#How to get a random enum class value?

28 messages · Page 1 of 1 (latest)

muted fernBOT
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honest seal
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Each enum value is really an integer.

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Orange is 0 and so on.

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I'm talking about enum class.

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enum class is just a safer and more featured version of enum.

dense cypress
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believe you might want return static_cast<T>(index);

hazy goblet
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@dense cypress I'm getting the same issue. It seems to be not liking T::_COUNT

dense cypress
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oh, also update to int index = next(0, static_cast<int>(T::_COUNT) - 1);

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tell me how that goes

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if the compiler generates a warning or an error, tell me what it is

hazy goblet
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That worked... nice!

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Oh I see why. I mean, it has to cast _COUNT.

dense cypress
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np! I think the problem was the implicit conversion from int to the enumeration type

hazy goblet
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Yeah.

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_COUNT is still a member of the enum class, so makes sense to cast it as well.

dense cypress
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yup yup yup

hazy goblet
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Thanks!

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!solved

muted fernBOT
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late yew
# hazy goblet That worked... nice!

int to enum class doesn't get converted implicitly, that's exactly why enum class was introduced, but it still can be converted explicitly by a C-style cast, or by static_cast, they are equivalent here

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(int)(T::_COUNT)

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because writing static_cast and sending your code to friends who don't know what a static_cast is will make them feel
ExIsTeNtIaL AnXiEtY

late yew
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C-style casts are used in intro to C++ classes where they teach students how to convert from double to int with casting, it won't cause anxiety

late yew
honest seal
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That static_cast causes an uneasy feeling is an intentional design, it makes you think twice before using and it stands out to be found.

ivory musk
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_COUNT is not a permissible name for an enumerator because all names starting with _A, _B, _C etc. are reserved

hot moss