TJ-Bot
I know that a class can't extend from 2 or more classes due to a diamond problem (same method signature in both superclasses).
But when a class implements 2 or more interfaces that both have the same implemented (default) method signatures, you get a comp
erfaces and those interfaces have the same method signature, there is no diamond problem because interfaces only provide method declarations, not implementations.
In the case of conflicting method signatures in multiple interfaces, the implementing class has to provide its own implementation of the method. This allows Java to avoid ambiguity and the diamond problem that occurs with multiple inheritance in classes.
If a class implements two interfaces with conflicting method signatures, it must provide its own implementation for both methods. This means that there is no conflict or ambiguity in the implementation of methods from multiple interfaces.
Overall, while classes cannot extend from multiple classes due to the diamond problem, they can implement multiple interfaces without running into conflicts as long as they provide their own implementations for any conflicting methods. This allows for flexibility and modularity in Java programming without the issues that can arise from multiple inheritance.