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#std:string giving me an error
latent spearBOT
faint snow
Gotta show relevant code
solid kiln
@modest rain what code is causing the error
modest rain
this is in the middle of a function
string password = extract_password(it, end);
if (password == "") {
return "ERR";
}
functions:
string extract_password(string::iterator &it, string::iterator end) {
string password = extract_sized_word(it, end, 8);
cout << "|" << password << "|" << endl;
if (is_valid_password(password)) {
cout << "no pass" << endl;
return "";
}
cout << "yess pass" << endl;
return password;
}
bool is_valid_password(const string &str) {
if (!(str.length() == 8 && all_of(str.begin(), str.end(), [](char c) { return ::isalnum(c); }))) {
cerr << "Invalid Password: " << str << endl;
return false;
}
return true;
}
i know that this line if (is_valid_password(password)) { i was missing a '!' char in the expression, still i cant understand what happen
solid kiln
this is in the middle of a function
```
string password = extract_password(it, e...
std::string::length_error is thrown when the string created is way too large
maybe you're providing iterators to unrelated objects which is causing this error?
also [](char c) { return ::isalnum(c); } should be [](char c) { return ::isalnum((unsigned char)c); }
modest rain
also `[](char c) { return ::isalnum(c); }` should be `[](char c) { return ::isal...
the iterators it and end are pointing to a a string that contains "LIN 103600 12345678\n"
end is str.end()
it starts at the str.begin() and goes foward in the string
it stops on \n
when i do *it it points to \n
modest rain
also `[](char c) { return ::isalnum(c); }` should be `[](char c) { return ::isal...
didn't know ty
latent spearBOT
@modest rain Has your question been resolved? If so, type !solved :)
latent spearBOT