uncut tangle
pls use c++ and don’t use string or vector
I want to input a number and get its first digit and second digit.
Then subtract these two digits to form a new number and then determine the first digit and second digit of the new number. What should I do?
use while loop until the number<o?
bleak trellisBOT
dense marsh
that could work yes
uncut tangle
how?
bleak trellisBOT
HolyBlackCat
dull sedge
Can you show your attempt as code, and tell us what problems you have with it?
edgy ravine
pls use c++ and don’t use string or vector
I want to input a number and get its...
to get the first (most significant) digit, you can repeatedly divide by 10 until the result is < 10 or you could divide n by 10^number-of-digits-in-n-minus-1. The number of digits minus one can be obtained from log10 of that number, or you could just read one character at a time left to right. Give it some thought...
pale finch
pls use c++ and don’t use string or vector
I want to input a number and get its...
But... Wouldn't that just always result in you getting a 1-digit number after the very first iteration?
Because if you have e.g. 123456789 and you decide to grab first (1) and last digit (9) and you subtract them, then you get |1 - 9| = |-8| = 8 (assuming you want the absolute value).
What do you do then? Just do |8 - 8| in the next iteration because 8 was the first and last digit of the number 8?
Also why would you want to loop? Like, this is guaranteed to be 2 iterations at max.
If you're really (un-)lucky you could end up with only 1 iteration even, e.g. if your number is 4xxxxxxxxxxxx4, then you'd do |4 - 4| = 0 in the first iteration, meaning you're already finished.
Or ofc if your input number is 0 to begin with, then you're immediately finished
But I can't see any other scenario than 0, 1 or 2 iterations
dense marsh
But... Wouldn't that just always result in you getting a 1-digit number after th...
yeah
i guessed it was subtracting 8 from 123456789
idk