Create new object from another object - typebox optional

[lost musk]

Hello,
can you help me how i can keep object keys hints when create new object

import type { TPropertyKey, TSchema } from '@sinclair/typebox';

export const createOptional = (list: Record<TPropertyKey, TSchema>) => {
  return Object.fromEntries(Object.entries(list).map(([key, value]) => [key, Type.Optional(value)])) as Record<TPropertyKey, TOptional<TSchema>>;
}

const result = createOptional({ id: Type.String() });

[indigo bobcat]

You're probably going to want to do this: ```ts
export const createOptional = <T extends Record<TPropertyKey, TSchema>>(list: T) => {}

And then either remove the as Record<...> at the end, or make it as T

Oh the keys too, moment *

[worn kiln]

mjuksel#0

Playground Link

Preview:```ts
import type {
TPropertyKey,
TSchema,
Type,
} from "@sinclair/typebox"
console.clear()

export const createOptional = <
T extends Record<TPropertyKey, TSchema>

(
list: T
) => {
return Object.fromEntries(
Object.entries(list).map(([key, value]) => [
key,
Type.Optional(value),
])
) as T
...```

You can choose specific lines to embed by selecting them before copying the link.

[lost musk]

looks better, because it keeps keys, it is maybe possible to return it as { id: TOptional<TString> } instead { id: TString }

[indigo bobcat]

I think you need to pass in Optional in createOptional

I haven't really seen that library, so I dunno how it works exactly

Ye looks like it

[lost musk]

type Optional<T extends Record<TPropertyKey, TSchema>> = {
  [Key in keyof T]: TOptional<T[Key]>;
}
export const createOptional = <T extends Record<TPropertyKey, TSchema>>(list: T) => {
  return Object.fromEntries(Object.entries(list).map(([key, value]) => [key, Type.Optional(value)])) as Optional<T>;
}

const schema = { id: Type.String() };
const schema_optional = createOptional(schema);

const schema_id = schema.id;
const schema_optional_id = schema_optional.id;

it works now as i wanted it, thank you for help @indigo bobcat ❤️

[indigo bobcat]

😘 np