}}
\frac{dy}{dx}=\frac{5}{4}
\frac{dy}{dx}=\frac{x+7}{(x+1)^{\frac{3}{2}}}
\frac{5}{4}=\frac{x+7}{(x+1)^{\frac{3}{2}}}
5((x+1)^{\frac{3}{2}}=4(x+7)
(5\sqrt{(x+1)^3})^2=(4x+28)^2
25(x+1)^3=16x^2+224x+784
25x^3+75x^2+75x+25=16x^2+224x+784
25x^3+59x^2-149x-759=0
X=3
y=\frac{2(x-5)}{\sqrt{x+1}}
y=\frac{2(3-5)}{\sqrt{3+1}}
y=\frac{-4}{\sqrt{4}}=\frac{-4}{2}
y=-2
\therefore \hspace{2mm}Coordinates \hspace{2mm}of\hspace{2mm} a\hspace{2mm} point\hspace{2mm} when\hspace{2mm} m=\frac{5}{4}\hspace{2mm} are \hspace{2mm}(3,-2)$
Madelyn
LaTeX source sent via direct message.
test
,av @hearty notch
Lol
It's supposed to be double slash while u r typing
But it'll show up as single slash
,av @fluid pawn
ahhh i see
skySLAYER
Like this\\
$y=x+1\\
y-1=x\\
1=x-y$
@vast stump as u can see on the highlighted part above the image
Yee thanks
Gave +1 rep to skySLAYER#2732
Difference Quotient(First Principles):\
$\
f(x)=\frac{4}{1-2x}\
\
\
f(x+h)=\frac{4}{1-2(x+h)}
\
\
f'(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}\
\
=\lim_{h\to 0}\frac{\frac{4}{1-2(x+h)}-\frac{4}{1-2x}}{h}\
\
\
=\lim_{h\to 0}\frac{\frac{4(1-2x)-4(1-2(x+h))}{(1-2(x+h))(1-2x)}}{h}\
\
\
=\lim_{h\to 0}\frac{4-8x-4+8x+8h}{h[(1-2(x+h))(1-2x)]}\
\
\
=\lim_{h\to 0}\frac{8h}{h[(1-2(x+h))(1-2x)]}\
\
\
=\lim_{h\to 0}\frac{8}{(1-2(x+h))(1-2x)}\
\
\
=\lim_{h\to 0}\frac{8}{(1-2(x+0))(1-2x)}=\lim_{h\to 0}\frac{8}{(1-2x)(1-2x)}\
\
\
=\lim_{h\to 0}\frac{8}{(1-2x)^2}\
\
\
\therefore f'(x)=\frac{8}{(1-2x)^2}$
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