#Spring Entry Point URL Detection

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craggy lanternBOT
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@sly nest has a question:

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Hello, in spring, how i can know where is the entry point before the rest controller, i mean the url

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<@&987246399047479336> please have a look, thanks.

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TJ-Bot
Hello, in spring, how i can know where is the entry point before the rest controller, i mean the url

Spring provides a way to detect and handle the entry point URL before reaching the controller using a filter. You can create a custom filter by implementing the javax.servlet.Filter interface and registering it in your Spring configuration.

Here's an example of how you can create a custom filter to intercept incoming requests and log the entry point URL:

import org.springframework.web.filter.OncePerRequestFilter;
import javax.servlet.FilterChain;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

public class EntryPointFilter extends OncePerRequestFilter {

    @Override
    protected void doFilterInternal(HttpServletRequest request, HttpServletResponse response, FilterChain filterChain)
            throws ServletException, IOException {
        String entryPoint = request.getRequestURI();
        System.out.println("Entry Point URL: " + entryPoint);
        
        // Continue with the filter chain
        filterChain.doFilter(request, response);
    }
}

Then, you can register this filter in your Spring configuration class like this:

@Configuration
public class AppConfig extends WebMvcConfigurerAdapter {

    @Override
    public void addInterceptors(InterceptorRegistry registry) {
        registry.addInterceptor(new EntryPointFilter());
    }
}

By registering this custom filter in your Spring configuration, you can intercept incoming requests and log the entry point URL before it reaches the controller.

echo ruin
craggy lanternBOT
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Changed the category to Spring.

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<@&1004656351647117403> please have a look, thanks.

echo ruin
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if you're using spring-boot, the default url is

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http://localhost:8080