Passing a function pointer as an argument

[shrewd zealot]

i keep getting this error:

void get_guess_position(int search_min_x, int search_max_x, int search_min_y, int search_max_y, int (*is_available)(int, int), int *guess_x, int *guess_y); is the function prototype i have to use.

this is where i'm calling the function:

int (*fn_ptr)(int, int);
fn_ptr = &is_available;

void get_guess_position(west, east, south, north, is_available(*guess_x,*guess_y), guess_x, guess_y);

where is_available is defined as: int is_available(int x, int y);

[grizzled egret]

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[shrewd zealot]

side question: how do i make an asterisk display properly?

[obtuse trellis]

*like this* or *like this*

[obtuse trellis]

just do is_available

when you pass a pointer you don't reference it to pass it, nor should you call a function when passing it

;compile c void foo(void()){} void bar(){} int main(){ foo(bar); }

[warm kraken]

Compilation successful

halalaluyafail3 | 32ms | c | x86-64 gcc 15.2 | godbolt.org

[obtuse trellis]

for example

instead of foo(bar()), that's trying to pass the result of bar to foo

[shrewd zealot]

i had tried that but it didn't work either

[obtuse trellis]

what error did you get

[obtuse trellis]

or code blocks:c "like this";

[shrewd zealot]

same thing, missing ')'

[obtuse trellis]

wait, you included void in the call?

[shrewd zealot]

what do you type to get that?

[obtuse trellis]

that's the issue then

you don't write the return type when calling a function

[shrewd zealot]

yeah lol it definitely is

i theoretically know that, i just keep making copy-paste errors

ty!

[grizzled egret]

@shrewd zealot Has your question been resolved? If so, type !solved :)

[shrewd zealot]

!solved