First find the derivative of $C_1$ to solve for the Gradient of the tangent:\
$\frac{d}{dx}[x^2-4x+7]=2x-4\$
\
Since x=3:\
$m=2(3)-4\
m=2\
\$
Now solve for y=mx+c using coordinates at $C_1:\$
$y=x^2-4x+7\
y=3^2-4(3)+7\
y=4\
\
y=mx+c\
y-mx=c\
4-2(3)=c\
c=-2\
\
y=2x-2\$
\
Now solve for k by equating the equations of the tangent and $C_2$ together\
$y=2x-2\
y^2=4x+k\
\
(2x-2)^2=4x+k\
4x^2-8x+4=4x+k\
4x^2-12x+4-k=0\
\$
Discriminant =0 as the line is a tangent \
$b^2-4ac=0\
144-4(4[4-k])=0\
144-64+16k=0\
16k=-80\
k=-5\$
\
\
Now we can solve for the coordinates of P using this information:\
$4x^2-12x+4-(-5)=0$\
When $C_2$ and tangent are equal\
\
Solve for X:\
$4x^2-12x+9=0\
(2x-3)^2=0\
2x-3=0\
\
x=\frac{3}{2}\$
\
\
Now solve for y\
$y^2=4x+k....C_2\
\
y^2=4\left(\frac{3}{2}\right)-5\
y^2=6-5\
y^2=1
y=\pm 1\
\
y=2x-2....$ Tangent\
\
$y=2\left(\frac{3}{2}\right)-2
\
y=3-2=1
\
\
\therefore k=-5
\
\therefore P\left(\frac{3}{2}, 1\right)$
#latex
1 messages · Page 1 of 1 (latest)
skySLAYER
(mg\cos{\theta})
adjectivenoun
10(a)\
f(x)=$2x^2$-3, ${ x:x\mathbb{\in R}|x<0}\$
\
f$^{-1}$(x)=$-\sqrt{\frac{x+3}{2}}$, ${ x:x\mathbb{\in R}|x\geq -3}\$
\
\
10(b)\
$f(a)=a\
2a^2-3=a\
2a^2-a-3=0\
(2a-3)(a+1)=0\
\
a=\frac{3}{2}$, $-1$
\
Domain states that x<0;\
$\therefore a=-1$
skySLAYER
skySLAYER
For the second last line where a statement is made
Equation of line PQ;\
\
$\frac{x}{a}-\frac{y}{b}=1\
\
\
y=\frac{xb}{a}-1b\$
\
\
Gradient of line PQ;\
\
$m=\frac{2}{5}\
\
\
m=\frac{b}{a}\
\
\
\frac{b}{a}=\frac{2}{5}
\$
\
\
Length of Line PQ; \
Where: \
$y_1=0\
\
y_2=\frac{x_2b}{a}-1b\
\
x_2=0\
\
x_1={y_1a}{b}+1a\
\
\
\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{4\cdot 29}\
\
\sqrt{\left(\frac{x_2\cdot b}{a}-b\right)^2+\left(-\frac{y_1\cdot a}{b}-a\right)^2}=\sqrt{116}\
\
\sqrt{b^2+a^2}=\sqrt{116}\
b^2+a^2=116\$
\
\
Simultaneous equations;
$b^2+a^2=116.....(1)
\
\frac{b}{a}=\frac{2}{5}.....(2)$
\
\
Using (2);\
\
$b=\frac{2a}{5}\$
\
\
Substitute for b in (1) to solve for a;\
\
$\left(\frac{2a}{5}\right)^2+a^2=116
\
29a^2=2900\
a^2=100\
a=\pm 10\
a=10$, since a and b are positive constants\
\
\
Now solve for b using (2);\
\
$b=\frac{2\cdot 10}{5}
\
b=4\
\
\
\therefore$ a=10\
$\therefore$ b=4
skySLAYER
Equation of measuring your mothers mass =;
$g{9.8}
Formula;
$m=\frac{123198}{g}
\
ok
,use
,help
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naahhhhh broooo
that's patience I don't have
How long did that take you
2 mins
Watched classroom of the elite, respect bro
\begin{equation}
\begin{split}
F = {F_{x} \in F_{c} &: (|S| > |C|) \
&\quad \cap (\text{minPixels} < |S| < \text{maxPixels}) \
&\quad \cap (|S_{\text{conected}}| > |S| - \epsilon) }
\end{split}
\end{equation}
un1ND3X|Sigma Is The New Vision.
\documentclass{article}
\usepackage{amsmath}
\usepackage{kantlipsum}
\usepackage{showframe}
\allowdisplaybreaks
\begin{document}
\kant[1-3]
\begin{align*}
a\
b\
c\
d\
e\tag{\stepcounter{equation}\theequation}\
f\
g\
h\
i
\end{align*}
\documentclass{article}
\begin{equation}
Ep = P_l \times da_i,
\end{equation}
%
where $P_l 😒 Required Personality Level of Each Resource-Assigned Personality Level of all Resources
\end{document}
un1ND3X|Sigma Is The New Vision.
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
good
Ayeee my man. Appreciate it.
Yo how'd u go to the next side over
Like how'd u do ur working into 2 columns ?
@sturdy sable
I used an align* environment from the mathtools package
Can u show an eg?
Alright I'll send you the code
Thanks bruv
\usepackage{mathtools}
\textbf{Find the limit of {\bm{$\lim_{x\to\infty}\frac{x^3-7x^2+6x-17}{x^4-8}$}:}}
\begin{align*}
&=\lim_{x\to\infty}\frac{x^3-7x^2+6x-17}{x^4-8}\\
&=\frac{(\infty)^3-7(\infty)-6(\infty)-17}{(\infty)^4-8}\\
\intertext{Since this is an $\frac{\infty}{\infty}$, we can use L`Hôpital's rule}
&\frac{dy}{dx}(x^3-7x^2+6x-17)&&\frac{dy}{dx}(x^4-8)&\longrightarrow\text{ L`Hôpital's rule:}\\
&=3x^2-14x+6&&=4x^3&\text{1st attempt}\\
\intertext{Since this is still an $\frac{\infty}{\infty}$ limit, we can repeatedly use L'Hôpital's rule until we get to a result:}
&\frac{dy}{dx}(3x^2-14x+6)&&\frac{dy}{dx}(4x^3)&\longrightarrow\text{ L`Hôpital's rule:}\\
&=6x-14&& =12x^2&\text{2nd attempt}\\
&\frac{dy}{dx}(6x-14)&&\frac{dy}{dx}(12x^2)&\longrightarrow\text{ L`Hôpital's rule:}\\
&=6&& =24x&\text{3rd attempt}\\
\intertext{Now we have:}
&\lim_{x\to\infty}\frac{6}{24x}\\
&=\frac{6}{24(\infty)}\\
&=\frac{6}{\infty}\\
&=0\\
\end{align*}
The & symbols are used to align everything
so everything with an & before it will align
everything with an && will align in a separate column
and so on
Thanks alot
Everything with an & on a single line right?
Wdym?
U said everything with an & will align with && so the code should be on a single line or separate lines is fine as well
Noo I meant everything that starts with an & will align with other lines that start with an &. And just like that, every part that starts with an && will align with other parts that start with &&
You can code on the same line or different lines, either works
But I prefer separate lines coz it's neater
$S_{n} = S_{\infty} (1-r^n) $
why isn't this working man
$S_{n} = S_{\infty} (1-r^n)$
Uibi
OHHHHH
It's more easier to correct mistakes
Yepp
Ramen
How to use latex?

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(f\left(x\right)=\left{-5\le x<-3:-4x-14,\ -3\le x\le7\ :\ \left(2x+4\right)\right}\ )
adjectivenoun
(\angle HAF = \arccos\frac{AF^2+AH^2-HF^2}{2AFAH})
adjectivenoun
(\begin{cases}
6a = \text{3rd difference} \
9a + 3 = \text{2nd difference} \
7a + 3b + c = \text{1st difference} \
a + b + c + d = \text{1st member of sequence}
\end{cases}
)
adjectivenoun
(\int_0^{\frac{\pi}{2}} \ln{\left \sin{x} \right} dx = -\frac{\pi\ln{2}}{2})
adjectivenoun
\(\int_0^{\frac{\pi}{2}} \ln{\left \sin{x} \right} dx = -\frac{\pi\ln{2}}{2}\)
```Compilation error:```! Missing delimiter (. inserted).
<to be read again>
\tex_let:D
l.58 \(\int_0^{\frac{\pi}{2}} \ln{\left \sin
{x} \right} dx = -\frac{\pi\ln{2...
I was expecting to see something like `(' or `\{' or
`\}' here. If you typed, e.g., `{' instead of `\{', you
should probably delete the `{' by typing `1' now, so that
braces don't get unbalanced. Otherwise just proceed.
Acceptable delimiters are characters whose \delcode is
nonnegative, or you can use `\delimiter <delimiter code>'.```
,preamble
Your personal custom preamble.
% Required to support mathematical unicode
\usepackage[warnunknown, fasterrors, mathletters]{ucs}
\usepackage[utf8x]{inputenc}
% Always typeset math in display style
\everymath{\displaystyle}
% Use a larger font size
\usepackage[fontsize=14pt]{scrextend}
\usepackage{dsfont}
% Standard mathematical typesetting packages
\usepackage{amsfonts, amsthm, amsmath, amssymb}
\usepackage{mathtools} % Extension to amsmath
% Symbol and utility packages
\usepackage{cancel, textcomp}
\usepackage[mathscr]{euscript}
\usepackage[nointegrals]{wasysym}
% Extras
\usepackage{physics} % Lots of useful shortcuts and macros
\usepackage{tikz-cd} % For drawing commutative diagrams easily
\usepackage{color} % Add some colour to life
\usepackage{microtype} % Minature font tweaks
% Common shortcuts
\def\mbb#1{\mathbb{#1}}
\def\mfk#1{\mathfrak{#1}}
\def\bN{\mbb{N}}
\def\bC{\mbb{C}}
\def\bR{\mbb{R}}
\def\bQ{\mbb{Q}}
\def\bZ{\mbb{Z}}
% Sometimes helpful macros
adjectivenoun
,help
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Global reputation: 3 rep
#ig-business-studies - 2 rep
#ig-economics - 1 rep
Alright
(\int_0^\infty (4x+2)^{-2} dx \
= -\frac{1}{16x+8}\bigg|1^{\infty} \
= \left( \lim\limits{x \to \infty} -\frac{1}{16x+8} \right) - \left( -\frac{1}{24} \right) \
= \left( \lim\limits_{x \to \infty} -\frac{\frac{1}{x}}{16 + \frac{8}{x}} \right) + \frac{1}{24} \
= 0 + \frac{1}{24} \
= \frac{1}{24}
)
adjectivenoun
,help
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\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
tex x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
,tex x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
xQ
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
```Compilation error:```! Missing $ inserted.
<inserted text>
$
l.57 x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.
LaTeX Font Info: Calculating math sizes for size <14> on input line 57.
LaTeX Font Info: Trying to load font information for U+msa on input line 57.```
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Please give me something to evaluate.
See ,help calc for usage details.
,help calc
,calc <expr>
Calculates the provided expressions and returns the result.
Multiple expressions may be entered simultaneously, separated by newlines.
Variables defined in one expression will be remembered in the expressions below.
For further documentation see the mathjs API docs.
,calc sin(45 deg)
,calc det([1, 1; 2, 3])
,calc 5 inches to cm
Visit our support server here to speak to our friendly support team!
,calc 2+2
Result:
4
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,tex x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
xQ
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,tex \x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
xQ
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,tex (x=\frac{-b\pm\sqrt{b^2-4ac}}{2a})
xQ
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,tex (x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
xQ
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$X$
anya
$\sqrt 56$
anya
$\sqrt 8 --> (8)^1/2$
anya
$hello from the other side$
anya
$hello\medspace\ from$
anya
anya
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reaction for more information.
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$\test$
dacia
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reaction for more information.
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dacia
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, tex{meow}
skySLAYER
Ahh
Noice
skySLAYER
$1\left(\begin{array}{c}
n\
1\end{array}\right)+2\left(\begin{array}{c}
n\
2\end{array}\right)+3\left(\begin{array}{c}
n\
3\end{array}\right)+4\left(\begin{array}{c}
n\
4\end{array}\right)+...+n\left(\begin{array}{c}
n\
n\end{array}\right)=n2^{n-1}\
\$
\
Start with the binomial;\
$(1+x)^n=\left(\begin{array}{c}
n\
0\end{array}\right)x^0+\left(\begin{array}{c}
n\
1\end{array}\right)x^1+\left(\begin{array}{c}
n\
2\end{array}\right)x^2+\left(\begin{array}{c}
n\
3\end{array}\right)x^3+\left(\begin{array}{c}
n\
4\end{array}\right)x^4+...+\left(\begin{array}{c}
n\
n\end{array}\right)x^n$\
\
\
Now differentiate this binomial;\
$n(1+x)^{n-1}=0+1\left(\begin{array}{c}
n\
1\end{array}\right)x^1+2\left(\begin{array}{c}
n\
2\end{array}\right)x^1+3\left(\begin{array}{c}
n\
3\end{array}\right)x^2+4\left(\begin{array}{c}
n\
4\end{array}\right)x^3+...+n\left(\begin{array}{c}
n\
n\end{array}\right)x^{n-1}\$
\
\
\
Since only the sum of the coefficients is required, Assume x=1;
The above sum can also be written in summation form, for x=1 we will get another summation in combination with the binomial theorem.\
\
$\sum\limits^{n}{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)(1)^{n-r}(x)^r=n(1+x)^{n-1}\$
\
\
When x=1\
$\sum\limits^{n}{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)(1)^{n-r}(1)^r=n(1+1)^{n-1}\
\
\sum\limits^{n}_{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)=n2^{n-1}$
skySLAYER
$hi$
dacia
, tex {hi}
dacia
{hi}
${hi}$
dacia
$hi$
dac
, tex {meow}
dac
$array$
dac
dac
${array}$
dac
😭
$\left[\begin {array}{cc}
0 & 1\
a & \theta\
\end{array}\right]$
skySLAYER
$food\medspace\is good$
anya
Compile Error! Click the
reaction for more information.
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$2/4 * 4/5$
anya
𝕿𝖆𝖒𝖎𝖒
,help
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Aaya
Aaya
$u\medspace\suck$
```Compilation error:```! Undefined control sequence.
l.57 $u\medspace\suck
$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.
Preview: Tightpage -1310720 -1310720 1310720 1310720
[1{/usr/local/texlive/2020/texmf-var/fonts/map/pdftex/updmap/pdftex.map}]```
$4x8=32$
Aaya
$4*8=32$
Aaya
$4/4=1$
Aaya
$lol lmao$
Aaya
$lol\space\lmao$
Aaya
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,help
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,ask 3x+2=5
,ask x^2-6x>0
You don't have the required permissions to kick members here!
,ask x^4-6x^3+7<=0
this is actually helpful lol
ikr
,w \frac{d}{dx}\frac{5x-1}{3-x}
$\frac {a+b}{a}=\frac {a}{b}}=\varphi$
Rengoku||AS Level||JEE||24||
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reaction for more information.
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$\frac {a+b}{a}=\frac {a}{b}=\varphi$
Rengoku||AS Level||JEE||24||
,calc 65/5
Result:
13
😱
$\frac{d}{dx}(x^{(x^x)}) = x^{(x^x + x - 1)} (x log^{2}(x) + x log(x) + 1)$
Unknown Member
,ask x^2 - 6x^3 + 7 = 0
Hmm
$ 1/2(6.4^2-5.6^2) $
,w calc $\int 1-\frac{\sqrt{x}}{21 ^3\sqrt{x}}+\frac{4 ^3\sqrt{x}}{2\sqrt{x}}+\frac{9}{ 4x^3 \sqrt{x}}$
$\sqrt{}$
Unknown Member
$\text{why ain't the bot working}$
$\text{why ain't the bot working}$
skySLAYER
It is tho
$\text{Ronaldo is the best footballer in the world}$
Goatnaldo
AlatusRex
dolpcons
,ask x+2=4
,help
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Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
$\trans{1}{0.5}{0.5}{1}$
Yoriichi Tsugikuni
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$Cosec(2\theta)\
\
= [sin(\theta)]^{-1}\
\
=\frac{1}{2\sin(\theta)\cos(\theta)}$
\
\
\
\
Now we can make use of Partial Fractions;\
\
$\frac{1}{2\sin(\theta) \cos(\theta)}= \frac{A}{2\sin(\theta)}+\frac{B}{\cos(\theta)}\
\
\
\frac{1}{2\sin(\theta)\cos(\theta)}=\frac{A\cdot \cos(\theta) + B\cdot 2\sin(\theta)}{2\sin(\theta)\cos(\theta)}\$
\
\
A must be $\cos(\theta)$ and B must be $\frac{\sin(\theta)}{2}$ as $\sin^2(\theta) + \cos^2(\theta)= 1$ due to numerators being equal I.e num(RHS)=num(LHS)\
\
$\frac{A}{2\sin(\theta)}+\frac{B}{\cos(\theta)}= \frac{\cos(\theta)}{2\sin(\theta)}+\frac{\sin(\theta)}{2\cos(\theta)}\
\
\
\
\
Cosec(2\theta)\
\
= \frac{\cos(\theta)}{2\sin(\theta)}+\frac{\sin(\theta)}{2\cos(\theta)}\
\
= \frac{1}{2\tan(\theta)} + \frac{\tan(\theta)}{2} \hspace{4mm}$ As $\left{\frac{\cos(\theta)}{\sin(\theta)}= \frac{1}{\tan(\theta)}, \frac{\sin(\theta)}{\cos(\theta)}= \tan(\theta)\right}\
\
\
=\frac{ \cot(\theta) + \tan(\theta)}{2}\
\
\
\
\therefore Cosec(2\theta)= \frac{ \cot(\theta) + \tan(\theta)}{2}$
skySLAYER
$(cos^2x +sin^2x)^2$
suffering thru physics
$(cosx+sinx)^2$
suffering thru physics
$integral$
suffering thru physics
suffering thru physics
skySLAYER
U can also apply limits
If u use \limits then top limit will be written after ^ sign and bottom limit written after _ sign
Like this
$\int\limits^a_b{(\cos x+ \sin x)^2}dx$
skySLAYER
suffering thru physics
$\int{(sin2xsinx)}dx$
suffering thru physics
ohh nice
thanks dude
Gave +1 rep to skySLAYER#2732
Also whenever u write trig functions keep \ before the function
So \sin 2x
Make sure u have that space between the trig and the input
As sometimes it doesn't work
,help
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
Unknown User
,help cmd
You really shouldn't take it literally :upside_down:. Please type ,help ping, for example!
The full command list may be found using ,list.
,list
Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.
If you still have questions, talk to our friendly support team here.
Render LaTeX code and configure rendering options.
tex: Render LaTeX code.
ctan: Searches the ctan
texdoc: Searches the texdoc
autotex: Toggle whether your LaTeX is automatically rendered.
preamble: View or modify your LaTeX preamble.
texconfig: View or modify your personal LaTeX rendering options.
guildpreamble: View or modify the guild's default LaTeX preamble
Guild administration
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editrole: Create or edit a server role.
autoclean: Automatic deletion of messages in the current channel.
forgetrolesfor: Forget stored persistent roles for one or all members.
,texdoc
Please give me something to search for!
,nlab
Please give me something to search for!
,nlab 6
,preamble
Your personal custom preamble.
% Required to support mathematical unicode
\usepackage[warnunknown, fasterrors, mathletters]{ucs}
\usepackage[utf8x]{inputenc}
% Always typeset math in display style
\everymath{\displaystyle}
% Use a larger font size
\usepackage[fontsize=14pt]{scrextend}
% Standard mathematical typesetting packages
\usepackage{amsfonts, amsthm, amsmath, amssymb}
\usepackage{mathtools} % Extension to amsmath
% Symbol and utility packages
\usepackage{cancel, textcomp}
\usepackage[mathscr]{euscript}
\usepackage[nointegrals]{wasysym}
% Extras
\usepackage{physics} % Lots of useful shortcuts and macros
\usepackage{tikz-cd} % For drawing commutative diagrams easily
\usepackage{color} % Add some colour to life
\usepackage{microtype} % Minature font tweaks
% Common shortcuts
\def\mbb#1{\mathbb{#1}}
\def\mfk#1{\mathfrak{#1}}
\def\bN{\mbb{N}}
\def\bC{\mbb{C}}
\def\bR{\mbb{R}}
\def\bQ{\mbb{Q}}
\def\bZ{\mbb{Z}}
% Sometimes helpful macros
\newcommand{\func}[3]{#1\colon#2\to#3}
$\everymath{\displaystyle}$
Unknown User
,preamble \everymath{\displaystyle}
% Required to support mathematical unicode
\usepackage[warnunknown, fasterrors, mathletters]{ucs}
\usepackage[utf8x]{inputenc}
% Always typeset math in display style
\everymath{\displaystyle}
% Use a larger font size
\usepackage[fontsize=14pt]{scrextend}
% Standard mathematical typesetting packages
\usepackage{amsfonts, amsthm, amsmath, amssymb}
\usepackage{mathtools} % Extension to amsmath
% Symbol and utility packages
\usepackage{cancel, textcomp}
\usepackage[mathscr]{euscript}
\usepackage[nointegrals]{wasysym}
% Extras
\usepackage{physics} % Lots of useful shortcuts and macros
\usepackage{tikz-cd} % For drawing commutative diagrams easily
\usepackage{color} % Add some colour to life
\usepackage{microtype} % Minature font tweaks
% Common shortcuts
\def\mbb#1{\mathbb{#1}}
\def\mfk#1{\mathfrak{#1}}
\def\bN{\mbb{N}}
\def\bC{\mbb{C}}
\def\bR{\mbb{R}}
\def\bQ{\mbb{Q}}
\def\bZ{\mbb{Z}}
% Sometimes helpful macros
\newcommand{\func}[3]{#1\colon#2\to#3}
Prompt timed out, your preamble was not modified.
$\int^2_{-1}\pi y^2 dy$
Unknown User
, help
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
$$\sum_{i=1}^5 2 \times (\frac{1}{\sqrt{2}})^{i-1} + \sum_{i=1}^{5}(\frac{1}{\sqrt{2}})^{i-1}]$$
HRM LordFoogThe2st
Brave the Browser
$$\begin{bmatrix}1 & 1\1 & -1\end{bmatrix} \begin{bmatrix} 2\0\end{bmatrix}_S = \begin{bmatrix} 1\-1\end{bmatrix} $$
Brave the Browser
$$ \begin{bmatrix} 2\2\end{bmatrix}_S = \begin{bmatrix}0.5 & 0.5\-0.5 & 0.5\end{bmatrix} \begin{bmatrix} 2\0\end{bmatrix}$$
Brave the Browser
,w evaluate \sum_{i=1}^{181} (30 + 6(i-1))
,w evaluate \sum_{i=1}^{10} (30 + 6i - 6)
$$U_n = U_1r^{n-1}$$
HRM LordFoogThe2st
$$U_n = x(\frac{37.5}{100})^3$$
HRM LordFoogThe2st
drug amount after a whole day can be given by the function:
$$f(a) = a(0.375)^3$$
\emph{where a is the amount of drug administered at the start of the day}
HRM LordFoogThe2st
,w simplify \frac{37.5}{100}(\frac{37.5}{100}(\frac{37.5x}{100} + x) + x ) + x
,w simplify x(1 + 0.375 + 0.375^2 + 0.375^3)
drug amount after a whole day can be given by the function:
$$f(a) = a(0.375)^3$$
\emph{where a is the amount of drug administered at the start of the day}
Army
$$ \begin{bmatrix} 2\2\end{bmatrix}_S = \begin{bmatrix}0.5 & 0.5\-0.5 & 0.5\end{bmatrix} \begin{bmatrix} 2\0\end{bmatrix}$$
Army
$\frac {a+b}{a}=\frac {a}{b}}=\varphi$
Army
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$1\left(\begin{array}{c}
n\
1\end{array}\right)+2\left(\begin{array}{c}
n\
2\end{array}\right)+3\left(\begin{array}{c}
n\
3\end{array}\right)+4\left(\begin{array}{c}
n\
4\end{array}\right)+...+n\left(\begin{array}{c}
n\
n\end{array}\right)=n2^{n-1}\
\$
\
Start with the binomial;\
$(1+x)^n=\left(\begin{array}{c}
n\
0\end{array}\right)x^0+\left(\begin{array}{c}
n\
1\end{array}\right)x^1+\left(\begin{array}{c}
n\
2\end{array}\right)x^2+\left(\begin{array}{c}
n\
3\end{array}\right)x^3+\left(\begin{array}{c}
n\
4\end{array}\right)x^4+...+\left(\begin{array}{c}
n\
n\end{array}\right)x^n$\
\
\
Now differentiate this binomial;\
$n(1+x)^{n-1}=0+1\left(\begin{array}{c}
n\
1\end{array}\right)x^1+2\left(\begin{array}{c}
n\
2\end{array}\right)x^1+3\left(\begin{array}{c}
n\
3\end{array}\right)x^2+4\left(\begin{array}{c}
n\
4\end{array}\right)x^3+...+n\left(\begin{array}{c}
n\
n\end{array}\right)x^{n-1}\$
\
\
\
Since only the sum of the coefficients is required, Assume x=1;
The above sum can also be written in summation form, for x=1 we will get another summation in combination with the binomial theorem.\
\
$\sum\limits^{n}{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)(1)^{n-r}(x)^r=n(1+x)^{n-1}\$
\
\
When x=1\
$\sum\limits^{n}{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)(1)^{n-r}(1)^r=n(1+1)^{n-1}\
\
\sum\limits^{n}_{r=0}r\left(\begin{array}{c}
n\
r\end{array}\right)=n2^{n-1}$
Army
$\mathbb{R}$
donkey loves sigma
i came for latex and am dissapointed
This is some text in LaTeX
$$ $$
Brave the Browser
What does a Linear Transformation look like in basis C?\
\First convert vector in basis of C to B
$$[\vec v]_B = CtoB \cdot [\vec v]_C$$
\Then Transform vector in basis of B
$$[T]_B \cdot [\vec v]_B $$
$$[T]_B \cdot (CtoB \cdot [\vec v]_C)$$
\Finally Convert transformed matrix in basis of B to basis of C
$$BtoC \cdot [T]_B \cdot [\vec v]_B$$
$$BtoC \cdot ([T]_B \cdot (CtoB \cdot [ \vec v]_C))$$
$$[T]_C = BtoC \cdot [T]_B \cdot CtoB$$
\ Matrix $ [T]_C$ is transformation matrix in basis of C
$$[T]_C \cdot [ \vec v]_C $$
Brave the Browser
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$A_x$
dac
$$A_x$$
dac
dac
dac
Meow $A_x$,,, $$B_x, Meow Meow$$
dac 🐣
Meow $A_x$,,, $$B_x, \Meow Meow$$
dac 🐣
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Meow $A_x$,,, $$B_x, \Meow Meow$$
Am I bad at math cuz I've never seen these at math
dac 🐣
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dac 🐣
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dac 🐣
$$frac{1/1}$$
it’s complicated
Lxst_Jedi | LSE Janitor
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$$\frac{1}{2}$$
Lxst_Jedi | LSE Janitor
Noice
I mean I do programming but it was the first time I had ever heard of latex
i had to google it up
ye LaTeX is rly common for people going into/doing enginneering hgdjhks majors
- If AB is a diameter on the circle $(x-3)^2 + (y-2)^2 = 5$, where A is (2,0) and D(5,3) lies on the circle, prove that triangle ABD is right-angled at D
\par
HRH LordFoogThe2st
,w plot (\frac{x}{7}\right)^2 \sqrt{\left|\frac{|x|}{2}-\frac{3}{2}\right|+\frac{3}{2}-\frac{3}{10}(x^2+y^2)-y^2} - \frac{3}{7}\sqrt{10}\sqrt{\left|\frac{1}{2}-\frac{|x|}{5}\right|-\left(\frac{x}{5}\right)^2-y^2} = 0
$$\sum_{k=0}^{\infty} \frac{1}{(k+1)(k+2)(k+3)\cdots(k+n+1)}
= \frac{1}{n(n+1)(n+2)\cdots(n+n)}
\sum_{k=0}^{\infty} \frac{(-1)^k}{k+n+1}
\binom{k+n}{n}$$
where $n \in \mathbb{N}$ and $\binom{m}{n}$ is the binomial coefficient. This equation involves a summation over an infinite series of fractions, with each denominator containing one more factor than the previous term. The second part of the equation involves a summation over another infinite series, with each term being a binomial coefficient multiplied by an alternating sign. The equation is often used in combinatorics and can be derived using techniques from calculus and complex analysis. $$
HRH LordFoogThe2st
$$\sum_{k=0}^{\infty} \frac{1}{(k+1)(k+2)(k+3)\cdots(k+n+1)}
= \frac{1}{n(n+1)(n+2)\cdots(n+n)}
\sum_{k=0}^{\infty} \frac{(-1)^k}{k+n+1}
\binom{k+n}{n}$$
where $n \in \mathbb{N}$ and $\binom{m}{n}$ is the binomial coefficient. This equation involves a summation over an infinite series of fractions, with each denominator containing one more factor than the previous term. The second part of the equation involves a summation over another infinite series, with each term being a binomial coefficient multiplied by an alternating sign. The equation is often used in combinatorics and can be derived using techniques from calculus and complex analysis. $$
```Compilation error:```! Missing $ inserted.
<inserted text>
$
l.62 \end{document}
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
:(
yeeee
$meow$
♡‧₊˚ dac
♡‧₊˚ dac
interesting
$frac{1}{2}$
Lxst_Jedi | LSE Janitor
Lxst_Jedi | LSE Janitor
$\frac{1}{2}$
Finally figured it out
what is latex?
$\sigma = \sqrt{\frac{1}{N}\sum_{i=1}^N(x_i - \mu)^2}$
HRH LordFoogThe2st
HRH LordFoogThe2st
$$\sigma = \frac{\sum x_i - \bar{x}}{n - 1}$$
HRH LordFoogThe2st
$$\sigma^2 = \frac{\sum x_i - \bar{x}}{n - 1}$$
HRH LordFoogThe2st
$\meow$
dac
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dac
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reaction for more information.
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A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
$meow$
Notalex
$7/4*10^3$
Notalex
$\meow=meow$
dac
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dac
$$meow=meow$$
dac
dac
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dac
dac
$/bar {x}$
dac
dac
$$\bar{x}$$
dac
dac
$\gamma$
dac
$\gamma = lim$
dac
$\gamma = {lim}$
dac
ok
$\sigma$
Lxst_Jedi | LSE Janitor
Lxst_Jedi | LSE Janitor
dac
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$\approach$
dac
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dac
Lxst_Jedi | LSE Janitor
$\gamma = \sum_{n=1}^{\infinity}$
dac
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dac
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no
$infinty$
Lxst_Jedi | LSE Janitor
,list
Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.
If you still have questions, talk to our friendly support team here.
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mute: Silence a misbehaving user for a specified amount of time.
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Mathematical calculatuations and computations.
calc: Calculate short mathematical expressions.
nlab: Searches the nlab
query: Query the Wolfram Alpha computation engine.
,help cmd
You really shouldn't take it literally :upside_down:. Please type ,help ping, for example!
The full command list may be found using ,list.
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
$\infty$
dac
dac
dac
dac
dac
$\gamma = \sum{n=1}^{\infty} = {\frac{1}{1^s}} + {\frac{1}{2^s}}$
dac
dac
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^(x+iy)}}$
dac
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{(k)^(x+iy)}}$
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
COMPILE ERROR BUT IT WORKED
2
oh ok got it
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
dac
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dac
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reaction for more information.
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dac
$f(x+iy) = {\sum_{k=1}^{\infty}}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Extra }, or forgotten $.
l.57 $f(x+iy) = {\sum_{k=1}^{\infty}}}
{\frac {1}{k^{(x+iy)}}$
I've deleted a group-closing symbol because it seems to be
spurious, as in `$x}$'. But perhaps the } is legitimate and
you forgot something else, as in `\hbox{$x}'. In such cases
the way to recover is to insert both the forgotten and the
deleted material, e.g., by typing `I$}'.```
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
$f(x+iy) = {\sum_{k=1}^{\infty}{\frac {1}{k^{(x+iy)}}$
dac
$f(x+iy) = {\sum_{k=1}^{\infty}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...\sum_{k=1}^{\infty}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
dac
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reaction for more information.
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dac
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reaction for more information.
(You may edit your message to recompile.)
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
$f(x+iy) = {\sum_{k=1^{\infty}}{\frac {1}{k^{(x+iy)}}$
dac
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
dac
$f(x+iy) = {\sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 ...sum_{k=1}^{\infty}}{\frac {1}{k^{(x+iy)}}$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
$f(x+iy) = {\sum_{k=1}}^{\infty}}{\frac {1}{k^{(x+iy)}}$
dac
$f(x+iy) = {\sum_{k=1}}^{\infty}}{\frac {1}{k^{(x+iy)}}$
```Compilation error:```! Extra }, or forgotten $.
l.57 $f(x+iy) = {\sum_{k=1}}^{\infty}}
{\frac {1}{k^{(x+iy)}}$
I've deleted a group-closing symbol because it seems to be
spurious, as in `$x}$'. But perhaps the } is legitimate and
you forgot something else, as in `\hbox{$x}'. In such cases
the way to recover is to insert both the forgotten and the
deleted material, e.g., by typing `I$}'.```
dac
Compile Error! Click the
reaction for more information.
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$f(x+iy) = {\sum_ {k+1}{\infty}}$
dac
$f(x+iy) = {\sum_ {k+1}^{\infty}}$
dac
$f(x+iy) = {\sum_ {k+1}^{\infty}}$$\frac{1}{k^{x+iy}}$
dac
dac
dac
$\mod {x}$
dac
$\equiv$
dac
$\left$
dac
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$|x$
dac
$|x|$
dac
$\lambda$
dac
Are you trying to type this?
$\int{dx}{(x^2 +2)^2}$
dac
dac
dac
Compile Error! Click the
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dac
$\int {\frac{dx}{(x^2 +2)^2}}$
put $$\sqrt{2}$$
dac
dac
dac
$\int {\frac{dx}{(x^2 +2)^2}}$
\put $\sqrt{2} tan u$
\ $dx = \sqrt {2} sec^2 u du$
…
dac
$\int {\frac{dx}{(x^2 +2)^2}}$
\put $\sqrt{2} tan u$
\ $dx = \sqrt {2} sec^2 u du$
\ $\int{\frac{dx}{(x^2 + 2)^2}} = \int {\frac{\sqrt {2} sec^2 u du}{(2 tan^2 u + 2)^2}} = \int{\frac{\sqrt{2} sec^2 u du}{4(tan^2 u + 1)^2}}$
\
\$= \frac{\sqrt{2}}{4}$$\int{\frac{sec^2 u du}{(sec^2 u)^2}} = {\frac{\sqrt {2}}{4}}\int {cos^2 u}{du}$
\ $ = \frac {\sqrt {2}}{4}$•$\frac {1}{2} \int{[1+cos2u]} du$
\$\frac {\sqrt {2}}{8}$$[u + \frac{sin 2u}{2}] + C$$=\frac{\sqrt{2}}{8}$$[u + sin u cos u] + C$
\$= \frac{\sqrt{2}}{8}$
how do yall space it out so evenly
dac
$\arctan(x)$
dac
$\arctan(x)$
dac
Compile Error! Click the
reaction for more information.
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$\int {\frac{dx}{(x^2 +2)^2}}$
\put $\sqrt{2} tan u$
\ $dx = \sqrt {2} sec^2 u du$
\ $\int{\frac{dx}{(x^2 + 2)^2}} = \int {\frac{\sqrt {2} sec^2 u du}{(2 tan^2 u + 2)^2}} = \int{\frac{\sqrt{2} sec^2 u du}{4(tan^2 u + 1)^2}}$
\
\$= \frac{\sqrt{2}}{4}$$\int{\frac{sec^2 u du}{(sec^2 u)^2}} = {\frac{\sqrt {2}}{4}}\int {cos^2 u}{du}$
\ $ = \frac {\sqrt {2}}{4}$•$\frac {1}{2} \int{[1+cos2u]} du$
\$\frac {\sqrt {2}}{8}$$[u + \frac{sin 2u}{2}] + C$$=\frac{\sqrt{2}}{8}$$[u + sin u cos u] + C$
\$= \frac{\sqrt{2}}{8}$
dac
$\int {\frac{dx}{(x^2 +2)^2}}$
\\put $\sqrt{2} tan u$
\\ $dx = \sqrt {2} sec^2 u du$
\\ $\int{\frac{dx}{(x^2 + 2)^2}} = \int {\frac{\sqrt {2} sec^2 u du}{(2 tan^2 u + 2)^2}} = \int{\frac{\sqrt{2} sec^2 u du}{4(tan^2 u + 1)^2}}$
\\
\\$= \frac{\sqrt{2}}{4}$$\int{\frac{sec^2 u du}{(sec^2 u)^2}} = {\frac{\sqrt {2}}{4}}\int {cos^2 u}{du}$
\\ $ = \frac {\sqrt {2}}{4}$•$\frac {1}{2} \int{[1+cos2u]} du$
\\$\frac {\sqrt {2}}{8}$$[u + \frac{sin 2u}{2}] + C$$=\frac{\sqrt{2}}{8}$$[u + sin u cos u] + C$
\\$= \frac{\sqrt{2}}{8}$
$\int {\frac{dx}{(x^2 +2)^2}}$
\put $\sqrt{2} tan u$
\ $dx = \sqrt {2} sec^2 u du$
\ $\int{\frac{dx}{(x^2 + 2)^2}} = \int {\frac{\sqrt {2} sec^2 u du}{(2 tan^2 u + 2)^2}} = \int{\frac{\sqrt{2} sec^2 u du}{4(tan^2 u + 1)^2}}$
\
\$= \frac{\sqrt{2}}{4}$$\int{\frac{sec^2 u du}{(sec^2 u)^2}} = {\frac{\sqrt {2}}{4}}\int {cos^2 u}{du}$
\ $ = \frac {\sqrt {2}}{4}$•$\frac {1}{2} \int{[1+cos2u]} du$
\$\frac {\sqrt {2}}{8}$$[u + \frac{sin 2u}{2}] + C$$=\frac{\sqrt{2}}{8}$$[u + sin u cos u] + C$
\$= \frac{\sqrt{2}}{8}$$[arctan(\frac{x}{\sqrt{2}}) + {(\frac{x}{\sqrt{x^2 + 2}})}$$(\frac{\sqrt{2}}{\sqrt {x^2 + 2}}) ] + C$
\$=\frac{\sqrt{2}}{8}$$[arctan (\frac{x}{\sqrt{2}}) + (\frac{x•\sqrt{2}}{x^2 + 2})] + C$
dac
$tan^-1$
dac
$\tan^-1$
dac
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
Are y...you th...the g...o....d?
$e$
dac
$r = \frac{\sum_{i}$•(y_i - \bar{y})}{\sqrt{\sum_{i}(x_i - \bar{x})^2}}{\sqrt{\sum_{i}(y_i - \bar{y})^2}}$
oops
eh
dac
$\sum_{k=1}$
dac
$\sum_{k=1}$
dac
bruh
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
hmmm
bro enough, you embarrassed me enough
oh
pine
What in the
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
Gojo's_Mekuri | IIT Janitor
Damn
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4\i + 55:1) -- ++(4\i:1) -- ++(4\i + 60:1) -- ++(4\i:1) -- ++(4\i + 65:1) -- ++(4\i:1) -- ++(4*\i + 70:1);
}
Lxst_Jedi | LSE Janitor
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
\boxed{\v=\frac d t}
u forgot the /end{tikzpicture}
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 200\relax,
\the\numexpr125 + \pdfuniformdeviate 200\relax,
\the\numexpr125 + \pdfuniformdeviate 200\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
trash
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 29\relax,
\the\numexpr125 + \pdfuniformdeviate 29\relax,
\the\numexpr125 + \pdfuniformdeviate 29\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
nahhh
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{R}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
DrYpTiC
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$_a^b\int\pi x^2 dx$
Unknown User | Harvard Janitor
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 29\relax,
\the\numexpr125 + \pdfuniformdeviate 29\relax,
\the\numexpr125 + \pdfuniformdeviate 29\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4\i + 55:1) -- ++(4\i:1) -- ++(4\i + 60:1) -- ++(4\i:1) -- ++(4\i + 65:1) -- ++(4\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
Advis
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4\i + 55:1) -- ++(4\i:1) -- ++(4\i + 60:1) -- ++(4\i:1) -- ++(4\i + 65:1) -- ++(4\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
Advis
you proved im dumb and useless in less than 1 second 
Unknown User | Harvard Janitor
Unknown User | Harvard Janitor
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$SO_4^2-$
Gojo's_Mekuri | IIT Cook
$SO_4 ^2-$
Gojo's_Mekuri | IIT Cook
$SO_4^2^-$
Gojo's_Mekuri | IIT Cook
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$\multiply$
dac
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$\times$
dac
dac
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$\left[\begin {array}{cc}
0 & 1\
a & \theta\
\end{array}\right]$
dac
$(x+a)^n = \sum_{k=0}^{n} \top[\begin {array}{cc} 0 & 1\end{array}\bottom]$
Lxst_Jedi | LSE Janitor
$\frac{\theta}{x}$
Lxst_Jedi | LSE Janitor
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$\frac{\theta}{x}$
Lxst_Jedi | LSE Janitor
Further Math
dac
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Bruh
$(x+a)^n = \sum_{k=0}^{n}
\left[\begin {array}{c} 0\ 1\
\end{array}\right]$
$\hobx$
dac
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
dac
$(x+a)^n = \sum_{k=0}^{n}
\left(\begin {array}{c} n\
k\
\end{array}\right)$
Tf am i doing wrong
dac
dac
,calc +0.15 -(-0.74)
Result:
0.89
\frac{1}{2}
$a^2$
Arven 🇧🇩
$a^2+b^2=c^2$
Arven 🇧🇩
$c^2=a^2+b^2-2abcosc$
Arven 🇧🇩
$bababooey$
Arven 🇧🇩
$hello
$\sqrt{2}$
dac 🧚
dac 🧚
$E = MC^2$
nguyen minh duc
$F = MA$
nguyen minh duc
$Physics$
nguyen minh duc
$Further.Math.Is.Hard$
Lxst_Jedi | LSE Janitor
$I'm really hot$
r1ra
$I'm harder$
kortuvor
drunkenergetic
$\frac{}{a}$
Lxst_Jedi | LSE Janitor
Hmm, NOT A
$N$
Tzu
$i$
Tzu
drunkenergetic
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4\i + 55:1) -- ++(4\i:1) -- ++(4\i + 60:1) -- ++(4\i:1) -- ++(4\i + 65:1) -- ++(4\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
Geagle
stolen from someone’s message earlier in this channel fr
I can tell
$Hey_handsome$
Jessie bluewoman
$meow$
Fia
chaawal
Study
$computer.science.is.killing.me.slowly$
3.14
$deez nutz$
3.14
$\frac{1}{2}$
3.14
$class TStudentRecord:
def init(self):
self.name =""
self.address = ""
self.className =""
studentFile = open('student.TXT','w')
myStudent = TStudentRecord()
myStudent.name = "micheal afton"
myStudent.address = "random house 2"
myStudent.className ="87B"
print ("Name ", myStudent.name)
print ("Address ", myStudent.address)
print ("Class ", myStudent.className)
studentFile.write(myStudent.name + " " + myStudent.address + " " + myStudent.className + "\n")
studentFile.close()
studentFile = open('student.TXT','r')
print (studentFile.read()) #print all the records in a file
studentFile.close()$
3.14
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
💔
$class TStudentRecord:
def init(self):
self.name =""
self.address = ""
self.className =""
studentFile = open('student.TXT','w')
myStudent = TStudentRecord()
myStudent.name = "micheal afton"
myStudent.address = "random house 2"
myStudent.className ="87B"
print ("Name ", myStudent.name)
print ("Address ", myStudent.address)
print ("Class ", myStudent.className)
studentFile.write(myStudent.name + " " + myStudent.address + " " + myStudent.className + "\n")
studentFile.close()
studentFile = open('student.TXT','r')
print (studentFile.read()) #print all the records in a file
studentFile.close()$
3.14
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex
\definecolor{eggshell}{RGB}{252,230,201}
\pgfdeclareradialshading{eggshading}{\pgfpoint{1cm}{1cm}}%
{color(0cm)=(eggshell!80);
color(0.5cm)=(brown!75!eggshell);
color(0.7cm)=(brown);
color(0.9cm)=(brown!70!black);
color(1.2cm)=(black)
}
\pgfdeclareradialshading{eggshadow}{\pgfpointorigin}%
{color(0cm)=(black);
color(2mm)=(gray!80);
color(3mm)=(gray!40);
%color(0.3cm)=(black!5!white);
color(7mm)=(white)
}
\begin{tikzpicture}
\begin{scope}[yscale=0.93,transform shape]
\node[xscale=2,yscale=0.3,shading=eggshadow,circle,minimum size=7mm] at (0,2.75mm){};
\shade[shading=eggshading] (0,2.7mm)..controls (9mm,0.25cm) and (7mm,2cm)%
..(0,20.5mm)..controls(-7mm,2cm) and (-9mm,2.5mm)..(0,2.7mm)--cycle;
\end{scope}
\end{tikzpicture}
Bitch
3.14
Talur 🤩
,tex
\documentclass{article}
\usepackage{graphicx}
\newcommand{\heart}{\ensuremath\heartsuit}
\newcommand{\butt}{\rotatebox[origin=c]{180}{\heart}}
\begin{document}
\heart\ \butt
\Large \heart\ \butt
\end{document}
\documentclass{article}
\usepackage{graphicx,txfonts}
\newcommand{\heart}{\ensuremath\varheartsuit}
\newcommand{\butt}{\rotatebox[origin=c]{180}{\heart}}
\begin{document}
\heart\ \butt
\Large \heart\ \butt
\end{document}
I compile the code you give me by putting it into a template LaTeX document, between \begin{document} and \end{document} commands.
Please don't give me code that belongs outside of there!
See ,help tex for some examples of what I understand.
If you want to modify the template to add packages or your own macros, see ,help preamble.
3.14
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
💔
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4*\i + 55:1) -- ++(4*\i:1) -- ++(4*\i + 60:1) -- ++(4*\i:1) -- ++(4*\i + 65:1) -- ++(4*\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
3.14
I compile the code you give me by putting it into a template LaTeX document, between \begin{document} and \end{document} commands.
Please don't give me code that belongs outside of there!
See ,help tex for some examples of what I understand.
If you want to modify the template to add packages or your own macros, see ,help preamble.
3.14
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
3.14
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex
\begin{tikzpicture}
\newcommand{\rngcolor}{\definecolor{rngcolor}{RGB}
{
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
}}
\foreach \i in {0,...,90}
{
\rngcolor
\draw[rngcolor,thick] (0,0) -- (4 * \i:1) -- ++(4\i + 55:1) -- ++(4\i:1) -- ++(4\i + 60:1) -- ++(4\i:1) -- ++(4\i + 65:1) -- ++(4\i:1) -- ++(4*\i + 70:1);
}
\end{tikzpicture}
Julian_Loki
DAMN
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax,
\the\numexpr125 + \pdfuniformdeviate 131\relax
$\frac{\sqrt{3} + 1}{ \sqrt{3}-1}$
CoolGuy
$\frac{\sqrt{3} + 1}{1 - \sqrt{3}}$
CoolGuy
eeyore.
$dolla dolla bils$
Slimshady
Slimshady
$OH NOW I UNDERSATND$
Slimshady
$BHAI FAIL$
Slimshady
$DO YOU TAKE INPUT AS CHAR$
Slimshady
$SEEMS .LIKE U DO$
Slimshady
$slim rocks$
Slimshady
$meow$
dac
@median phoenix
PrK
$meow$
dac
$what do I do here$
orion
$dead_channel$
Master X
$toodeadfr$
Master X
$1/2/3/4$
nguyen minh duc
$\frac{\sqrt{3} + 1+3+frac{1/3}+sqrt{12345}{1 - \sqrt{3}}+11+frac{1/2}$
nguyen minh duc
$\frac{\sqrt{3} + 1+3+frac{1/3}+sqrt{12345}{1 - \sqrt{3}}+11+frac{1/2}$
```Compilation error:```! File ended while scanning use of \frac .
<inserted text>
\par
<*> 1008765404245672107.tex
I suspect you have forgotten a `}', causing me
to read past where you wanted me to stop.
I'll try to recover; but if the error is serious,
you'd better type `E' or `X' now and fix your file.```
nguyen minh duc
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
$\frac{\sqrt{3} + 1+sqrt{321}+sqrt{12345}{1 - \sqrt{3}}+11$
nguyen minh duc
Compile Error! Click the
reaction for more information.
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✨
$\frac{1}{(ax^2)(bx)(c)} = \frac{Ax+B}{ax^2} + \frac{C}{bx} + \frac{1}{c}$
nasi_murni
$1 = (Ax+B)(bx)(c) + C(ax^2)(c) + (ax^2)(bx)$
nasi_murni
$x^2$
\
$0 = Abc + Cac $
\
$x$
\
$0 = Bbc$
nasi_murni
$0=c(Ab+Ca)$
\
let $Ab + Ca \neq 0$
\
$ c = 0$
\
$0 = Bb(c)$
\
$Bb \neq 0$
nasi_murni
$\frac{\frac{3}{3}}{3}$
nasi_murni
$Test$
nasi_murni
$\vec{x}$
nasi_murni
$\vec{meow}$
d.gyj
$\sqrt{2}$
d.gyj
nasi_murni
$
$
d.gyj
does not work 
nasi_murni
noob
$\tfrac{\vec{CoC}}{\vec{oW}}$
nasi_murni
What's the point of this bot?
$\sigma$
$\frac{d\sigma}{d\Omega} = \mid f (\theta , \phi) \mid ^2$
\
$a \mid n > = \sqrt{n + 1} \mid n+ 1 >$
hm
omg
lord wtf
where is the bot

$test$
dcagh
bruh
$Maths is fun$
huang17
Maths is fun $:)$
nasi_murni
Kaalhu🐦
$"Give up on your dreams and die"$
Man
$\text{This is a test.}$
dysto.
Hm
We now have
$\sum _{n=0} ^{10} (-1)^n$
basic_acid
Yeah
∑ essential sums terms
So here the lower bound is n=0 the upper bound is n=10
So you sub in each value and increment 1 and so on
So like
(-1)⁰+(-1)¹+(-1)²+....
You are substituting values of n
Like a for loop
And adding the terms
Ohhh
Uptil n=10
Ok lemme try
Sure
Ye
basic_acid
Hm
You can rewrite this as $3^a=1$ right?
basic_acid
Ohhhh it'll be 0
Yepp
😊
Here
$$\begin{equation}z_1=r_1e^{i\theta},,z_2=r_2e^{i\theta}, z_1z_2=r_1e^{i\theta}\times r_2e^{i\theta}=r_1r_2e^{i(\theta_1+\theta_2)}\end{equation}:and:\frac{z_1}{z_2}=\frac{r_1e^{i\theta_1}}{r_2e^{i\theta_2}}=\frac{r_1}{r_2}e^{i(\theta_1-\theta_2)}$$
Parallax Error
$$\begin{equation}z_1=r_1e^{i\theta},\,z_2=r_2e^{i\theta}, z_1z_2=r_1e^{i\theta}\times r_2e^{i\theta}=r_1r_2e^{i(\theta_1+\theta_2)}\end{equation}\:and\:\frac{z_1}{z_2}=\frac{r_1e^{i\theta_1}}{r_2e^{i\theta_2}}=\frac{r_1}{r_2}e^{i(\theta_1-\theta_2)}$$
```Compilation error:```! LaTeX Error: Bad math environment delimiter.
See the LaTeX manual or LaTeX Companion for explanation.
Type H <return> for immediate help.
...
l.57 $$\begin{equation}
z_1=r_1e^{i\theta},\,z_2=r_2e^{i\theta}, z_1z_2=r_1e^...
Your command was ignored.
Type I <command> <return> to replace it with another command,```
$$z_1=r_1e^{i\theta},,z_2=r_2e^{i\theta}, z_1z_2=r_1e^{i\theta}\times r_2e^{i\theta}=r_1r_2e^{i(\theta_1+\theta_2)}:and:\frac{z_1}{z_2}=\frac{r_1e^{i\theta_1}}{r_2e^{i\theta_2}}=\frac{r_1}{r_2}e^{i(\theta_1-\theta_2)}$$
Parallax Error
$$\begin{equation}z_1=r_1e^{i\theta},,z_2=r_2e^{i\theta}, z_1z_2=r_1e^{i\theta}\times r_2e^{i\theta}=r_1r_2e^{i(\theta_1+\theta_2)}:and:\frac{z_1}{z_2}=\frac{r_1e^{i\theta_1}}{r_2e^{i\theta_2}}=\frac{r_1}{r_2}e^{i(\theta_1-\theta_2)}\end{equation}$$
Parallax Error
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