earnest tapir
How to do Array of not optional X Type
Probably there i have to use satisfies but i dont know how
export type TpkgManagerSupport = "npm" | "yarn" | "pnpm" | "bun";
export const pkgManagerSupportWrong: TpkgManagerSupport[] = ["npm", "pnpm", "bun"] as const; // should crash - no "yarn"
export const pkgManagerSupportCorrect: TpkgManagerSupport[] = ["npm","yarn", "pnpm", "bun"] as const; // Fine, has everypossible type of Tpkg...
Ping me in answer
shut crystal
@earnest tapir There isn't really a way to do this - an array's type says what can be in it, not what must be in it.
The most common appraoch is to define the array and then derive the type from it.
export type TpkgManagerSupport = (typeof pkgManagerSupport)[number]
export const pkgManagerSupport = ["npm","yarn", "pnpm", "bun"] as const;
Oh, i thought it's possible with satisfies to do this.
Can you explain me how works (typeof pkgManagerSupport)[number] ? Why with [number] it's not a array
it's like "simulating" output with OurArray[index] ?
If you know where it would be, can you send me link to docs to that feature?
shut crystal
it's like "simulating" output with `OurArray[index]` ?
Yeah, this is basically the definition of an array: when you use a number to index it, you get whatever is inside the array out.
There's an example of it here: