isn't this example UB? std::string is not an implicit lifetime type I reckon:
#include <cstdlib>
#include <iostream>
#include <memory>
#include <string>
int main()
{
const char *v[] = {"This", "is", "an", "example"};
auto sz = std::size(v);
if (void *pbuf = std::aligned_alloc(alignof(std::string), sizeof(std::string) * sz))
{
try
{
auto first = static_cast<std::string*>(pbuf);
auto last = std::uninitialized_copy(std::begin(v), std::end(v), first);
for (auto it = first; it != last; ++it)
std::cout << *it << '_';
std::cout << '\n';
std::destroy(first, last);
}
catch (...) {}
std::free(pbuf);
}
}
from https://en.cppreference.com/w/cpp/memory/uninitialized_copy