2d array problem

[gleaming sage]

I want to use char x[N][N]= all N*N terms = 'X'
how can I do this
thank you

[last prawn]

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[gleaming sage]

I can only use for loop to fill in the item?

[west notch]

memset(array, 'X', sizeof(array));
Or

    for (int i = 0; i < N; ++i) {
        for (int j = 0; j < N; ++j) {
            a[i][j] = 'X';
        }
    }

[cerulean stirrup]

(we try to not just give the solution)

but yes - loop, memset, or some std:: options

[gleaming sage]

I understand your stand
I am trying to ask question that is not exactly the same as my homework
and ask the method only

[cerulean stirrup]

great 🙂

[gleaming sage]

I want to do let the C++ know
a is same as A
my previous method is

char x;
cin>> x
if (x=='a' or x=='A') return true

do you have smarter method
I design to do this by using the table
by char x+32

then I dont need to do if (x=='a' or x=='A') until if (x=='z' or x=='Z')

however
can I do something like this?

[cerulean stirrup]

@gleaming sage x=='a' or x=='A' is perfectly fine. You could to tolower(x) == 'a' if you want, but really either are fine.

[cerulean stirrup]

you can access a char from the string with x[some index]

[last prawn]

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