Need help with making a number spread pattern

[crude sierra]

The program ask the user to input 1 to 9 continuously as N value and print the nested loop number pattern like the picture.
I think it for a long time but still can’t find the way to make it. How can i do it? Thank you

[alpine widget]

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[torn cloud]

Hi.

This is a piece of cake.

💪

[torn cloud]

#include <stdio.h>

void display_number_spread_pattern(int n){
int row, col, i, k, m;
for(row = 0; row < n * 2 - 1; row++){
k = row < n ? 1 : -1;
col = (n * 2 - 2) * (row / n) + row * k;
if(row == n - 1){
for(i = 0; i < n * 2 - 1; i++) printf("1");
}
else{
for(i = 0; i <= col; i++) printf("%d", n - col);
m = n - col - 1;
for(i = 0; i < m * 2 - 1; i++){
k = i < m ? 1 : -1;
printf("%d", m - ((m * 2 - 2) * (i / m) + i * k));
}
for(i = 0; i <= col; i++) printf("%d", n - col);
}
puts("");
}
}

int main(){
int n;
scanf("%d", &n);
display_number_spread_pattern(n);
puts("");
return 0;
}

Please DM when you see this result.

[crude sierra]

Omg

[torn cloud]

Hi.

[pliant hinge]

think of it line by line

the first line starts with 3 and goes down to 1 then back to 3

the next line does the same with 2, except this is 2 characters shorter so you pad the remaining spaces with 2

[alpine widget]

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