#imagine
1 messages · Page 1 of 1 (latest)
aight
this is the field
yes
imagine the field
1^2 + 1^2 + 1^2 = C^2
do you use meters or feet?
meters
aight
a is 40 and 30 is B?
to the other edge
it would take me 70 meters
if i walk directly next to the field
right?
right
now the question is
how many meters would it be
if i crossed the field diagonally
like this
yeah
this is where you can use the pythagorean theorem
now to go from a square
to its width/height
we know for a square
it is l*l or b*b
which is just l² and b²
so to go back to l and b
so like, that 4^2
w x h is 8?
yes
4^2 = 4x4
mb
4^3 = 4x4x4
i see
so you see
a^2 is the area
of the square of a
b^2 is the area of the square of b
add them together
and you get c^2 which is the area of the square of c
a^2+b^2=c^2
now you have the area of the square of c
i think i get it
for that triangle here
its 25 sq = 5
do it for this one
sqrt 25
yeah
25 sq is not sqrt 25
25 sq = 25^2
oh nvm
ya
aight
so
you see we have everything
except for the diagonal
so 30^2+40^2=c^2
30^2=900
40^2=1600
900+1600=2500
c^2=2500
c=sqrt(2500)=50
those are the w and h right?
what is
I see
this would move me 50 meters
this is too much
so we want to only move one meter at a time
one final question
so we divide everything by 50
ya
A and B, are they the area?
i dont think you are following anything i am saying
a is literally just the name for the width or height of the square
ok ok mb
eh??
i still understand what you were trying to tell me so dont worry
Okay I think i got it
sorry if i wasted ur time btw
app the help
OHHHHHHHHHHHHHHHHHHH
i went back to review what u said
and I understand it
tysm