light flare
How do I make the \blacksquare go all the way to the right on that same line in this proof? This is what I got:
%[...]
La primera integral es $|F(s)|$ y la tercera integral se resuelve, entonces:
$$0 \leq |F(s)| \leq \frac{M}{s-c}$$
para $s>c$. Entonces por el teorema de enclaustramiento
$$\lim_{s\to\infty} |F(s)| = 0\blacksquare$$
%[...]
tough lynx
La primera integral es $|F(s)|$ y la tercera integral se resuelve, entonces:
\[0 \leq |F(s)| \leq \frac{M}{s-c}\]
para $s>c$. Entonces por el teorema de enclaustramiento
\[\lim_{s\to\infty} |F(s)| = 0 \tag*{$\blacksquare$}\]
@light flare
livid badgerBOT
tough lynx
Assuming you are using amsmath and amssymb, you can use \tag
and by extension to this you must use the LaTeX style square brackets \[ and \] and not the old TeX style double dollar signs for display math.
light flare
Okay thanks
sharp oxide
also, if you're typesetting a proof, then you could also use the proof environment:
\begin{proof}
...
La primera integral es \(|F(s)|\) y la tercera integral se resuelve, entonces:
\[0 \leq |F(s)| \leq \frac{M}{s-c}\]
para \(s > c\). Entonces por el teorema de enclaustramiento
\[\lim_{s \to \infty} |F(s)| = 0 \qedhere\]
\end{proof}
lonk_from_pennsylvania
light flare
also, if you're typesetting a proof, then you could also use the proof environme...
I was aware of this, however I'd like my proofs to have my own styling
thank you anyway
also thanks a lot, I didn't know the usage of \[ \] was a must now, I kinda taught latex to myself so I kinda live under a rock