ripe girder
int array[]={1,2,3,4,5,6};
int occurrence=-1;
int key=4;
for(int i=0;i<6;i++){
if(array[i]=key){
occurrence=i;
}
}
cout<<occurrence;
In this code above,if I use assignment operator instead of "==" in the fifth line there doesn't come any error but it's printing something else i.e 5 what it's representing here??what does that assignment operator signify here
turbid merlinBOT
reef smelt
it just assigns right hand side to the left hand side
question is what happens after that value, and so after assignment you are left with the value, which gets implicitly converted to boolean
in this case 0 means false and anything else true
so the check is gonna happen 5 times, and every time you will assign key to array[i]
and you probably want to have occurance+=i;
because now it's just going to save the last i, without actually keeping number of occurances
outer garnet
you can think of using the assigment as two seperate statements ```cpp
array[i]=key;
if(array[i]){
occurrence=i;
}
sand zinc
Assignments have a return value. The reason is that you can do a = b = c = 5;. c = 5 is evaluated to 5 which is then assigned to b and so on. Here if (array[i] = key) is evaluated to if (4) and numbers other than 0 are evaluated as true.
ripe girder
U r telling (6=5=4=3=2=1=key) means first array[0] returns value 4(key) which is then assigned to array[1] i.e 2 nd so on till i=5 i.e last i which it is giving us as result...are u telling the same thing or I am going in wrong direction??
sand zinc
Can't do this. It would try to evaluate 1=key and then notice you cannot assign to 1.
(you could make it compile by overloading operators, but that's really not what you want)
ripe girder
Assignments have a return value. The reason is that you can do `a = b = c = 5;`....
Ok then I am not understanding how this implicitly converted to boolean
sand zinc
There are 2 parts to it.
The first part is the return value of an assignment. a = 5 evaluates to 5 so that when you do b = a = 5 b also becomes 5.
The second part is that numbers other than 0 are evaluated as true, so if (5) is the same as if (true).
ripe girder
Ok can u explain me in the context of my question how it works here
sand zinc
if(array[i]=key) evaluates to if(array[i]=4) which evaluates to if(4) which evaluates to if(true).
ripe girder
Sorry I am a beginner I don't understand completely. Could u give me an example where 0 is also included and what will be the compiler's result there so that I will be more able to understand the logic here
sand zinc
int key = 0;
int value = 42;
if (value = key) {
std::cout << "This will not print\n";
}
if (value = key) is evaluated to if (value = 0) which assigns 0 to value and then evaluates if (0) which evaluates to if (false).
ripe girder
Ok means in my question everytime it's going to be true that's why it's printing the last i traversing through the loop
ripe girder
!solved