Reverse an array using pointers

[clever wyvern]

when I've declared s=*(arr(n-1-i)) its showing an error. How do I write arr[n-1-i] in the form of a pointer

[spiral lance]

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@clever wyvern

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[clever wyvern]

where n is the size of the array

[random halo]

I would use pointer arithmetic in the loop, but I am weird.

[clever wyvern]

but why is it showing its wrong in this way ??

i declared it as a pointer

[random halo]

Hang on, you have a double pointer as a parameter there.

[crisp haven]

Missing a +.

[clever wyvern]

omggg yeahh

right

thank you

and moreover it would be call by reference right if i dont use pointers also ??

[crisp haven]

Call function.

[clever wyvern]

sorry typo

[crisp haven]

Not sure what you mean by that.

[clever wyvern]

pointer in functions are of two types

call by vale

and

call by reference

[crisp haven]

No they aren't.

There is no such distinction.

[clever wyvern]

here we pass address of variable as argument

[clever wyvern]

oh

i saw that in one of a tutorial

thats why asked

[spiral lance]

@clever wyvern Has your question been resolved? If so, type !solved :)

[crisp haven]

That tutorial is wrong then.

[clever wyvern]

👍🏻🗿

!solved