proven comet
I should calculate the average value of 4 letters as floating point.
int main() {
char c1, c2, c3, c4;
printf("Bitte geben Sie vier einzelne Zeichen ein: ");
scanf("%c %c %c %c", &c1, &c2, &c3, &c4);
printf("ASCII Codes: %d %d %d %d\n", c1, c2, c3, c4);
printf("ASCII Code (Mittel,fl): %f \n", atof((const char *) c1+c2+c3+c4)/4));
return 0;
}
faint jayBOT
daring glen
what you are doing in the line atof((cont char *) c1 + c2 + c3 + c4) / 4 doesn't make sense. That line is adding c1, c2 ,c3, and c4 and using the resulting value as an address. It then interprets the values at this arbitrary address as a string an converts it to a float, then divides the result by 4. in your screenshot, I think you have more of the right idea when you do (c1 + c2 + c3 + c4) / 4, but this will yield in an int - since it seems like you want it to be a float, change this line to (c1 + c2 + c3 + c4) / 4.0. This now divides an int (specifically char) by a float which results in a float.
amber owl
what you are doing in the line `atof((cont char *) c1 + c2 + c3 + c4) / 4` does...
Actually 4.0 is of type double, so this would be a double division then.
If he specifically wants floating division then 4.0f or (float) 4 or (float) 4.0 is required, or else he will get a warning/error for a wrong format specifier (%f is for float, %lf for double).
quartz wagon
Is that true?
I always thought %f was for double and that floats would be promoted.
https://en.cppreference.com/w/c/io/fprintf seems to back this up.
Obviously %lf does the same, so should you prefer to be more explicit then more power to you.
proven comet
!solved