gritty crypt
I am working with a library that makes extensive use of an interface called Record. The problem is that I also want to use typescript's Record<T, U>. I would like to have Record refer to my library's interface, not the typescript one. is there any way to do
import { Record as TSRecord } from '???'
livid axle
@gritty crypt I don't think there's any way to do that via import syntax.
You could make your own file that exports it, like:
// ts-utils.ts
export type TSRecord<K extends string, V> = Record<K, V>;
import { TSRecord } from "./ts-utils"
... but personally, I'd suggest going the other way.
gritty crypt
oh interesting
livid axle
I would do something like:
import * as lib from "lib";
type Whatever = lib.Record
idk its hard, Record is such a widely used thing that I dont want to confuse me/others about whether it refers to our lib or typescript
gritty crypt
I would do something like:
```ts
import * as lib from "lib";
type Whatever = li...
oh hm good point that could work
livid axle
idk its hard, `Record` is such a widely used thing that I dont want to confuse m...
Yup, that's why I'd keep the default Record as the TS version, personally.
gritty crypt
got it, thanks for the advice!