How to create a function that can take any number of arguments to be used by cout?

[hollow sapphire]

If you didn't understand the question what i mean is i want to create a function that takes any number of arguments and i want to pass those arguments into cout so that i can print any number of arguments.

Expected Output:

Utils::Log("Hello world", SomefunctionOutput(), 2, 2+2, "Hi");

This is the result i want to achieve. Is there a way? Any help is greatly appreciated!

[covert kettle]

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[hearty python]

https://en.cppreference.com/w/cpp/language/parameter_pack

For a printing function you probably want to take by const & instead of by value.

[dawn crown]

you need to use variadic template

[dawn crown]

an example:

void Log()
{
    
}

 template<typename T1, typename... T2>
void Log(const T1& value, const T2&... args)
{
    std::cout << value << '\n';
    Log(args...);
}

int main()
{
    Log("Hello", 3, 2.0f, true);
}```

[sterile brook]

https://learn.microsoft.com/en-us/cpp/cpp/ellipses-and-variadic-templates?view=msvc-170#example

[abstract ingot]

Worth noting that from C++17 you can express that example more easily using fold expressions:

template <typename... Args>
void Log(const Args&... args) {
  (..., std::cout << args << ' ');
  std::cout << '\n';
}
``` for a (slightly different) example

[covert kettle]

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