Can someone make this not AI?

[flat star]

I need this rewritten as an AI detector states that the code below is mostly AI generated, this is for a university assignment. Help please!

float compute_area(float a, float b, float c, float d, float lower, float upper){
   float width = 0.01;
   float area = 0.0;
   
    for (float x = lower; x < upper; x += width){
    float y = a * x * x * x + b * x * x + c * x + d;
    area += y * width;
   
     }
     
     
     return area;
   }

[vernal shuttle]

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[zealous merlin]

lmao

[flat star]

yo?

[zealous merlin]

well did you write it with AI ?

[flat star]

assignment is hard as shit

[idle hedge]

If that code actually solves your problem, then there is a much easier solution if you know a bit about integrals.

[zealous merlin]

also

there is no such thing as an " AI detector"

at least one that is reliably correct all of the time

[idle hedge]

But I have a feeling that this isn't actually doing what it is supposed to....

[flat star]

That coding is straight off of chat gpt

whoever grades my assignemnt will likely know that

[flat star]

this is just 1 section of the full code, the code works perfectely I just need it to pass an AI detector

[idle hedge]

The code is simple. Except for changing some variable names or order of parameters, I don't see what you would want to change.

[flat star]

Alright thank you

[vernal shuttle]

@flat star Has your question been resolved? If so, type !solved :)

[flat star]

!solved