Having trouble getting them to run separately

[zealous hemlock]

I know I am missing something that will make it so the code will run individually and not give me every answer at the same time.

[hallow geode]

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@zealous hemlock

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[zealous hemlock]

{
    double seconds, minutes, hours;

    printf("Please input whole number of seconds:\n");
    scanf("%lf", &seconds);

    hours =floor(seconds / 3600); 
    minutes =floor(fmod(seconds,3600)/60);
    seconds = fmod(seconds, 60); 
    
    if (minutes && seconds==0)
    printf("%lf hour \n", hours);
    
    if (hours && seconds>0 ) 
     printf("%lf hours %lf seconds \n", hours, seconds);
    
    if (hours && minutes>0)
    printf("%lf hours %lf minutes \n", hours, minutes);

    printf("%lf hours %lf minutes %lf seconds \n", hours, minutes, seconds);
    

    
    return 0;
}```

[deft coral]

do you know about else?

Also, minutes && seconds == 0 (and the rest of the conditions) doesn't do what you think it does; it is equivalent to minutes != 0 && seconds == 0

[fair lark]

Your code isn't nested.

    if (hours && minutes>0)
    printf("%lf hours %lf minutes \n", hours, minutes);

    printf("%lf hours %lf minutes %lf seconds \n", hours, minutes, seconds);

Will print without evaluating the conditions.

int main()
{
    double seconds, minutes, hours;

    printf("Please input whole number of seconds:\n");
    scanf("%lf", &seconds);

    hours =floor(seconds / 3600); 
    minutes =floor(fmod(seconds,3600)/60);
    seconds = fmod(seconds, 60); 
    
    if (minutes && seconds==0)
        printf("%lf hour \n", hours);
    
    if (hours && seconds>0 ) 
        printf("%lf hours %lf seconds \n", hours, seconds);
    
    if (hours && minutes>0)
        printf("%lf hours %lf minutes \n", hours, minutes);
    else
        printf("%lf hours %lf minutes %lf seconds \n", hours, minutes, seconds);
    

    
    return 0;
}

Should work.

But prefer using curly braces to avoid confusion. Like it :

if (hours && seconds > 0)
{
    printf("%lf hours %lf minutes \n", hours, minutes);
}

Mind that if (minutes && secondes==0) isn't the same as if (minutes == 0 && seconds == 0)

In C, the condition if (var) is true if var is different from 0 and false otherwise. So if (minutes && seconds == 0) means "if minutes is different from 0 and seconds is equal to 0, do ..."

[zealous hemlock]

yes, i think im supposed to use them but I couldnt get it to work while using else so i thought i could just work around it x_x

[zealous hemlock]

o I see, so it should be more like minutes !=0 && seconds!=0

[zealous hemlock]

that makes sense, ty

[hallow geode]

@zealous hemlock Has your question been resolved? If so, type !solved :)

[zealous hemlock]

Having trouble getting them to run separately

[untold schooner]

What exactly was the issue, if you remember?

[zealous hemlock]

when i run the code, lets say I input "12876 seconds" and expect output "3 hours 34 minutes 36 seconds", I will get
"3 hours
3 hours 36 seconds
3 hours 34 minutes
3 hours 34 minutes 36 seconds "

I was tyring to figure out how to just get the correct output isntead of all the possiblites

[untold schooner]

Do you know about this:

if () {
} else if () {
} else {
}

You can add as many else if as you want and check for all different possibilities. Even leave the closing else, if you don't need it anymore^^

[zealous hemlock]

yes but when i try to use else

    {
    printf("%0.lf hour \n", hours);
    }
    
    if else (hours>1)
    {
    printf("%0.lf hours \n", hours); 
    }

i get

[untold schooner]

Yeah, bc you wrote if else.

Theres is if, else if and else

Not if else

[zealous hemlock]

ah i fixed it, thank you, I will keep messing around with it!

[zealous hemlock]

!solved