1
21
321
4321
54321....
I can make pyramid but couldn't Reverse print it... I only managed to do this...
1
12
123
1234
12345
P.S(I am a newbie)#1217658493977493525
#Pyramid
carmine zealot
idle crownBOT
eternal flint
Not sure I understand. Did you intend to print:
5 4 3 2 1
5 4 3 2
5 4 3
5 4
5
or perhaps
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
Where are you stuck?
carmine zealot
I intend to print
1
21
321
4321
54321....
But I am stuck on this.
1
12
123
1234
12345
eternal flint
Is there code involved that can be looked at?
vale hornet
But I am stuck on this.
1
12
123
1234
...
if you have this,
it' likely you have a loop from i=1 to i=5, at some point
just reverse it to go from i=5 to i=1 by steps of -1
carmine zealot
Is there code involved that can be looked at?
#include<stdio.h>
int main(){
for(int i=1;i<=5;i++){
for(int j=5-ij>=1;j--){
}
printf(" ");
for(int k=1;k<=i;k++){
printf("%d",k);
}
printf("\n");
}
return 0;
}
eternal flint
Maybe think about how you might iterate over the 5 rows as an outer loop and then inside that loop figure out how many spaces to print based on which row you are on and then the decending numbers starting with the row you are on. For example the first row consists of 4 spaces and then the number 1. The second row is 3 spaces and starting with the number 2 down to 1 and so forth for all rows.
vale hornet
you haven't even tried the suggestion I gave.... very sad
idle crownBOT
#include<stdio.h>
int main() {
for (int i = 1; i <= 5; i++) {
for (int j = 5 - ij >= 1; j--) {
}
printf(" ");
for (int k = 1; k <= i; k++) {
printf("%d", k);
}
printf("\n");
}
return 0;
}
Kakashibrat
Formatted by Monke
tacit surge
!code
idle crownBOT
unique thorn
The solution using just one loop.
int main()
{
const char* str = "54321";
int len = strlen(str);
for (int i = len -1 ; i >=0; --i)
{
printf("%*s\n", len, str + i);
}
}
With a string length = 5
printf("%*s\n", len , str + i) always prints 5 characters exclusive of the newline.
If the string to be printed is less than 5 characters, then it will pad out the string at the left using spaces.
For the first loop, i will be 4.
Then str + 4 will point at "1\0". That easily fits 5 chars, so this prints "....1\n" (spaces shown as dots for clarity)
For the second loop, i will be 3.
Then str + 3 will point at "21\0". That easily fits 5 chars, so this prints "...21\n".
etc.
For the last loop, i will be 0.
Then str + 0 will point at "54321\0". That just fits 5 chars, so this prints "54321\n".
I know you cannot / should not use this, because no teacher will believe that you came up with this yourself.
Besides, we're using a string literal, and that may be considered cheating too.
candid basin
The solution using just one loop.
```c
int main()
{
const char* str = "54321...
;compile ```c
// Here's some code golf (although this
// is probably confusing for beginners)
#include <stdio.h>
int main(void) {
const char str[] = "54321";
for (int i = sizeof str - 1; --i >= 0;) {
printf("%*s\n", (int)sizeof str - 1, &str[i]);
}
}
final carbonBOT
candid basin
well the compiler tried to also compile the code from the comment i replied to
;compile ```c
#include <stdio.h>
int main(void) {
const char str[] = "54321";
for (int i = sizeof str - 1; --i >= 0;) {
// the lines start with "|" because
// the compiler bot removes leading
// whitespace from the first line
printf("|%*s\n", (int)sizeof str - 1, &str[i]);
}
}
;asm -O3 ```c
#include <stdio.h>
int main(void) {
const char str[] = "54321";
for (int i = sizeof str - 1; --i >= 0;) {
printf("%*s\n", (int)sizeof str - 1, &str[i]);
}
}
;asm -O3 ```c
#include <stdio.h>
#include <string.h>
int main()
{
const char* str = "54321";
int len = strlen(str);
for (int i = len -1 ; i >=0; --i)
{
printf("%*s\n", len, str + i);
}
}
;asm -Os
final carbonBOT